Inverse Operations OperationInverse Operation MultiplicationDivision Multiplication Solving an equation that contains multiplication or division is similar.

Slides:



Advertisements
Similar presentations
Multiplying or Dividing 2-2
Advertisements

Inverse Operations Operation Inverse Operation
An equation is a mathematical statement that two expressions are equal. A solution of an equation is a value of the variable that makes the equation true.
Solving One Step Equations using inverse operations. 2-2
3.2 – Solving Equations Using Multiplication and Division.
Solving Equations by Adding or Subtracting Warm Up Lesson Presentation
Holt Algebra Solving Equations by Adding or Subtracting Over 20 years, the population of a town decreased by 275 people to a population of 850. Write.
An equation is a mathematical statement that two expressions are equal. A solution of an equation is a value of the variable that makes the equation true.
Warm Up  – Evaluate.  (0.29)
4. ; $22, $11, $10 5. C6. F7. B An equation is a mathematical statement that two expressions are equal. A solution of an equation is a value of the variable.
Multiplying or Dividing
Section 2.1 Solving Equations Using Properties of Equality.
4. ; $22, $11, $10 5. C6. F7. B An equation is a mathematical statement that two expressions are equal. A solution of an equation is a value of the variable.
I can solve one-step equations in one variable.. Equations that have the same solutions. In order to solve a one-step equation, you can use the properties.
Chapter 1 Review Advanced Algebra 1.
2-1 Solving One-Step Equations Warm Up Warm Up Lesson Presentation Lesson Presentation California Standards California StandardsPreview.
Multiplying or Dividing 1-3
2-2 Solving Equations by Multiplying or Dividing Warm Up Warm Up Lesson Quiz Lesson Quiz Lesson Presentation Lesson Presentation.
CONFIDENTIAL 1 Solving Equations by Multiplying or Dividing.
An equation is a mathematical statement that two expressions are equal. A solution of an equation is a value of the variable that makes the equation true.
Warm Up Solve. 1. x + 5 = 9 2. x – 34 = 72 = x – 39 x = 4 x = 106
A LGEBRA Chapter 2 – Lesson 1. O BJECTIVE : S TANDARD AF 5.0 I can solve algebraic problems involving multiple steps.
Chapter 3.2 and 3.3 – Solving One-Step Equations.
Solving Equations by Adding or Subtracting Holt McDougal Algebra 1 Solving Equations by Adding, Subtracting, Multiplying and Dividing Warm Up Warm Up Lesson.
Holt McDougal Algebra Solving Equations by Adding or Subtracting Warm Up Evaluate. 1.   (0.29) Give the opposite of each number.
Holt McDougal Algebra 1 Solving Equations by Multiplying or Dividing Solving Equations by Multiplying or Dividing Holt Algebra 1 Warm Up Warm Up Lesson.
I’m thinking of a number between 1 and 10…. Can you guess my number? play again.
Multiplying or Dividing 1-3
Solving Absolute-Value Equations
Multiplying or Dividing 1-3
3. 3 Solving Equations Using Addition or Subtraction 3
2.2 – Solving Equations Using Multiplication and Division
Monday, November 10, 2014 Today is an A day, and you will be attending 7th period Flex. Copy the HW into your agenda One step equation worksheet Complete.
Multiplying or Dividing 2-2
Solving One-Step Equations
3.2 – Solving Equations Using Multiplication and Division
Bell Ringer.
Bell Ringer.
Warm up 11/1/ X ÷ 40.
Solving 1-Step Integer Equations
Solving One-Step Equations
Multiplying or Dividing 1-3
  An equation is a mathematical statement that two expressions are equal. y=13 X=85.
Objective Solve one-step equations in one variable by using multiplication or division.
Solving One-Step Equations By Adding, Subtracting,
BEFORE: September 5, Understand the problem 2. Make a plan
Lesson Objective: I will be able to …
1.  2.  (0.29) Give the opposite of each number. 
Lesson 1-2 Solving Equations by Adding or Subtracting Lesson 1-3 Solving Equations by Multiplying or Dividing Obj: The student will be able to 1) solve.
Multiplying or Dividing 2-2
Objective Solve one-step equations in one variable by using multiplication or division.
Multiplying or Dividing
Bell Ringer.
Solving Absolute-Value Equations
Multiplying or Dividing
Solving Equations by 1-2 Adding or Subtracting Warm Up
Learning Objective Students will be able to: Solve equations in one variable that contain absolute-value expressions.
Multiplying or Dividing 2-2
Multiplying or Dividing 2-2
Multiplying or Dividing 2-2
Solve the equation. Check your answer.
Multiplying or Dividing 1-3
Multiplying or Dividing 1-3
Solving Equations Using Multiplication and Division
Solving Equations by 2-1 Adding or Subtracting Warm Up
Chapter 3.2 and 3.3 – Solving One-Step Equations
Multiplying or Dividing 2-2
Multiplying or Dividing 1-3
Warm Up Evaluate each expression. 1. (–7)(2.8) ÷ 6 3. (–9)(–9)
Presentation transcript:

Inverse Operations OperationInverse Operation MultiplicationDivision Multiplication Solving an equation that contains multiplication or division is similar to solving an equation that contains addition or subtraction. Use inverse operations to undo the operations on the variable.

