Tom, Dick, Harry and the Gorilla An Investigation.

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Presentation transcript:

Tom, Dick, Harry and the Gorilla An Investigation

Tom, Dick, Harry and the Gorilla On a table is a bag of nuts. Standing round the table are three boys Tom, Dick and Harry and a gorilla called Hilda. The nuts are to be shared between them. Tom takes the bag of nuts. He gives one to the Gorilla and takes half of what is left for himself, and then passes the bag onto Dick. Dick opens the bag and takes half the nuts for himself before passing one to the Gorilla. He then passes the bag to Harry.

Tom, Dick, Harry and the Gorilla Harry eats one of the nuts when he gets the bag and then shares the rest equally with the Gorilla. If the Gorilla got 17 nuts in total, how many nuts were originally in the bag?

Solution:- Tom, Dick, Harry and the Gorilla Let x be the number of nuts in the bag originally. Tom gets ½(x-1) of the nuts. Dick gets ¼(x-1). Harry gets and Hilda gets Solving the equation, gives x = 129 nuts in the bag. Therefore Tom = 64 nuts Dick = 32 nuts Harry= 16 nuts Hilda = 17 nuts