InvestmentWorth Investment Worth. Investment Worth MARR Suppose a company can earn 12% / annum in U. S. Treasury bills No way would they ever invest in.

Slides:



Advertisements
Similar presentations
Applications of Money-Time Relationships
Advertisements

Copyright Oxford University Press 2009 Chapter 8 Choosing the Best Alternative.
1 Dr. Lotfi K.GAAFAR Eng. Ahmed Salah RIFKY ENGR 345 Engineering Economy.
Chapter IV Examples.
TM 661 Engineering Economics for Managers
Chapter 7 - Rate of Return Analysis Click here for Streaming Audio To Accompany Presentation (optional) Click here for Streaming Audio To Accompany Presentation.
InvestmentWorth Investment Worth. Given a minimum attractive rate-of-return, be able to evaluate the investment worth of a project using Net Present Worth.
Internal Rate of Return (Multiple Rates of Return Problem) ECON 320 Engineering Economics Mahmut Ali GOKCE Industrial Systems Engineering.
Multiple Investment Alternatives Sensitivity Analysis.
8/25/04 Valerie Tardiff and Paul Jensen Operations Research Models and Methods Copyright All rights reserved Economic Decision Making Decisions.
Flash back before we compare mutually exclusive alternatives.
Dealing With Uncertainty
Present Worth Analysis Lecture No.15 Professor C. S. Park Fundamentals of Engineering Economics Copyright © 2005.
Engineering Economy IEN255 Chapter 4 - Present Worth Analysis  Do the product or not?  3 main issues  How much additional investment in plant & equipment.
CTC 475 Review Matching period and interest interval Matching period and interest interval Continuous Compounding Continuous Compounding Continuous Flow.
Internal Rate of Return (Multiple Rates of Return Problem) Lecture No. 20 Professor C. S. Park Fundamentals of Engineering Economics Copyright © 2005.
(c) 2001 Contemporary Engineering Economics 1 Chapter 7 Present Worth Analysis Describing Project Cash Flows Initial Project Screening Method Present Worth.
Contemporary Engineering Economics, 4 th edition, © 2007 Comparing Mutually Exclusive Alternatives Lecture No.18 Chapter 5 Contemporary Engineering Economics.
Applications of Money- Time Relationships MARR by PW Method r r All cash inflows and outflows are discounted to the present point in time at an interest.
EPT 221 Engineering Design Introduction to Engineering Economics.
Intro to Engineering Economy
Engineering Economics Contemporary Engineering Economics, 5 th edition, © 2010.
1 Reviewing… Net Present Worth: Used to select among alternative projects. Used to compare mutually exclusive alternatives. If all expenses and revenues.
ENGM 661 Engineering Economics Replacement Analysis.
Engineering Economics
Comparing Projects Using Time Value of Money
Inflation November 8, Inflation can be defined as the rate of decline in the purchasing power of money. Purchasing power might be defined as: a)
Annual Worth Analysis An alternative to Present Worth (PW) and Future Worth (FW) analysis is Annual Worth (AW) analysis. Annual worth analysis will select.
Analysis of Engineering Business Decisions
EGR Rate of Return Analysis Rate of Return (ROR) is the rate paid on the unpaid balance of borrowed money, or the rate earned on the unrecovered.
ENGINEERING ECONOMICS ISE460 SESSION 13 Annual Equivalent, June 17, 2015 Geza P. Bottlik Page 1 OUTLINE Questions? News? Annual Equivalent Examples.
Evaluating a Single Project
L15: Present Worth Analysis ECON 320 Engineering Economics Mahmut Ali GOKCE Industrial Systems Engineering Computer Sciences.
MIE Class #5 Manufacturing & Engineering Economics Concerns and Questions Concerns and Questions Quick Recap of Previous ClassQuick Recap of Previous.
1 Word Problems Organize the Data Given: Determine the objective and your strategy. Draw the Cash Flow Diagram. Write Equations and Solve. Reflect Back.
Annual Worth Analysis An alternative to Present Worth (PW) and Future Worth (FW) analysis is Annual Worth (AW) analysis. Annual worth analysis will select.
TM 661 M2 - Probs II. Consider a simple five year investment project with discrete end-of-year cash flows shown below. Revenue at the end of year one.
TM 661 Chapter 6 Solutions 1 The manager of a canned-food processing plant is trying to decide between two labeling machines. Their respective costs.
Project cash flow n A B Example 1: Consider the following two mutually exclusive investment projects. Assume.
Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display. CHAPTER V PRESENT WORTH ANALYSIS McMc Graw Hill ENGINEERING.
1 1. Order alternatives from lowest to highest initial investment. 2. Let Alternative A 0 (do nothing) be considered the current best. 3. Consider next.
TM 661 Engineering Economics for Managers Break Even & Sensitivity.
Lecture No.18 Chapter 5 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5 th edition, © 2010.
ENGM 661 Engineering Economics for Managers InvestmentWorth Investment Worth.
EGR Break-Even Analysis Break-even Analysis – performed to determine the value of a variable that makes two elements equal. In economic terms:
Chapter 5 Present-Worth Analysis. 2 Loan versus Project Cash Flows Initial Project Screening Methods Present-Worth Analysis Methods to Compare Mutually.
L16: Comparing Mutually Exclusive Alternatives ECON 320 Engineering Economics Mahmut Ali GOKCE Industrial Systems Engineering Computer.
Contemporary Engineering Economics, 6 th edition Park Copyright © 2016 by Pearson Education, Inc. All Rights Reserved Comparing Mutually Exclusive Alternatives.
Chapter 6 Annual Equivalent Worth Criterion. Chapter 6 Annual Equivalence Analysis  Annual equivalent criterion  Applying annual worth analysis  Mutually.
Replacement Analysis and Economic Life Should we replace an asset that we own now or later?
Chapter 5: Evaluating a Single Project
APPLICATIONS OF MONEY-TIME RELATIONSHIPS
Lecture slides to accompany
Chapter 5: Evaluating a Single Project
Rate of Return Analysis
TM 661 Chapter 5 Solutions 1 5.4) Consider the net cash flows and salvage values for each of alternatives 1 and 2 having lives 3 and 5 years respectively.
Chapter 5: Evaluating a Single Project
Annual Worth Analysis An alternative to Present Worth (PW) and Future Worth (FW) analysis is Annual Worth (AW) analysis. Annual worth analysis will select.
Chapter 7 Present Worth Analysis
Example Problem A company is considering the purchase of a new piece of testing equipment that is expected to produce $8,000 additional income during the.
Lecture slides to accompany
RATE OF RETURN ANALYSIS CHAPTER 7
Engineering Economic Analysis
Lecture slides to accompany
Alt Comparison by AW Not necessary to use LCM for different life alternatives Example: A company is considering two machines for a certain operation. Machine.
Lecture slides to accompany
Steps of the Incr. Analysis Process
Annual Worth Analysis An alternative to Present Worth (PW) and Future Worth (FW) analysis is Annual Worth (AW) analysis. Annual worth analysis will select.
Example Problem A company is considering the purchase of a new piece of testing equipment that is expected to produce $8,000 additional income during the.
Chapter 5: Evaluating a Single Project
Presentation transcript:

