Bell work 1. Solve. 0.5a + 0.75a +1.2 = 1.45 0.5a + 0.75a +1.2 = 1.45 2. Solve. (x/2) + 3/16 = (5/8) 3. Solve. 5(3 + 2c) = 12 – 4(c – 6) 4. Solve. (2y.

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Bell work 1. Solve. 0.5a a +1.2 = a a +1.2 = Solve. (x/2) + 3/16 = (5/8) 3. Solve. 5(3 + 2c) = 12 – 4(c – 6) 4. Solve. (2y – 5)(y + 8) = 0

Bell work answers 1. (25/125) = (1/5) = x = (7/8) = c = (3/2) = 1½ = y = { 5/2, - 8 }

Algebra 3 Chapter 2 Section 2 Objective: Students will: 1. Solve word problems by translating words to equations that can be used to solve the problems and by using the guidelines specific to this section.

Guidelines for Solving Word Problems Using Equations (p.68) 1. If two #’s are consecutive, Call one x and the other (x + 1). 2. If two numbers are consecutive odd or consecutive even,call one number x and the other (x + 2). 3. If a number is increased by n%, the new number is (x + (n/100 ) x).

Word problems Example 1. Solve. A carpenter works one third as long after lunch as she worked before lunch. If she works a total of 8 hours, how long did she work before lunch?

Word problems solution Example 1. Solution. x ⅓x x ⅓x| | | 0 hours Lunch 8 hours let x = time (hours worked before lunch) let x = time (hours worked before lunch) Equation: x + ⅓x = 8 3 (x + ⅓x = 8) 3 3 (x + ⅓x = 8) 3 3x + 1x = 24 4x = 24 4x = 24 x = 6 hours x = 6 hours

Word problems Example 2. Solve. A certain amount of money was deposited in a bank. The value of the money increased by 25% to a final value of $ How much was originally invested?

Word problems solution Example 2. Solution. let x = the original amount invested (deposited) let x = the original amount invested (deposited) 25% =.25 (means the money earned 25 cents/dollar) Equation: x +.25 x = x = x = 100 x = 100/1.25 x = 100/1.25 x = $80.00 x = $80.00

Word problems Example 3. Solve. The sum of two consecutive odd integers is 36. What are the two integers?

Word problems solution Example 3. Solution. let x = the first odd integer & let x = the first odd integer & x+2 = the next odd integer Equation: x + (x + 2 ) = 36 2x +2 = 36 2x +2 = 36 2x = 34 2x = 34 x = 34/2 = 17 ; (x +2 ) = 17+2 =19 Thus the two odd consecutive integers are 17,19

Homework ALGEBRA 3 P. 69 (2- 28) even

Grade Homework p (2- 46) even&41 # correct/ (49/9) 6. (-502/100) (39/14) (-37/5)22.{ - 4, 8 } 24. { 3, 7}26. { 4/3, ¼ }28. { 0, 5 } 30.{0, 4, - 2} 32. (-16/3)34. { (c – 3)/ 8}36. {(5a -3h)/ c } 38. { 12/(a – b)}40. solve without clearing the decimals due to use of a calculator 41. (x -7) (x + 8) = {1, -1 } 44. { 0, 2 } 46. a. {whole numbers}b. {pos. integers} c. {neg. integers} d.{ even whole numbers} e. { whole # multiple s of 10} f. {integers} d.{ even whole numbers} e. { whole # multiple s of 10} f. {integers}

Journal Topic Write what the problems solving guidelines are for word problems from (p. 66 in your book) in the blue box in the upper left corner of the page.