Q08. Gravity.

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Presentation transcript:

Q08. Gravity

Suppose you have a pendulum clock which keeps correct time on Earth (acceleration due to gravity = 9.8 m/s2). Without changing the clock, you take it to the Moon (acceleration due to gravity = 1.6 m/s2). For every hour interval (on Earth) the Moon clock will record: (9.8/1.6) h 1 h (1.6/9.8) h <PowerClick><Answer>5</Answer><Option>5</Option></PowerClick>

The mass density of a certain planet has spherical symmetry but varies in such a way that the mass inside every spherical surface with center at the center of the planet is proportional to the radius of the surface. If r is the distance from the center of the planet to a point mass inside the planet, the gravitational force on the mass is : not dependent on r proportional to r2 proportional to r proportional to 1/ r proportional to 1/ r2 <PowerClick><Answer>4</Answer><Option>5</Option></PowerClick>

Mass inside radius R :  Force due to mass shell beyond m vanishes. Force due to mass sphere beneath m is the same as if it’s a point mass M(r) placed at the center.

Each of the four corners of a square with edge a is occupied by a point mass m. There is a fifth mass, also m, at the center of the square. To remove the mass from the center to a point far away the work that must be done by an external agent is given by : 4Gm2/a –4Gm2/a (42) Gm2/a –(42) Gm2/a 4Gm2/a2 <PowerClick><Answer>3</Answer><Option>5</Option></PowerClick>

Potential energy of m at center of square is : To bring it to infinity, where requires work

A projectile is fired straight upward from Earth's surface with a speed that is half the escape speed. If R is the radius of Earth, the highest altitude reached, measured from the surface, is R/4 R/3 R/2 R 2R <PowerClick><Answer>2</Answer><Option>5</Option></PowerClick>

By definition: Maximum height H is given by: ( Energy conservation ) 

An object is dropped from an altitude of one Earth radius above Earth's surface. If M is the mass of Earth and R is its radius the speed of the object just before it hits Earth is given by : <PowerClick><Answer>1</Answer><Option>5</Option></PowerClick>

Energy conservation :

A planet in another solar system orbits a star with a mass of 4 A planet in another solar system orbits a star with a mass of 4.0  1030 kg. At one point in its orbit it is 250  106 km from the star and is moving at 35 km/s. Take the universal gravitational constant to be 6.67  10–11 m2/s2  kg and calculate the semimajor axis of the planet's orbit. The result is : 79  106 km 160  106 km 290  106 km 320  106 km 590  106 km <PowerClick><Answer>3</Answer><Option>5</Option></PowerClick>

Energy conservation : ( M = mass of planet ) Using ( MS = mass of star, a = semimajor axis ) , we have

A spaceship is returning to Earth with its engine turned off A spaceship is returning to Earth with its engine turned off. Consider only the gravitational field of Earth and let M be the mass of Earth, m be the mass of the spaceship, and R be the distance from the center of Earth. In moving from position 1 to position 2 the kinetic energy of the spaceship increases by : <PowerClick><Answer>4</Answer><Option>5</Option></PowerClick>

Energy conservation :