Chapter 12.3 Pages 368-375. Cake example: Recipe: 2 cups flour1½ TBSP baking powder 2 eggs1 cup water 1 cup sugar1/3 cup oil Suppose in your kitchen you.

Slides:



Advertisements
Similar presentations
Chapter 12 “Stoichiometry”
Advertisements

Stoichiometry.
“Stoichiometry” Mr. Mole.
Stoichiometry Ratios The stoichiometric coefficients in a balanced chemical reaction can be used to determine the mole relationships between any combination.
Chapter 11 “Stoichiometry”
Chapter 12 “Stoichiometry”
Chapter 12 “Stoichiometry” Chemistry Tutorial Stoichiometry Mr. Mole.
“Stoichiometry” Mr. Mole u First… –A bit of review.
Limiting Reactants and Percent Yield
Chapter 9 Combining Reactions and Mole Calculations.
Limiting Reactant. + ? 2B + S ?
Chemistry 12.3 “Limiting Reagent and Percent Yield”
Chapter 9 Combining Reactions and Mole Calculations.
Limiting Reactant + ? 2B + S ? +
Section “Limiting” Reagent
Section 3 Section 3 – Part 1  Determine the limiting reagent in a reaction  Calculate the amount of product formed in a reaction, based on the limiting.
Limiting Reactants and Excess
Percent Yield. Yield u The amount of product made in a chemical reaction. u There are three types u Actual yield- what you get in the lab when the chemicals.
Starter S moles NaC 2 H 3 O 2 are used in a reaction. How many grams is that?
Chapter 12 Stoichiometry
Limiting Reactant and Percent Yield Limiting Reagent u If you are given one dozen loaves of bread, a gallon of mustard and three pieces of salami, how.
Chapter 9 Stoichiometry
UNIT VII Excess & Percentage Yield Unit 7: Lesson 2.
Greek for “measuring elements” The calculations of quantities in chemical reactions based on a balanced equation.
Chapter 11 “Stoichiometry” Mr. Mole. Let’s make some Cookies! When baking cookies, a recipe is usually used, telling the exact amount of each ingredient.
Chapter 8 Stoichiometry.
Limiting Reagent u The limiting reagent is the reactant you run out of first. u The excess reagent is the one you have left over. u The limiting reagent.
“Stoichiometry” Original slides by Stephen L. Cotton Mr. Mole.
Chapter 12 Stoichiometry
Chapter 12 Stoichiometry Mr. Mole. Molar Mass of Compounds Molar mass (MM) of a compound - determined by up the atomic masses of – Ex. Molar mass of CaCl.
Chemical Calculations
Chapter 8 Quantities in Chemical Reactions. 2 Quantities in Chemical Reactions the amount of every substance used and made in a chemical reaction is related.
Chapter 12 “Stoichiometry” Chemistry Chemistry Pioneer High School Mr. David Norton.
Limiting Reagent u If you are given one dozen loaves of bread, a gallon of mustard and three pieces of salami, how many salami sandwiches can you make?
Chapter #9 Stoichiometry. Chapter 9.1 Composition stoichiometry deals with the mass relationships of elements in compounds. Reaction stoichiometry involves.
Chapter 8 “Stoichiometry” Mr. Mole. Section 8.2 The Arithmetic of Equations u OBJECTIVES: Interpret balanced chemical equations in terms of: a) moles,
Quantities in Chemical Reactions. the amount of every substance used and made in a chemical reaction is related to the amounts of all the other substances.
The Concept of: A little different type of yield than you had in Driver’s Education class.
Gravimetric Stoichiometry Is used to calculate masses of reactants and products in a reaction.
Chapter 12 “Stoichiometry” Mr. Mole. Stoichiometry is… u Greek for “measuring elements” Pronounced “stoy kee ahm uh tree” u Defined as: calculations of.
Limiting Reactants and Excess What is the Limiting Reagent (Reactant)? It is the substance in a chemical reaction that runs out first. The limiting reactant.
Limiting Reagents and Percent Yield Limiting Reagent If you are given one dozen loaves of bread, a gallon of mustard and three pieces of salami, how.
Chapter 12 “Stoichiometry” Pre-AP Chemistry Charles Page High School Stephen L. Cotton Mr. Mole.
Limiting Reagent and Percent Yield Chapter 12.3 Page 368.
Limiting Reagents Stochiometry Chapter 9 Chemical Reactions.
Chapter 9 Stoichiometry 9.3 Limiting reagent and percent yield.
Imagine you are baking chocolate chip cookie s What materials do you need?
Ch. 9-3 Limiting Reactants & Percent Yield. POINT > Define limiting reactant POINT > Identify which reactant is limiting in a reaction POINT > Define.
TOPIC 17: INTRO TO STOICHIOMETRY EQ: EQ: How does a balanced chemical equation help you predict the number of moles and masses of reactants and products?
Today’s Do Now: Cooking with Chemistry “Let’s Make a Cake”
Stoichiometry Chapter 12. Chocolate Chip Cookies!! 1 cup butter ;1/2 cup white sugar 1 cup packed brown sugar 1 teaspoon vanilla extract 2 eggs ; 2 1/2.
Unit 6: Limiting Reactants and Percent Yield Chapter 11.3 and 11.4.
“Stoichiometry” Original slides by Stephen L. Cotton and modified by Roth, Prasad and Coglon Mr. Mole.
Chapter 9 Stoichiometry.
Sec 12.3 limiting reactant, percent, actual and theoretical Yield
“Stoichiometry” Mr. Mole.
Chapter 9 “Stoichiometry”
Chapter 9 “Stoichiometry”
Chapter 12 “Stoichiometry”
Chapter 11 “Stoichiometry”
Chapter 9 “Stoichiometry”
Cooking with Chemistry
Chapter 12 “Stoichiometry”
Unit 5 “Stoichiometry” Mr. Mole.
Stoichiometry Greek for “measuring elements”
Bell Work: Limiting Reactant Problems
Limiting Reagent If you are given one dozen loaves of bread, a gallon of mustard and three pieces of salami, how many salami sandwiches can you make? The.
Chapter 9 “Stoichiometry”
Chapter 9 “Stoichiometry”
Presentation transcript:

