Mapping from conceptual model (EER-M) 24/04/2017 Mapping from conceptual model (EER-M) into a relational schema prepared by chaamwe prepared by chaamwe
Lifecycle of Database system development
Mapping an EER-Model into a relational schema This approach involves applying transformation rules (or steps) to the EER model in order to achieve a relational logical schema. NB: the steps below should not be taken as golden rules. prepared by chaamwe
Mapping an EER-Model into a relational schema Application requirements vary from one domain to another and from one user to another. Hence, the following steps should be only taken as guidelines
Step 1 For each regular entity type (ignore those with subclasses at this point) on your diagram create a table and nominate a primary key (PK) for that relation. prepared by chaamwe
Step 1 Cont:
Step 2: For each weak entity type, create a relation. The PK is a combination of the identifier of the parent entity and the identifier of the weak or dependent entity (i.e. a composite PK). prepared by chaamwe
Step 2 cont
Step 4: Each unary or binary type relationship with a one-to-one cardinality is mapped by placing a foreign key attribute in one of the relational as the linking attribute. If the relationship is mandatory OR optional from both sides, then it does not make a difference as to where to place the foreign key. prepared by chaamwe
Step 4 Cont: If it is mandatory (total participation) from one side and optional (partial participation) from the other side, then the PK of the optional side is inserted as a foreign key at the mandatory side. prepared by chaamwe
Step 4 cont:
Step 5: For Each unary or binary one-to-many relationship type. The PK from the 1-end is inserted as a FK at the N-end. prepared by chaamwe
Step 5 cont:
Step 6: Each N:M relationship of any degree is mapped to a new linking relation whose PK includes the keys of all participating relations (a composite PK). Include all relationship’s attributes in the new relation. prepared by chaamwe
Step 6 cont:
Step 7: Each multi-value attribute mapped to a new relation. The new relation should include an attribute pertaining to the main relation as a foreign key. prepared by chaamwe
Step 7 cont:
Step 3.0 If we have a single optional (always!) subtype then: Create a relation for the superclass and identify a PK for it; Create a relation for the single subtype. The Subtype’s PK is the same as the one for the Superclass entity. Add all other specific attributes to the subclass.
Example
Step 3/ Multi Subclasses If we have more than one subtype, there are four different possibilities, depends on Business Rules (Constraints). These are: Disjoint Optional Disjoint Mandatory Overlapping Optional Overlapping Mandatory
Step 3a: If the participation is disjoint optional, then create a relation for the superclass and identify a PK for it. You also need to create a relation for each subclass. prepared by chaamwe
Step 3a: cont The subclass PK is the same as the one for the superclass entity. Add all other specific attributes.
disjoint optional EMPLOYEE D SECRETARY ENGINEER TECHNICIAN prepared by chaamwe
Step 3a Results EMPLOYEE (SSN, FNAME, MINT, LNAME,...); SECRETARY (SSN, TYPINGSPEED); TECHNICIAN (SSN, TGRADE); ENGINEER (SSN, ENGTYPE); prepared by chaamwe
Step 3b: If the participation is disjoint mandatory, then create a relation for each of the subclasses (no relation for the superclass) with the same PK you have chosen earlier for the superclass. Add all the specific attributes to the appropriate subclass. prepared by chaamwe
disjoint mandatory EG EMPLOYEE D SALARIED- EMPLOYEEE HOURLY- EMPLOYEE prepared by chaamwe
Step 3b Results SALARIED_EMPLOYEE (SSN, SALARY, FNAME, MINT, LNAME,...); HOURLY_EMPLOYEE (SSN, PAYSCALE, FNAME, MINT, LNAME,...); prepared by chaamwe
Step 3c: If the participation is overlapping optional, then create a single relation to represent the superclass and all its subclasses. Identify the PK, as well as, a type or flag attribute to specify class membership. The type attribute is used to indicate the participation occurrences of the superclass in the subclasses. prepared by chaamwe
Overlapping Optional The mapping is not recommended if many specific attributes are defined at the subclass, or if the subclasses are involved in relationships among themselves or with other entities. In these cases, this option should be treated as a disjoint optional (step 3a). prepared by chaamwe
overlapping optional EG EMPLOYEE O SECRETARY ENGINEER TECHNICIAN prepared by chaamwe
Step 3c Result EMPLOYEE (SSN, FNAME, MINT, LNAME, … JOBTYPE , TYPINGSPEED, TGRADE, ENGTYPE). OR EMPLOYEE (SSN, FNAME, MINT, LNAME, …, EMP_JOB (SSN, TYPINGSPEED, TGRADE, ENGTYPE) prepared by chaamwe
Step 3d The overlapping mandatory case. In this case you need to create a single relation to represent the superclass and all it subclasses. Identify the PK as well as a type or flag attribute to specify class membership. prepared by chaamwe
Step 3d cont: If the flag is “on” for a specific subclass means that the superclass has a specialisation. At least one of the flags should be “on”. Other flags could be “on” or “off”.
overlapping mandatory The mapping is not recommended if many specific attributes are defined at the subclass, or if the subclasses are involved in relationships among themselves or with other entities. In these cases, this option should be treated as a disjoint optional (step 3a). prepared by chaamwe
overlapping mandatory PART EG1 O MANUFACTURED PART PURCHASED PART prepared by chaamwe
Step 3d Result PART (PartNo, Description, MFlag, DrawingNo, ManufactureDate, BatchNo, PFlag, SupplierName, ListPrice); prepared by chaamwe
Other rules There are few semantic concepts that exist in the EER model that need to be resolved in order to be mapped easily into a relational logical model. prepared by chaamwe
Remove Complex Relationship This step involves removing or decomposing any relationship of degree d, where d is greater than two into d one-to-many relationships linked via a weak entity type. prepared by chaamwe
A ternary relationship TENANT LEASES STAFF PROPERTY prepared by chaamwe
A Decomposed ternary relationship TENANT PROPERTY STAFF HOLDS ASSOCIATED WITH ORGANISES LEASE AGREEMENT LEASE AGREEMENT prepared by chaamwe
Remove Recursive Relationships This step is to decompose any recursive relationship by creating a weak entity type prepared by chaamwe
Recursive Relationships supervises Employee prepared by chaamwe
Recursive Relationships supervises Allocated Staff Employee Allocated Staff Supervised by prepared by chaamwe
prepared by chaamwe