Non-Uniform Cash Flows

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Presentation transcript:

Non-Uniform Cash Flows For example: You and several classmates have developed a keychain note-taking device that you believe will be a huge hit with college students and decide to go into business producing and selling it. Sales are expected to start small, then increase steadily for several years. Cost to produce expected to be large in first year (due to learning curve, small lot sizes, etc.) then decrease rapidly over the next several years.   EGR 312 - 04b

Arithmetic Gradient Factors (P/G, A/G) Cash flows that increase or decrease by a constant amount are considered arithmetic gradient cash flows. The amount of increase (or decrease) is called the gradient. $2000 $175 $1500   $150 $1000 $125 $500 $100   0 1 2 3 4 0 1 2 3 4 G = $25 Base = $100 G = -$500 Base = $2000 EGR 312 - 04b

Arithmetic Gradient Factors (P/G, A/G) Equivalent cash flows: => + Note: the gradient series by convention starts in year 2. $175 $150 $75 $125 $100 $100 $50 $25   0 1 2 3 4 0 1 2 3 4 0 1 2 3 4 G = $25 Base = $100   EGR 312 - 04b

Arithmetic Gradient Factors (P/G, A/G) To find P for a gradient cash flow that starts at the end of year 2 and end at year n: or P = G(P/G,i,n) where (P/G,i,n) = $nG $2G $G 0 1 2 3 … n $P   EGR 312 - 04b

Arithmetic Gradient Factors (P/G, A/G) To find P for the arithmetic gradient cash flow: P1 = _____________ P2 = _____________ P = Base(P/A, i, n) + G(P/G, i, n) = _________ $175 P = ? P2 = ? $150 P1 = ? $75 $125 $100 $100 $50  + $25   0 1 2 3 4 0 1 2 3 4 0 1 2 3 4 i = 6% P1 = 100 (P/A, 6%, 4) = 100(3.4651) = 346.51 P2 = 25 (P/G, 6%, 4) = 25 (4.9455) = 123.64 P = Base(P/A, i, n) + G(P/G, i, n) = 346.51 + 123.64 = 470.15   EGR 312 - 04b

Arithmetic Gradient Factors (P/G, A/G) To find P for the declining arithmetic gradient cash flow: P1 = _____________ P2 = _____________ P = Base(P/A, i, n) - G(P/G, i, n) = _________ P1 = ? $2000 $2000 P2 = ? $1500 $1500 $1000 $1000 -  $500 $500   0 1 2 3 4 0 1 2 3 4 0 1 2 3 4 i = 10% P1 = 2000(P/A, 10%, 4) =2000 (3.1699) =6339.80 P2 = 500( P/G, 10%, 4) = 2189.05 P = 4150.75   EGR 312 - 04b

Arithmetic Gradient Factors (P/G, A/G) To find the uniform annual series, A, for an arithmetic gradient cash flow G: A = G(P/G,i,n) (A/P,i,4) = G(A/G,i,n) Where (A/G,i,n) = $nG $2G $G 0 1 2 3 … n 0 1 2 3 … n $A   EGR 312 - 04b

Geometric Gradient Factors (Pg/A) A Geometric gradient is when the periodic payment is increasing (decreasing) by a constant percentage: A1 = $100, g = 0.1 A2 = $100(1+g) A3 = $100(1+g)2 An = $100(1+g)n-1 $133 $121 $110 $100   0 1 2 3 4   EGR 312 - 04b

Geometric Gradient Factors (Pg/A) To find the Present Worth, Pg, for a geometric gradient cash flow G: $Pg $133 $121   $110 $100   0 1 2 3 4 EGR 312 - 04b

Determining Unknown Interest Rate To find an unknown interest rate from a single-payment cash flow or uniform-series cash flow, the following methods can be used: Use of Engineering Econ Formulas Use of factor tables Spreadsheet (Excel) a) =IRR(first cell: last cell) b) =RATE(n,A,P,F)   EGR 312 - 04b

Determining Unknown Interest Rate Example: The list price for a vehicle is stated as $25,000. You are quoted a monthly payment of $658.25 per month for 4 years. What is the monthly interest rate? What interest rate would be quoted (yearly interest rate)? Using factor table: $25000 = $658.25(P/A,i,48)  (P/A,i,48) = _________ i = ________ (HINT: start with table 1, pg. 727) 0r _______ annually 37.974 = (P/A,i,48) i = 1% from table 4, pg 730 0r 12 % annually   EGR 312 - 04b

Determining Unknown Interest Rate Example (cont’d) Using formula: Use calculator solver or Excel trial and error method to find i.   EGR 312 - 04b

Determining Unknown Number of Periods (n) To find an unknown number of periods for a single-payment cash flow or uniform-series cash flow, the following methods can be used: Use of Engineering Econ. Formulas. Use of factor tables Spreadsheet (Excel) a) =NPER(i%,A,P,F)   EGR 312 - 04b

Determining Unknown Number of Periods (n) Example: Find the number of periods required such that an invest of $1000 at 5% has a future worth of $5000. P = F(P/F,5%,n) $1000 = $5000(P/F,5%,n) (P/F,5%,n) = ______________ n = ___________________ (P/F,5%,n) = 0.2 n ~ 33 periods EGR 312 - 04b