DIFFERENTIATION RULES

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Presentation transcript:

DIFFERENTIATION RULES We have: Seen how to interpret derivatives as slopes and rates of change Seen how to estimate derivatives of functions given by tables of values Learned how to graph derivatives of functions that are defined graphically Used the definition of a derivative to calculate the derivatives of functions defined by formulas

However, it would be tedious if we always had to use the definition. DIFFERENTIATION RULES However, it would be tedious if we always had to use the definition. So, in this chapter, we develop rules for finding derivatives without having to use the definition directly.

DIFFERENTIATION RULES These differentiation rules enable us to calculate with relative ease the derivatives of: Polynomials Rational functions Algebraic functions Exponential and logarithmic functions Trigonometric and inverse trigonometric functions

3.1 Derivatives of Polynomials and Exponential Functions DIFFERENTIATION RULES 3.1 Derivatives of Polynomials and Exponential Functions In this section, we will learn: How to differentiate constant functions, power functions, polynomials, and exponential functions.

CONSTANT FUNCTION Let us start with the simplest of all functions, the constant function f(x) = c.

CONSTANT FUNCTION The graph of this function is the horizontal line y = c, which has slope 0. So, we must have f’(x) = 0.

A formal proof, from the definition of a derivative, is also easy. CONSTANT FUNCTION A formal proof, from the definition of a derivative, is also easy.

In Leibniz notation, we write this rule as follows. DERIVATIVE In Leibniz notation, we write this rule as follows.

POWER FUNCTIONS We next look at the functions f (x) = xn, where n is a positive integer.

POWER FUNCTIONS Equation 1 If n = 1, the graph of f (x) = x is the line y = x, which has slope 1. So, You can also verify Equation 1 from the definition of a derivative.

We have already investigated the cases n = 2 and n = 3. POWER FUNCTIONS Equation 2 We have already investigated the cases n = 2 and n = 3. In fact, in Section 2.8, we found that:

For n = 4 we find the derivative of f(x) = x4 as follows: POWER FUNCTIONS For n = 4 we find the derivative of f(x) = x4 as follows:

POWER FUNCTIONS Equation 3 Thus,

Comparing Equations 1, 2, and 3, we see a pattern emerging. POWER FUNCTIONS Comparing Equations 1, 2, and 3, we see a pattern emerging. It seems to be a reasonable guess that, when n is a positive integer, (d/dx)(xn) = nxn - 1. This turns out to be true.

If n is a positive integer, then POWER RULE If n is a positive integer, then

POWER RULE Proof 1 The formula can be verified simply by multiplying out the right-hand side (or by summing the second factor as a geometric series).

POWER RULE Proof 1 If f (x) = x n, we can use Equation 5 in Section 2.7 for f’(a) and the previous equation to write:

We illustrate the Power Rule using various notations in Example 1.

If f (x) = x6, then f’(x) = 6x5 If y = x1000, then y’ = 1000x999 POWER RULE Example 1 If f (x) = x6, then f’(x) = 6x5 If y = x1000, then y’ = 1000x999 If y = t 4, then

What about power functions with negative integer exponents? NEGATIVE INTEGERS What about power functions with negative integer exponents? In Exercise 61, we ask you to verify from the definition of a derivative that: We can rewrite this equation as:

So, the Power Rule is true when n = -1. NEGATIVE INTEGERS So, the Power Rule is true when n = -1. In fact, we will show in the next section that it holds for all negative integers.

What if the exponent is a fraction? FRACTIONS What if the exponent is a fraction? In Example 3 in Section 2.8, we found that: This can be written as:

This shows that the Power Rule is true even when n = ½. FRACTIONS This shows that the Power Rule is true even when n = ½. In fact, we will show in Section 3.6 that it is true for all real numbers n.

If n is any real number, then POWER RULE—GENERAL VERSION If n is any real number, then

POWER RULE Example 2 Differentiate: a. b. In each case, we rewrite the function as a power of x.

Since f(x) = x-2, we use the Power Rule with n = -2: Example 2 a Since f(x) = x-2, we use the Power Rule with n = -2:

POWER RULE Example 2 b

TANGENT LINES The Power Rule enables us to find tangent lines without having to resort to the definition of a derivative.

It also enables us to find normal lines. The normal line to a curve C at a point P is the line through P that is perpendicular to the tangent line at P. In the study of optics, one needs to consider the angle between a light ray and the normal line to a lens.

