Forging new generations of engineers. Moments A lesson on understanding and evaluating moments of forces.

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Presentation transcript:

Forging new generations of engineers

Moments A lesson on understanding and evaluating moments of forces

In This Lesson What is a moment? How are moments calculated? How are moments evaluated in dynamics problems? How are moments evaluated in static equilibrium problems? How do moments affect unconstrained objects?

What Is a Moment? The moment or torque of a force is a measure of the tendency of the force to rotate the body upon which it acts about an axis.

Terminology = F pivot distance = D lever arm

Formula for Moment = F pivot Moment M M = F x D distance = D

Units for Moments ForceDistanceMoment English Customary Pound (lb)Foot (ft)lb-ft SINewton (N)Meter (m)N-m

The Right Hand Rule +

Right Hand Rule THUMB POINTS TOWARD YOU POSITIVE

Right Hand Rule THUMB POINTS AWAY FROM YOU NEGATIVE

Moment Calculations Wrench F = 20 lb D = 9 in. M = -(F x D) ***Use the right hand rule to determine positive and negative. D = 9 in. =.75 ft M = -(20 lb x.75 ft) M = -15 lb-ft (15 lb-ft clockwise) ¯

Moment Calculations Longer Wrench F = 20 lb D = 1 ft M = -(F x D) M = -(20 lb x 1 ft) M = -20 lb-ft ¯

Moment Calculations L-shaped Wrench F = 20 lb D = 3 in. =.25 ft M = -(F x D) M = -(20 lb x.25 ft) M = -5 lb-ft ¯ 3 in.

Moment Calculations Offset Wrench F = 20 lb D = 8 in in. = 1.5 ft M = -(F x D) M = -(20 lb x 1.5 ft) M = -30 lb-ft ¯ 8 in. 10 in.

D = r = 50 cm =.5 m M = F x D ***Use the right hand rule to determine positive and negative. M = 100 N x.5 m M = 50 N-m Moment Calculations Wheel and Axle F = 100 N r = 50 cm +

50 o F y = Fsin50° = (100 N)(.766) F y = 76.6 N D = r = 50 cm =.5 m M = F y x D M = 76.6 N x.5 m M = 38.3 N-m Moment Calculations Wheel and Axle F = 100 N r = 50 cm FyFy FxFx

What Is Equilibrium? The state of a body or physical system at rest or in unaccelerated motion in which the resultant of all forces acting on it is zero. The sum of all moments about any point or axis is zero. ΣM = 0 M 1 + M 2 + M 3... = 0

Moment Calculations See-Saw

ΣM = 0 M 1 + ( – M 2 ) = 0 *** Use the right hand rule to determine positive and negative. M 1 = M 2 F 1 x D 1 = F 2 x D 2 25 lb x 4 ft = 40 lb x D lb-ft = 40 lb x D 2 Moment Calculations See-Saw F 1 = 25 lb F 2 = 40 lb D 1 = 4 ft D 2 = ? ft 40 lb 40 lb 2.5 ft = D 2 + ¯

ΣM = 0 M B + (–M C ) = 0 M B = M C R B x D AB = F C x D AC R B x 10 ft = 35 lb x 3 ft R B x 10 ft = 105 lb-ft Moment Calculations Loaded Beam D AB = 10 ft D AC = 3 ft A C B RARA F C = 35 lb RBRB 10 ft 10 ft R B = 10.5 lb R A + R B = 35 lb R A = 35 lb – 10.5 lb = 24.5 lb Select the pivot location A. Solve for R B.

A B C D F c = 600 lb Moment Calculations Truss 24 ft 8 ft 12 ft F B = 500 lb Replace the pinned and rolling supports with reaction forces. R AY R AX R DY D AC = 24 ft D CD = 8 ft D CB = 12 ft D AD = 32 ft

A B C D F c = 600 lb Moment Calculations Truss D AC = 24 ft D CD = 8 ft D CB = 12 ft D AD = 32 ft 24 ft 8 ft 12 ft F B = 500 lb R AY R AX R DY Select the pivot at A. Solve for R DY. 12 ft ΣM = 0 M D – M B – M C = 0 M D = M B + M C R DY x D AD = (F B x D CB ) + (F C x D AC ) R DY x 32 ft = (500 lb x 12 ft) + (600 lb x 24 ft) R DY x 32 ft = 6000 lb-ft lb-ft R DY x 32 ft = lb-ft 32 ft 32 ft R DY = lb

Moments on An Airplane AILERON Roll ELEVATORS Pitch RUDDER Yaw

PATH WITH MOMENTS Translation and Rotation PATH WITHOUT MOMENTS Pure Translation Moments on an Airplane

References Halpern, A.M. (1988). Schaum’s 3000 solved problems in physics. New York, NY: McGraw-Hill. NASA. (n.d.). The beginners' guide to aeronautics. Retrieved June 11, 2008, from 12/airplane/ Nave, C.R. (2005). HyperPhysics. Retrieved June 12, 2008, from National Institute of Standards and Technology. (2000). The NIST reference on constants, units and uncertainty. Retrieved June 11, 2008, from

Writer: Wendy DeMane Content Editor: Wes Terrell Production Work: CJ Amarosa Credits