Math for Liberal Studies.  We have seen many methods, all of them flawed in some way  Which method should we use?  Maybe we shouldn’t use any of them,

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Presentation transcript:

Math for Liberal Studies

 We have seen many methods, all of them flawed in some way  Which method should we use?  Maybe we shouldn’t use any of them, and keep searching for a better way

 In 1951, Kenneth Arrow proved that this search will be in vain  There is no voting system that satisfies all of the following conditions:  always gives a winner (except for ties)  is not a dictatorship  independence of irrelevant alternatives  Pareto condition  voters rank their candidates in order

 May’s theorem told us that with 2 candidates, there is only one system that satisfies certain “fairness” conditions  Arrow’s theorem tells us that with more than 2 candidates, there is no system that satisfies certain “fairness” conditions

 Arrow proves we can’t have all of these:  always gives a winner (except for ties)  is not a dictatorship  independence of irrelevant alternatives  Pareto condition  voters rank their candidates in order  What should we give up?

 Do we want to use a voting system that doesn’t always give a winner?  An example of this is Condorcet’s method

 If we allow our voting system to be a dictatorship, that means that there is a single voter that determines the outcome for everyone  That hardly seems “fair”

 This is the “spoiler effect” we studied earlier  Many of the common voting systems (plurality, rank methods) suffer from this problem

 Remember that the Pareto condition says that if every single voter prefers A over B, then B shouldn’t win  That seems like something we should have, though we could use sequential pairwise voting if we give this up

 Every system that we have studied has used ranked preferences  Is there another way for voters to express their preferences?

 We will look at 4 types of ballots  Single-vote: Voters choose a single candidate  Rank: Voters rank candidates from best to worst  Approval: Voters can choose multiple candidates to cast votes for  Range: Voters rate each candidate on a scale

 This is the ballot most of us are familiar with  Many of the methods we have studied (Condorcet, rank, runoff, etc.) are impossible with this ballot type

 This is the kind of ballot we would need to use the methods we have studied  Every candidate must be ranked, and ties are not allowed

 This generalizes the single-vote ballot  Allows voters to vote for minor party candidates and major party candidates at the same time

 Similar to a rank ballot, but voters assign each candidate a score  In this example, the scale is 1 to 5, but the scale could be anything, as long as it is the same for each voter

 We already know how to use the first two types of ballots to decide the winner of an election  Now we will look at how to use these two new ballot types to decide a winner

 Add up all the votes each candidate gets  The candidate with the most votes wins

 The results of an approval vote are shown here  For example, 6 people approved of both E and F Number of Ballots Results EFGH 6XX 5X 5X 4XXX 2X 1X

 E got 6+4+1=11 votes  F got 6+5+4=15 votes  G got 5 votes  H got 4+2=6 votes  F wins! Number of Ballots Results EFGH 6XX 5X 5X 4XXX 2X 1X

 We can assume that voters are still using (mental) preference lists, but simply have a “cutoff” above which they approve of a candidate and below which they do not  Suppose we have a voter with preference order B > D > A > C

 This voter could cast his approval ballot in 5 ways:  Approve of no one  Approve of B only  Approve of B and D  Approve of B, D, and A  Approve of everyone

 Now consider this profile, with approval cutoffs as shown  The approval results are:  A has 4 votes  B has 7 votes  C has 2 votes

 So B is the approval winner  However, since we have preferences we can use other methods as well  In fact, A is the Condorcet winner!

 The previous example showed us that approval voting doesn’t satisfy the Condorcet winner criterion  There is another problem that we’ll see in the next example

 In this profile, the approval results are:  A gets 6 votes  B gets 9 votes  C gets 11 votes  So C wins the approval vote

 However, if we look at the plurality results:  A gets 6 votes  B gets 3 votes  C gets 2 votes  A is the plurality winner (with a majority!) but comes in last using approval voting

 Add up all the points each candidate gets  The candidate with the most points wins

 The results of an approval vote are shown here  For example, 8 people rated E with 5 points, F with 4 points, G with 3 points, and H with 1 point Number of Ballots Results EFGH

 We compute the winner just like we did for rank voting, but this time there isn’t one point system that all the voters are using Number of Ballots Results EFGH

Number of Ballots Results EFGH E is the winner with 81 points!

 We can think of approval voting as being a special kind of range voting  In approval voting, the scale is only 0 or 1  0 means “I don’t approve”  1 means “I approve”

 Since we saw earlier that approval voting has problems, and approval voting is just a special kind of range voting, range voting has those same problems

 Even with its problems, range voting satisfies four of the five conditions of Arrow’s theorem:  always gives a winner (except for ties)  is not a dictatorship  independence of irrelevant alternatives  Pareto condition  voters rank their candidates in order