InvestmentWorth Investment Worth

Investment Worth MARR Suppose a company can earn 12% / annum in U. S. Treasury bills No way would they ever invest in a project earning < 12% Def: The Investment Worth of all projects are measured at the Minimum Attractive Rate of Return (MARR) of a company.

MARR MARR is company specific u utilities - MARR = % u mutuals - MARR = % u new venture - MARR = % MARR based on u firms cost of capital u Price Index u Treasury bills

Investment Worth Alternatives u NPW( MARR ) > 0Good Investment

Investment Worth Alternatives u NPW( MARR ) > 0Good Investment u EUAW( MARR ) > 0Good Investment

Investment Worth Alternatives u NPW( MARR ) > 0Good Investment u EUAW( MARR ) > 0Good Investment u IRR > MARRGood Investment

Present Worth Example: Suppose you buy and sell a piece of equipment. Purchase Price $16,000 Sell Price (5 years) $ 4,000 Annual Maintenance $ 3,000 Net Profit Contribution $ 6,000 MARR 12% Is it worth it to the company to buy the machine?

Present Worth 16,000 6,000 3, ,000 NPW= (P/A,12,5) + 4(P/F,12,5) 16,000 3, ,000

Present Worth 16,000 6,000 3, ,000 NPW= (P/A,12,5) + 4(P/F,12,5) = (3.6048) + 4(.5674) 16,000 3, ,000

Present Worth 16,000 6,000 3, ,000 NPW= (P/A,12,5) + 4(P/F,12,5) = (3.6048) + 4(.5674) = = -$2,916 16,000 3, ,000

Annual Worth Annual Worth (AW or EUAW) AW(i) = PW(i) (A/P, i%, n) = [ A t (P/F, i%, t)](A/P, i%, n) AW(i) = Annual Worth of Investment AW(i) > 0 **OK Investment** 

Annual Worth; Example Repeating our PW example, we have AW(12)= -16(A/P,12,5) (A/F,12,5) 3, ,000 16,000

Annual Worth; Example Repeating our PW example, we have AW(12)= -16(A/P,12,5) (A/F,12,5) = -16(.2774) (.1574) 3, ,000 16,000

Annual Worth; Example Repeating our PW example, we have AW(12)= -16(A/P,12,5) (A/F,12,5) = -16(.2774) (.1574) = = -$808 3, ,000 16,000

Alternately AW(12) = PW(12) (A/P, 12%, 5) = (.2774) = - $810 < 0 NO GOOD 3, ,000 16,000

Internal Rate of Return Internal Rate-of-Return IRR - internal rate of return is that return for which NPW(i*) = 0 i* = IRR i* > MARR **OK Investment**

Internal Rate of Return Internal Rate-of-Return IRR - internal rate of return is that return for which NPW(i*) = 0 i* = IRR i* > MARR **OK Investment** Alt: PW revenue (i*) = PW costs (i*)

Internal Rate of Return Example PW(i) = (P/A, i, 5) + 4(P/F, i, 5) 3, ,000 16,000

Internal Rate of Return Example PW(i) = (P/A, i, 5) + 4(P/F, i, 5) 3, ,000 16,000

Internal Rate of Return Example PW(i) = (P/A, i, 5) + 4(P/F, i, 5) i* = 5 1 / 4 % i* < MARR 3, ,000 16,000

Summary u NPW > 0 Good Investment

Summary u NPW > 0 Good Investment u EUAW > 0 Good Investment

Summary u NPW > 0 Good Investment u EUAW > 0 Good Investment u IRR > MARR Good Investment

Summary u NPW > 0 Good Investment u EUAW > 0 Good Investment u IRR > MARR Good Investment Note: If NPW > 0 EUAW > 0 IRR > MARR

Internal Rate of Return Internal Rate-of-Return IRR - internal rate of return is that return for which NPW(i*) = 0 i* = IRR i* > MARR **OK Investment** Alt: FW(i*) = 0 = A t (1 + i*) n - t PW revenue (i*) = PW costs (i*) 

Internal Rate of Return Example PW(i) = (P/A, i, 5) + 4(P/F, i, 5) 3, ,000 16,000

Internal Rate of Return Example PW(i) = (P/A, i, 5) + 4(P/F, i, 5) i* = 5 1 / 4 % i* < MARR 3, ,000 16,000

Spreadsheet Example