Chapter 12.3 Pages

Cake example: Recipe: 2 cups flour1½ TBSP baking powder 2 eggs1 cup water 1 cup sugar1/3 cup oil Suppose in your kitchen you have 14 cups flour, 4 eggs, 9 cups sugar, 15 TBSP baking powder, 10 cups of water, and 3 1/3 cups oil. How many cakes can be baked?

Flour... need 2 cups, have 14 cups = Eggs…need 2 eggs, have 4 eggs = Sugar… need 1 cup, have 9 cups = Baking powder…need 1½ TBSP, have 15 TBSP = Water…need 1 cup, have 10 cups = Oil…need 1/3 cup, have 3 1/3 = 7 cakes 2 cakes 9 cakes 10 cakes

Back to the question, how many cakes can be baked? Answer is 2 Only 4 eggs, so we have extra of all the other ingredients Eggs, in this case, is the limiting reactant

Now, assume you have 26 eggs and the quantities of the other ingredients stay the same. Which ingredients is now the limiting reactant? Flour... need 2 cups, have 14 cups = How many cakes can be made with this new limiting reactant?

Limiting Reactant The reactant you run out of (or use up) first Makes the least amount of product Excess Reactant The reactant you have left over (waste). The limiting reactant determines how much product you can make

Limiting Reactant You can recognize limiting reagent problems because they will give you 2 amounts of chemical Do two stoichiometry problems one for each reagent you are given

If 10.6 g of copper reacts with 3.83 g sulfur, how many grams of the product (copper (I) sulfide) will be formed? 2Cu + S  Cu 2 S 10.6 g Cu 63.6g Cu 1 mol Cu 2 mol Cu 1 mol Cu 2 S g Cu 2 S = 13.3 g Cu 2 S = 19.0 g Cu 2 S 3.83 g S 32.06g S 1 mol S 1 mol Cu 2 S g Cu 2 S

If 10.3 g of aluminum are reacted with 51.7 g of CuSO 4 how much copper (grams) will be produced? 2Al + 3CuSO 4 → 3Cu + Al 2 (SO 4 ) 3 The CuSO 4 is limited, so Cu = 20.6 g How much excess reagent will remain? 4.47 grams

Percent yield is the amount of product made in a chemical reaction. Three Types: Actual Yield – What you actually get in the lab Theoretical Yield – What the balanced equation tells should be made Percent Yield – Actual x 100 = Theoretical

Percent yield tells us how “efficient” a reaction is. Percent yield CANNOT be bigger than 100%. Theoretical yield will always be larger than actual yield. Why? Impure reactants, competing side reactions, loss of product in filtering or transferring between containers

Practice 6.78 g of copper is produced when 3.92 g of Al are reacted with excess copper (II) sulfate. What is the actual yield? 6.78 g Cu What is the theoretical yield? 13.8 g Cu What is the percent yield? 49.1%