Matched Filtering and Digital Pulse Amplitude Modulation (PAM)

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Presentation transcript:

Matched Filtering and Digital Pulse Amplitude Modulation (PAM)

Outline Part I Part II Transmitting one bit at a time Matched filtering PAM system Intersymbol interference Communication performance Bit error probability for binary signals Symbol error probability for M-ary (multilevel) signals Eye diagram Part I Part II

Additive Noise Channel Transmitting One Bit Transmission on communication channels is analog One way to transmit digital information is called 2-level digital pulse amplitude modulation (PAM) receive ‘0’ bit Tb -A t Tb -A ‘0’ bit t Additive Noise Channel input output x(t) y(t) receive‘1’ bit Tb t A Tb t A ‘1’ bit How does the receiver decide which bit was sent?

Model channel as LTI system with impulse response c(t) Transmitting One Bit Two-level digital pulse amplitude modulation over channel that has memory but does not add noise -A Th receive ‘0’ bit t Th+Tb Th Tb -A ‘0’ bit LTI Channel input output x(t) y(t) t t receive‘1’ bit Th+Tb Th A Th Tb t A ‘1’ bit Model channel as LTI system with impulse response c(t) 1 Th t Assume that Th < Tb

Transmitting Two Bits (Interference) Transmitting two bits (pulses) back-to-back will cause overlap (interference) at the receiver Sample y(t) at Tb, 2 Tb, …, and threshold with threshold of zero How do we prevent intersymbol interference (ISI) at the receiver? Th t 1 * = A Th+Tb 2Tb Tb Tb t t -A Th Assume that Th < Tb ‘1’ bit ‘0’ bit ‘1’ bit ‘0’ bit Intersymbol interference

Preventing ISI at Receiver Option #1: wait Th seconds between pulses in transmitter (called guard period or guard interval) Disadvantages? Option #2: use channel equalizer in receiver FIR filter designed via training sequences sent by transmitter Design goal: cascade of channel memory and channel equalizer should give all-pass frequency response t -A Th Tb ‘1’ bit ‘0’ bit Th+Tb * = A 1 Th+Tb Tb Th t t Th Assume that Th < Tb ‘1’ bit ‘0’ bit

Digital 2-level PAM System ak{-A,A} s(t) x(t) y(t) y(ti) Transmitted signal Requires synchronization of clocks between transmitter and receiver bi 1 Decision Maker PAM g(t) c(t) h(t) bits Sample at t=iTb bits pulse shaper w(t) matched filter Clock Tb Threshold l AWGN Clock Tb N(0, N0/2) Transmitter Channel Receiver p0 is the probability bit ‘0’ sent

Additive white Gaussian noise (AWGN) with zero mean and variance N0 /2 Matched Filter Detection of pulse in presence of additive noise Receiver knows what pulse shape it is looking for Channel memory ignored (assumed compensated by other means, e.g. channel equalizer in receiver) g(t) Pulse signal w(t) x(t) h(t) y(t) t = T y(T) Matched filter T is the symbol period Additive white Gaussian noise (AWGN) with zero mean and variance N0 /2

Matched Filter Derivation Design of matched filter Maximize signal power i.e. power of at t = T Minimize noise i.e. power of Combine design criteria T is the symbol period g(t) Pulse signal w(t) x(t) h(t) y(t) t = T y(T) Matched filter

Power Spectra Deterministic signal x(t) w/ Fourier transform X(f) Power spectrum is square of absolute value of magnitude response (phase is ignored) Multiplication in Fourier domain is convolution in time domain Conjugation in Fourier domain is reversal & conjugation in time Autocorrelation of x(t) Maximum value (when it exists) is at Rx(0) Rx(t) is even symmetric, i.e. Rx(t) = Rx(-t) t 1 x(t) Ts t Rx(t) -Ts Ts

Power Spectra Two-sided random signal n(t) Fourier transform may not exist, but power spectrum exists For zero-mean Gaussian random process n(t) with variance s2 Estimate noise power spectrum in Matlab approximate noise floor N = 16384; % finite no. of samples gaussianNoise = randn(N,1); plot( abs(fft(gaussianNoise)) .^ 2 );

Matched Filter Derivation Noise power spectrum SW(f) g(t) Pulse signal w(t) x(t) h(t) y(t) t = T y(T) Matched filter Noise Signal f AWGN Matched filter T is the symbol period

Matched Filter Derivation Find h(t) that maximizes pulse peak SNR h Schwartz’s inequality For vectors: For functions: upper bound reached iff a  b

Matched Filter Derivation T is the symbol period

Matched Filter Impulse response is hopt(t) = k g*(T - t) Symbol period T, transmitter pulse shape g(t) and gain k Scaled, conjugated, time-reversed, and shifted version of g(t) Duration and shape determined by pulse shape g(t) Maximizes peak pulse SNR Does not depend on pulse shape g(t) Proportional to signal energy (energy per bit) Eb Inversely proportional to power spectral density of noise

