Acid Safety 1. Always check the reagent bottle which contained the acid, or ask your teacher about the dangers of the acid. 2. When mixing acid and water,

Slides:



Advertisements
Similar presentations
An analyte is the substance that is being analyzed. For example, the concentration of glucose in blood is commonly analyzed by diabetics. Glucose is the.
Advertisements

Aim: What is titration? Write the completed neutralization reaction for the following reactants. 1. Carbonic acid and potassium hydroxide 2. Phosphoric.
Acid-Base Stoichiometry
Solution Stoichiometry
Topic: Titration Do Now:.
Chemistry Notes: Titrations Chemistry  A titration is a lab procedure which uses a solution of known concentration to determine the concentration.
Neutralization Chapter 21.
Solution Stoichiometry
Titrations. Titration Method for determining the concentration of an unknown solution A measured volume of a solution of known concentration (titrant)
Neutralization & Titration Lynette Shao. Neutralization  Acids release H + ions into solutions and bases release OH - ions.  Mixing the two solutions.
Topic 1.5 Titrations. Titrations In a titration a solution of accurately known concentration is added gradually added to another solution of unknown concentration.
Review Acid Base Equilbrium & Titrations? Bozeman Sci?
ACID-BASE TITRATION Due Today: 1. Acid-Base Titration Pre- Lab 2. Gravimetric Analysis of Phosphorus Formal Lab Report Homework: 1. Acid-Base Short Report.
Reactions in Aqueous Solutions II: Calculations Chapter 11.
Molarity by Dilution Diluting Acids How to Calculate Acids in concentrated form are diluted to the desired concentration using water. Moles of acid before.
ACIDS AND BASES Acid Base Titration A very accurate method to measure concentration. Acid + Base  Salt + Water H + + OH -  H 2 O Moles H + = Moles.
Standardization of 0.1N sodium hydroxide (NaOH)
Neutralization Reaction
 Brønsted-Lowry – proton donor  Arrhenius – acids produce H + ions in water  HCl  H + + Cl -  HCl, HBr, HI, H 2 SO 4, HC 2 H 3 O 2.
Leave space between each step to add more information. 1.Write a balance chemical equation between the acid and the base. Remember it’s a double replacement.
Standardisation of Sodium Hydroxide solution
What type of reaction? HCl + NaOH  H2O + NaCl
Titration 1.
DETERMINATION OF AN UNKNOWN DIPROTIC ACID THROUGH VOLUMETRIC ANALYSIS
HCl (aq) + NaOH (aq)  NaCl (aq) + H2O (l)
Part-2 Standardization of Hydrochloric Acid Solution.
Valdosta State University Experiment 5 NaOH Standardization Valdosta State University.
General chemistry Lab 2. Chemistry Analytical Chemistry Gravimetric Analysis Oxidation and Reduction Reactions Oxidation and Reduction Reactions Instrumental.
1 Titrations (Review) In a titration a solution of accurately known concentration is added gradually added to another solution of unknown concentration.
10.3Acid-Base Stoichiometry. Titration A method for determining the concentration of a solution by reacting a known volume of that solution with a solution.
Titrations Chapter 13.
Objectives Describe how an acid-base indicator functions. Explain how to carry out an acid-base titration. Calculate the molarity of a solution from titration.
19.4 Neutralization Reactions. Neutralization During a neutralization reaction, an acid and a base react to produce a salt and water. Salts are ionic.
Acid-Base Reactions. Neutralization acid + base salt + water HCl (aq) + NaOH (aq) NaCl (aq) + H 2 O (l) H + + Cl - + Na + + OH - Na + + Cl - + H 2 O (l)
Acid-Base Reactions. Neutralization acid + base salt + water HCl (aq) + NaOH (aq) NaCl (aq) + H 2 O H + + Cl - + Na + + OH - Na + + Cl - + H 2 O H + +
POINT > Review acid-base neutralization POINT > Identify pH indicators and how they work POINT > Describe titration process.
WARM UP 1. Write the equation for the neutralization reaction between sulfuric acid (H 2 SO 4 ) and ammonium hydroxide (NH 4 OH).
Fun fun. Acid-Base Reactions. Acid-Base Neutralization  Acids and bases will react with each other to form water and a salt.  Water has a pH of 7—it.
Practical Analytical Chemistry (1) Practical (8) Faculty of Pharmacy Department of Pharmaceutical Chemistry.
Titration A standard solution is used to determine the concentration of another solution.
Solution Stoichiometry
Determination of Acetic Acid in Vinegar Principle Acetic acid, can readily be determined by titration with standard base using phenolphthalein indicator.
11.8 Acid–Base Titration The titration of an acid. A known volume of an acid is placed in a flask with an indicator and titrated with a measured volume.
Acids & Bases Titration.
Solution Stoichiometry
Titration Introduction Experiment
Ch. 15 & 16 - Acids & Bases III. Titration (p )
Acids & Bases III. Titration.
(Acid/Base neutralization)
Unit 13 – Acid, Bases, & Salts
Week 4 Primary standards, Secondary standards solutions,
Neutralization.
ACIDS AND BASES.
Types of solution stoichiometry problems
Titration.
PRACTICAL (2) Acid – based Equilibrium
Titration.
Unit 13 – Acid, Bases, & Salts
Unit 13 – Acid, Bases, & Salts
Ch. 15 & 16 - Acids & Bases III. Titration (p )
Warm-Up Do not turn in pH practice!
Review cation Ion charges anion
EXP. NO. 6 Acid Base Titration
Unit 14 – Acid, Bases, & Salts
Ch. 15 & 16 - Acids & Bases III. Titration (p )
Neutralization – Day 1.
Acid-Base Titration. Acid-Base Titration. Acid-Base Titration.
Titrations Copyright © The McGraw-Hill Companies, Inc.  Permission required for reproduction or display.
Review cation Ion charges anion
Unit 13 – Acid, Bases, & Salts
Presentation transcript:

