Waves – Chapter 10.2 – 10.5 Transverse vs longitudinal Frequency f, wavelength, period T, wave speed – v = f Harmonic waves: y(x) = Asin(kx); with k =

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Presentation transcript:

Waves – Chapter 10.2 – 10.5 Transverse vs longitudinal Frequency f, wavelength, period T, wave speed – v = f Harmonic waves: y(x) = Asin(kx); with k = 2  Traveling waves: y(x, t) = Asin(kx +/–  t); with  = 2  f For waves on a string Total energy is proportional to A 2

Interference This is a property of waves Waves can pass through each other “like ghosts” Whenever two waves overlap in space, they add together – or superpose – in a phenomenon called interference For harmonic waves of the same wavelength, when they are in phase they add together leading to constructive interference, and when they are out of phase by 180 o – corresponding to /2 – then they add together leading to destructive interference

Superposition of two equal amplitude harmonic waves sin  + sin  = 2 sin ½(  +  ) cos ½(  -  )

Beats

Waves at a Boundary

Standing Waves Superposition of equal amplitude waves traveling in opposite directions Using the same trig identity No longer a traveling wave – but a standing wave

Standing waves on a string Only certain frequencies will allow standing waves – we require the wave to reflect and return to the starting point in phase with another oscillation. Lowest such resonant frequency (also known as the first harmonic) is the fundamental with /2 = L so f 1 = v/  v/2L Next is the second harmonic with f 2 = v/L since = L - introduces one node In general = 2L/n and f n = nv/2L = nf 1 - with n-1 nodes

Problem Ex A steel guitar string with a 10 gram mass and a total length of 1m has a length of 70 cm between the two fixed points. If the string is tuned to play an E at 330 Hz, find the tension in the string.

Standing Wave Resonance in the sand

Resonance Increase in energy input due to a matching of frequencies – other examples include NMR, ESR, resonance in springs, in pendula, in sound (we’ll see this one next)