EXAMPLE 3 Factor by grouping Factor the polynomial x 3 – 3x 2 – 16x + 48 completely. x 3 – 3x 2 – 16x + 48 Factor by grouping. = (x 2 – 16)(x – 3) Distributive.

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Presentation transcript:

EXAMPLE 3 Factor by grouping Factor the polynomial x 3 – 3x 2 – 16x + 48 completely. x 3 – 3x 2 – 16x + 48 Factor by grouping. = (x 2 – 16)(x – 3) Distributive property = (x + 4)(x – 4)(x – 3) Difference of two squares = x 2 (x – 3) – 16(x – 3)

EXAMPLE 4 Factor polynomials in quadratic form Factor completely: (a) 16x 4 – 81 and (b) 2p p p 2. a. 16x 4 – 81 Write as difference of two squares. = (4x 2 + 9)(4x 2 – 9) Difference of two squares = (4x 2 + 9)(2x + 3)(2x – 3) Difference of two squares b. 2p p p 2 Factor common monomial. = 2p 2 (p 3 + 3)(p 3 + 2) Factor trinomial in quadratic form. = (4x 2 ) 2 – 9 2 = 2p 2 (p 6 + 5p 3 + 6)

GUIDED PRACTICE for Examples 3 and 4 Factor the polynomial completely. 5. x 3 + 7x 2 – 9x – 63 x 3 + 7x 2 – 9x – 63 Factor by grouping. = (x 2 – 9)(x + 7) Distributive property = (x + 3)(x – 3) (x + 7) Difference of two squares = x 2 (x + 7) – 9(x + 3) SOLUTION

GUIDED PRACTICE for Examples 3 and g 4 – 625 a. 16g 4 – 625 Write as difference of two squares. = (4g )(4g 2 – 25) Difference of two squares = (4g )(2g + 5)(2g – 5) Difference of two squares = (4g 2 ) 2 – 25 2 SOLUTION

GUIDED PRACTICE for Examples 3 and t 6 – 20t t 2 = 4t 2 (t 4 – 5t 2 – 6t) SOLUTION 4t 6 – 20t t 2 = 4t 2 (t 2 – 3)(t 2 – 2 ) Factor common monomial. Factor trinomial in quadratic form.