Acid Safety 1. Always check the reagent bottle which contained the acid, or ask your teacher about the dangers of the acid. 2. When mixing acid and water, always pour the acid into the water. 3. Never allow the acid to come into contact with your skin unless your teacher has told you that it is ok.

4. Always clean up any spilled acid as soon as possible. 5. Never disturb an unmarked substance because it may be an acid. 6. If an acid comes in contact with your skin wash it with soap, because the soap will neutralize the acid.

Experiment 1

Standardization of NaOH Solution Introduction: The purpose of this experiment is to determine the concentration of an unknown NaOH solution by acid-base titration. KHC8H4O4 + NaOH KNaC8H4O4 + H2O

Titration: -It is an analytical procedure used to determine the concentration of a sample by reacting it with a standard solution. -Acid-base titration is one type of titration uses a neutralization reaction, in which an acid and a base react to produce salt and water. -The titration proceeds until the equivalence point is reached, where the number of moles of acid is equal to the number of moles of base. -Equivalence point is marked by adding indicator.

Standard Solution: It is a solution whose concentration is known accurately and used to standardize acidic and alkaline solution. *Primary standard solution: 1-Inexpensive and readily available. 2-High purity and High solubility. 3-Stability (low reactivity). 4-Low hygroscopicity and efflorescence. 5-High equivalent weight. Ex: Potassium Hydrogen Phthalate (KHP)

Indicator: It is any substance in solution that changes it's color as it react with either an acid or a base. Reagent: 1-KHP (Potassium Hydrogen Phthalate) dried for 2 hours at 110 °c (Standard Solution). 2-NaOH (Sodium Hydroxide Solution) 0.1M. 3-Phenolphthalein Indicator.

Procedure: g KHP ml H 2 O 3- 2drops indicator 4- Titrate with NaOH until get pink color

Calculation: Ex: Volume of NaOH react in standardization of NaOH = 25.3 ml -Molarity (M) of NaOH = moles of solute / liter of solution -m mole of KHP = wt. of KHP / m.wt = 0.5 / = mole = m mole -M = / 25.3 = M ~ 0.1 M

Standardization of HCL Solution Introduction: The purpose of this experiment is to determine the concentration of an unknown HCL solution by acid-base titration. NaOH + HCL NaCL + H2O

Reagent: 1-Phenolphthalein Indicator. 2-NaOH (Standard Solution) 0.1 M N HCL (Hydrochloric Acid). Procedure: 1- 10ml HCL 2- 10ml H2O 3- 2drops indicator 4- Titrate with NaOH until get pink color

Calculation: Ex: Volume of NaOH react in standardization of HCL = M HCL x V HCL = M NaOH x V NaOH M HCL =( x 10.2) / 10 = M ~ 0.1 M ml