Two small spheres of putty, A and B, of equal mass m, hang from the ceiling on massless strings of equal length. Sphere A is raised to a height h 0 as.

Slides:



Advertisements
Similar presentations
Chapter 7 Collisions. If the sum of the external forces is zero, then PRINCIPLE OF CONSERVATION OF LINEAR MOMENTUM The total linear momentum of an isolated.
Advertisements

Conservation of Energy Chapter 11 Conservation of Energy The Law of Conservation of Energy simply states that: 1.The energy of a system is constant.
Physics 207: Lecture 13, Pg 1 Lecture 13 Goals: Assignment: l HW6 due Wednesday, Feb. 11 l For Thursday: Read all of Chapter 11 Chapter 10 Chapter 10 
Linear Momentum and Second Newton’s Law Definition of momentum: Change in momentum: 2 nd Newton’s Law: Definition of acceleration: We can write 2 nd Newton’s.
Conservation of Momentum
Warm up. Physics Honors AB –Day 1/12/15-1/13/15 Momentum and Impulse.
Chapter 7 Impulse and Momentum.
Physics 218: Mechanics Instructor: Dr. Tatiana Erukhimova Lecture 18.
1 Chapter Five Work, Energy, and Power. 2 Definitions in physics do not always match the usage of the words. We consider mechanical work, energy, and.
Linear Momentum and Collisions
AP Physics Impulse and Momentum. Which do you think has more momentum?
Momentum is Conserved in an isolated system.
Physics 218: Mechanics Instructor: Dr. Tatiana Erukhimova Lecture 27.
7-6 Inelastic Collisions
Halliday/Resnick/Walker Fundamentals of Physics 8th edition
A family decides to create a tire swing in their backyard for their son Ryan. They tie a nylon rope to a branch that is located 16 m above the earth, and.
Copyright © 2009 Pearson Education, Inc. PHY093 Lecture 2d Linear Momentum, Impulse and Collision 1.
Chapter 7 Linear Momentum
Physics Chapter 11 Energy.
Physics 215 – Fall 2014Lecture Welcome back to Physics 215 Today’s agenda: More on momentum, collisions Kinetic and potential energy Potential energy.
Using the “Clicker” If you have a clicker now, and did not do this last time, please enter your ID in your clicker. First, turn on your clicker by sliding.
Today: Momentum – chapter 9 11/03 Finish momentum & review for exam 11/8 Exam 2 (5 – 8) 11/10 Rotation 11/15 Gravity 11/17 Waves & Sound 11/22 Temperature.
Introduction to Collisions Unit 5, Presentation 2.
Momentum and Its Conservation
1 PPMF102– Lecture 3 Linear Momentum. 2 Linear momentum (p) Linear momentum = mass x velocity Linear momentum = mass x velocity p = mv p = mv SI unit:
Collisions.
Click on one of the following icons to go to that resource.
Chapter 7 Linear Momentum. Units of Chapter 7 Momentum and Its Relation to Force Conservation of Momentum Collisions and Impulse Conservation of Energy.
Two blocks (m 1 =2.5kg, m 2 =1.8kg) are hanging from a pulley as shown in the figure below. The moment of inertia through the axis of rotation passing.
Momentum The linear momentum of an object of mass m moving with a velocity is defined as the product of the mass and the velocity SI Units are kg m / s.
A series of blocks is connected to a pulley in the manner depicted below. Find the minimum mass that block C must have in order to keep block A from sliding.
Monday, Mar. 24, 2008 PHYS , Spring 2008 Dr. Jaehoon Yu 1 PHYS 1441 – Section 002 Lecture #16 Monday, Mar. 24, 2008 Dr. Jaehoon Yu Potential Energy.
Work effect of force on the displacement of the object can be computed by multiplying the force by the parallel displacement force X displacement (assuming.
Chapter 9 - Collisions Momentum and force Conservation of momentum
Chapter 7 Impulse and Momentum. 7.1 The Impulse-Momentum Theorem DEFINITION OF IMPULSE The impulse of a force is the product of the average force and.
Physics 218 Lecture 15: Momentum Alexei Safonov.
Chapter 6 Linear Momentum. Units of Chapter 6 Momentum and Its Relation to Force Conservation of Momentum Collisions and Impulse Conservation of Energy.
Momentum.
Copyright © 2010 Pearson Education, Inc. Lecture Outline Chapter 9 Physics, 4 th Edition James S. Walker.
The force on an object may not be constant, but may vary over time. The force can be averaged over the time of application to find the impulse.
Chapter 14 Systems of Particles.
Chapter 7 Linear Momentum. Objectives: Students will be able to: Explain that a conserved quantity is a quantity that remains numerically constant. Define.
2D Collisions Physics 12 Adv.
Chapter 9:Linear Momentum
3.5 The Law of Conservation of Mechanical Energy p. 106 Conservation of Mechanical Energy EpEp EkEk A frictionless pendulum would swing from its high point.
Blended Learning Lesson 8 Dynamics 4: Collisions I figured it out already. Need three laws only.
Topic 2.2 Extended E – Elastic and inelastic collisions.
Motion 3.2 Solving Collision & Explosion Problems
A large wooden wheel of radius R and moment of inertia I w is mounted on an axle so as to rotate freely. A bullet of mass m b and speed v b is shot tangential.
Chap 8.3 and 8.4 Conservation of Momentum
Conservation of Momentum Elastic & Inelastic Collisions.
Collisions SPH4U. Momentum vs. Energy All interactions conserve momentum. They do not necessarily conserve kinetic energy.
Chapter 9:Linear Momentum
Elastic and Inelastic Collisions
A ball attached to a 3.0m string (pendulum)
LINEAR MOMENTUM The rate of change of the linear momentum of a particle is equal to the net force acting on the particle.
Test Review: Examples Chapters on the test: - momentum - energy/work - oscillations Physics 1D03 - Lecture 34.
ENGR 214 Chapter 14 Systems of Particles
Linear Momentum and Second Newton’s Law
Elastic Collisions.
DEFINITION OF AVERAGE POWER
Quiz 1 Period 2.
Lecture Outline Chapter 9 Physics, 4th Edition James S. Walker
Chapter 7 Impulse and Momentum.
Linear Momentum.
Lecture Outline Chapter 9 Physics, 4th Edition James S. Walker
Impulse and Momentum Chapter 7.
Collisions Chapter 4.
Conservation Laws Conservation of Momentum II
Lecture Outline Chapter 9 Physics, 4th Edition James S. Walker
Presentation transcript:

Two small spheres of putty, A and B, of equal mass m, hang from the ceiling on massless strings of equal length. Sphere A is raised to a height h 0 as shown below and released. It collides with sphere B (which is initially at rest). The two spheres stick and swing together to a maximum height h f. (assume a perfectly inelastic collision, where there is no internal energy lost to deformation, heating, etc.) Find the height h f in terms of h 0. y x h0h0 hfhf A B B A Lowest point in path is the point of zero gravitational potential

Question 1 Question 2 Question 3 Question 4 Question 5 Question 6 Question 7

1. Which of the following physics principles should we use to solve this problem. AA) Conservation of Total Mechanical Energy BB) Conservation of Momentum CC) Newton’s 2nd Law

Choice A Correct, but this is not the only principle that we need to apply. We will need to apply this principle to this problem twice in order to find relations between the initial height and the speed of ball A, and between the speed of the merged balls and the maximum height that the two balls reach together. We will also need to think about the conservation of momentum.

We will need to apply this principle to this problem in order to find a relation between the speed of ball A right before collision and the speed of the two balls together. We will also need to think about the conservation of energy. Choice B Correct, but this is not the only principle that we need to apply.

Newton’s 2nd Law will be of no use to us here. Remember, we are concerned with the speeds of the putty balls, and their initial and final heights. Newton’s 2nd Law will not lead us to useful relations. Choice C Incorrect

2. We want to find the speed at which putty ball A strikes putty ball B. We can find this using the law of conservation of energy. What types of mechanical energy does ball A have initially and just before colliding with ball B (final)? AA) Kinetic Gravitational potential BB) Gravitational potential Kinetic CC) Kinetic & Gravitational potential Gravitational potential Initial EnergyFinal Energy

Putty ball A starts from rest, so it will not have kinetic energy initially. Also, the lowest point of the ball’s motion is considered to be the point of zero gravitational potential (h=0). Choice A Incorrect

This is true because ball A starts from rest and reaches a point of zero gravitational potential with a speed v A. Choice B Correct

Choice C Incorrect Putty ball A starts from rest, so it will not have kinetic energy initially. Also, the lowest point of the balls’ motion is considered to be the point of zero gravitational potential (h=0).

3. Applying the law of conservation of energy to ball A gives which of the following expressions for the speed of ball A at the moment right before it collides with ball B? A)B)C)A)B)C) Initial Final

Choice A Correct Reasoning:

Choice B Incorrect kinetic energy gravitational potential energy

Choice C Incorrect kinetic energy gravitational potential energy

4. In order to find an expression for the speed of the merged balls (v AB ), in terms of the speed of ball A immediately before the collision (v A ), we need to use which conservation principle? AA) Conservation of Momentum BB) Conservation of Total Energy CC) Conservation of Angular Momentum

When we set the momentum before the collision equal to the momentum of the system after the collision, there will not be other variables in our relation between the speeds, because we know that m A =m B =m. Choice A Correct Note: In general, this problem can be solved for spheres with different masses. This problem is a more specific case of colliding pendulums. Note: In general, this problem can be solved for spheres with different masses. This problem is a more specific case of colliding pendulums.

We can relate the two speeds this way, but this expression will involve other variables. Choice B Incorrect

This does not help us with the problem at hand. Choice C Incorrect

5. Which of the following expressions correctly relates the speed of ball A immediately before the collision and the speed of both balls moving together? A)B)C)A)B)C)

Choice A Correct Reasoning: m A =m B =m

Choice B Incorrect P=total linear momentum 0,f subscripts represent before and after collision P=total linear momentum 0,f subscripts represent before and after collision Since m A =m B =m Since m A =m B =m

Choice C Incorrect Since m A =m B =m Since m A =m B =m P=total linear momentum 0,f subscripts represent before and after collision P=total linear momentum 0,f subscripts represent before and after collision

6. Once again, use the law of conservation of energy for the initial moment right before the collision to the final moment where balls A & B reach their maximum height. Which one of the following expressions is correct for h f ? A)B)C)A)B)C)

Choice A Incorrect m A =m B =m

Choice B Incorrect m A =m B =m

Choice C Correct Reasoning:

7. Use the relations that we found in previous questions to find an expression for the maximum height of the two balls together (h f ) in terms of the initial height of ball A (h 0 ). Which of the following expressions is correct? A)B)C)A)B)C)

Choice A Incorrect From our previous expressions: We see that:

Choice B Correct Reasoning: The two putty balls will reach a maximum height that is 1/4th of ball A’s initial height.

Choice C Incorrect From our previous expressions: We see that:

Reflection Questions: Answer this question twice more for balls of differing mass: –