Matched Filter for Rectangular Pulse Matched filter for causal rectangular pulse shape Impulse response is causal rectangular pulse of same duration Convolve input with rectangular pulse of duration T sec and sample result at T sec is same as First, integrate for T sec Second, sample at symbol period T sec Third, reset integration for next time period Integrate and dump circuit Sample and dump T t=nT h(t) = ___

Digital 2-level PAM System ak{-A,A} s(t) x(t) y(t) y(ti) Transmitted signal Requires synchronization of clocks between transmitter and receiver bi 1 Decision Maker PAM g(t) c(t) h(t) bits Sample at t=iTb bits pulse shaper w(t) matched filter Clock Tb Threshold l AWGN Clock Tb N(0, N0/2) Transmitter Channel Receiver p0 is the probability bit ‘0’ sent

Digital 2-level PAM System Why is g(t) a pulse and not an impulse? Otherwise, s(t) would require infinite bandwidth We limit its bandwidth by using a pulse shaping filter Neglecting noise, would like y(t) = g(t) * c(t) * h(t) to be a pulse, i.e. y(t) = m p(t) , to eliminate ISI p(t) is centered at origin actual value (note that ti = i Tb) intersymbol interference (ISI) noise

Eliminating ISI in PAM One choice for P(f) is a rectangular pulse W is the bandwidth of the system Inverse Fourier transform of a rectangular pulse is is a sinc function This is called the Ideal Nyquist Channel It is not realizable because pulse shape is not causal and is infinite in duration

Eliminating ISI in PAM Another choice for P(f) is a raised cosine spectrum Roll-off factor gives bandwidth in excess of bandwidth W for ideal Nyquist channel Raised cosine pulse has zero ISI when sampled correctly Let g(t) and h(t) be square root raised cosine pulses ideal Nyquist channel impulse response dampening adjusted by rolloff factor a

Bit Error Probability for 2-PAM Tb is bit period (bit rate is fb = 1/Tb) w(t) is AWGN with zero mean and variance 2 Lowpass filtering a Gaussian random process produces another Gaussian random process Mean scaled by H(0) Variance scaled by twice lowpass filter’s bandwidth Matched filter’s bandwidth is ½ fb h(t) s(t) Sample at t = nTb Matched filter w(t) r(t) rn r(t) = h(t) * r(t)

Bit Error Probability for 2-PAM Noise power at matched filter output Filtered noise T = Tsym Noise power s2 d(t1–t2)

Bit Error Probability for 2-PAM Symbol amplitudes of +A and -A Rectangular pulse shape with amplitude 1 Bit duration (Tb) of 1 second Matched filtering with gain of one (see slide 14-15) Integrate received signal over nth bit period and sample - Probability density function (PDF)

Bit Error Probability for 2-PAM Probability of error given that transmitted pulse has amplitude –A Random variable is Gaussian with zero mean and variance of one Tb = 1 PDF for N(0, 1) Q function on next slide

Q Function Q function Complementary error function erfc Relationship Erfc[x] in Mathematica erfc(x) in Matlab

Bit Error Probability for 2-PAM Probability of error given that transmitted pulse has amplitude A Assume that 0 and 1 are equally likely bits Probability of error exponentially decreases with SNR (see slide 8-16) Tb = 1

PAM Symbol Error Probability Set symbol time (Tsym) to 1 second Average transmitted signal power GT(w) square root raised cosine spectrum M-level PAM symbol amplitudes With each symbol equally likely 3 d d d -d d 3 d 2-PAM 4-PAM Constellation points with receiver decision boundaries

PAM Symbol Error Probability Noise power and SNR Assume ideal channel, i.e. one without ISI Consider M-2 inner levels in constellation Error only if where Probability of error is Consider two outer levels in constellation two-sided power spectral density of AWGN channel noise after matched filtering and sampling

PAM Symbol Error Probability Assuming that each symbol is equally likely, symbol error probability for M-level PAM Symbol error probability in terms of SNR M-2 interior points 2 exterior points

Visualizing ISI Eye diagram is empirical measure of signal quality Intersymbol interference (ISI): Raised cosine filter has zero ISI when correctly sampled

Eye Diagram for 2-PAM Useful for PAM transmitter and receiver analysis and troubleshooting The more open the eye, the better the reception Sampling instant M=2 Margin over noise Distortion over zero crossing Slope indicates sensitivity to timing error Interval over which it can be sampled t - Tsym t t + Tsym

Eye Diagram for 4-PAM Due to startup transients. 3d Fix is to discard first few symbols equal to number of symbol periods in pulse shape.