Solve the equation. Example 1A: Solving Equations by Using Multiplication Since j is divided by 3, multiply both sides by 3 to undo the division. –24 = j –8 To check your solution, substitute –24 for j in the original equation. –8 = j 3 –8 –24 3 Check –8 = j 3

Solve the equation. Check your answer. Check It Out! Example 1a Since p is divided by 5, multiply both sides by 5 to undo the division. p = To check your solution, substitute 50 for p in the original equation. = 10 p Check = 10 p 5

Solve the equation. Check your answer. Example 2A: Solving Equations by Using Division Since y is multiplied by 9, divide both sides by 9 to undo the multiplication. y = To check your solution, substitute 12 for y in the original equation. 9y = 108 9(12) 108 Check 9y = 108

Solve the equation. Check your answer. Example 2B: Solving Equations by Using Division Since v is multiplied by –6, divide both sides by –6 to undo the multiplication. 0.8 = v –4.8 To check your solution, substitute 0.8 for v in the original equation. –4.8 = –6v –4.8 –6(0.8) Check –4.8 = –6v

Solve the equation. Check your answer. Check It Out! Example 2b Since y is multiplied by 0.5, divide both sides by 0.5 to undo the multiplication. y = –20 –10 To check your solution, substitute –20 for y in the original equation. 0.5y = –10 0.5(–20) –10 Check 0.5y = –10

Solve the equation. Check your answer. Check It Out! Example 2c Since k is multiplied by 15, divide both sides by 15 to undo the multiplication. k = 5 75 To check your solution, substitute 5 for k in the original equation. 15k = 75 15(5) 75 Check 15k = 75

Remember that dividing is the same as multiplying by the reciprocal. When solving equations, you will sometimes find it easier to multiply by a reciprocal instead of dividing. This is often true when an equation contains fractions.

Solve the equation. Example 3A: Solving Equations That Contain Fractions w = 24 20 To check your solution, substitute 24 for w in the original equation. w =  Check w =  The reciprocal of is. Since w is multiplied by, multiply both sides by 20

Solve the equation. Example 3B: Solving Equations That Contain Fractions = z 3 16 To check your solution, substitute for z in the original equation. 3 2 = z The reciprocal of is 8. Since z is multiplied by, multiply both sides by Check = z

Solve the equation. Check your answer. Check It Out! Example 3a – = b 1 4 To check your solution, substitute – for b in the original equation The reciprocal of is 5. Since b is multiplied by, multiply both sides by = b 5 4 – 5 4 Check 1 1 –

Check It Out! Example 3b j = 1 Solve the equation. = 4j4j is the same as j j 6 The reciprocal of is. Since j is multiplied by, multiply both sides by

Check It Out! Example 3b Continued To check your solution, substitute 1 for j in the original equation. Check 2 3 4j4j 6 =

Example 4: Application Write an equation to represent the relationship. Ciro puts of the money he earns from mowing lawns into a college education fund. This year Ciro added $285 to his college education fund. Write and solve an equation to find how much money Ciro earned mowing lawns this year. 1 4 one-fourth times earnings equals college fund m = $1140 Substitute 285 for c. Since m is divided by 4, multiply both sides by 4 to undo the division. Ciro earned $1140 mowing lawns.

Check it Out! Example 4 Write an equation to represent the relationship. The distance in miles from the airport that a plane should begin descending, divided by 3, equals the plane's height above the ground in thousands of feet. A plane began descending 45 miles from the airport. Use the equation to find how high the plane was flying when the descent began. Distance divided by 3 equals height in thousands of feet 15 = h Substitute 45 for d. The plane was flying at 15,000 ft when the descent began.

WORDS Multiplication Property of Equality You can multiply both sides of an equation by the same number, and the statement will still be true. NUMBERS 6 = 6 6(3) = 6(3) 18 = 18 ALGEBRA a = b ac = bc Properties of Equality

Division Property of Equality You can divide both sides of an equation by the same nonzero number, and the statement will still be true. WORDS a = b (c ≠ 0) 8 = 8 2 = 2 ALGEBRA NUMBERS = a c a c =

Homework Assignment Pg (22-36 even, 37-47, 57-60, 65, 77, & 78)