Illustrate by graphing the curve and these lines. TANGENT AND NORMAL LINES Example 3 Find equations of the tangent line and normal line to the curve at the point (1, 1). Illustrate by graphing the curve and these lines.

The derivative of is: So, the slope of the tangent line at (1, 1) is: Example 3 The derivative of is: So, the slope of the tangent line at (1, 1) is: Thus, an equation of the tangent line is: or

The normal line is perpendicular to the tangent line. Example 3 The normal line is perpendicular to the tangent line. So, its slope is the negative reciprocal of , that is . Thus, an equation of the normal line is:

We graph the curve and its tangent line and normal line here. TANGENT AND NORMAL LINES Example 3 We graph the curve and its tangent line and normal line here.

NEW DERIVATIVES FROM OLD When new functions are formed from old functions by addition, subtraction, or multiplication by a constant, their derivatives can be calculated in terms of derivatives of the old functions.

NEW DERIVATIVES FROM OLD In particular, the following formula says that: the derivative of a constant times a function is the constant times the derivative of the function.

If c is a constant and f is a differentiable function, then CONSTANT MULTIPLE RULE If c is a constant and f is a differentiable function, then

CONSTANT MULTIPLE RULE Proof Let g(x) = cf(x). Then,

NEW DERIVATIVES FROM OLD Example 4

NEW DERIVATIVES FROM OLD The next rule tells us that the derivative of a sum of functions is the sum of the derivatives.

If f and g are both differentiable, then SUM RULE If f and g are both differentiable, then

Let F(x) = f(x) + g(x). Then, SUM RULE Proof Let F(x) = f(x) + g(x). Then,

The Sum Rule can be extended to the sum of any number of functions. For instance, using this theorem twice, we get:

NEW DERIVATIVES FROM OLD By writing f - g as f + (-1)g and applying the Sum Rule and the Constant Multiple Rule, we get the following formula.

If f and g are both differentiable, then DIFFERENCE RULE If f and g are both differentiable, then

NEW DERIVATIVES FROM OLD The Constant Multiple Rule, the Sum Rule, and the Difference Rule can be combined with the Power Rule to differentiate any polynomial—as the following examples demonstrate.

NEW DERIVATIVES FROM OLD Example 5

NEW DERIVATIVES FROM OLD Example 5

NEW DERIVATIVES FROM OLD Example 6 Find the points on the curve y = x4 - 6x2 + 4 where the tangent line is horizontal.

Horizontal tangents occur where the derivative is zero. NEW DERIVATIVES FROM OLD Example 6 Horizontal tangents occur where the derivative is zero. We have: Thus, dy/dx = 0 if x = 0 or x2 – 3 = 0, that is,

So, the given curve has horizontal tangents when x = 0, , and . NEW DERIVATIVES FROM OLD Example 6 So, the given curve has horizontal tangents when x = 0, , and . The corresponding points are (0, 4), ( , -5), and ( , -5).

NEW DERIVATIVES FROM OLD Example 7 The equation of motion of a particle is s = 2t3 - 5t2 + 3t + 4, where s is measured in centimeters and t in seconds. Find the acceleration as a function of time. What is the acceleration after 2 seconds?

The velocity and acceleration are: NEW DERIVATIVES FROM OLD Example 7 The velocity and acceleration are: The acceleration after 2 seconds is: a(2) = 14 cm/s2

EXPONENTIAL FUNCTIONS Let us try to compute the derivative of the exponential function f(x) = a x using the definition of a derivative:

EXPONENTIAL FUNCTIONS The factor ax does not depend on h. So, we can take it in front of the limit: Notice that the limit is the value of the derivative of f at 0, that is,

EXPONENTIAL FUNCTIONS The factor ax does not depend on h. So, we can take it in front of the limit: Notice that the limit is the value of the derivative of f at 0, that is,

EXPONENTIAL FUNCTIONS Equation 4 Thus, we have shown that, if the exponential function f (x) = a x is differentiable at 0, then it is differentiable everywhere and The equation states that the rate of change of any exponential function is proportional to the function itself. The slope is proportional to the height.

EXPONENTIAL FUNCTIONS If we put a = e and, therefore, f’(0) = ln(e) = 1 in Equation 4, it becomes the following important differentiation formula.

The derivative of the natural exponential function is:

EXPONENTIAL FUNCTIONS Thus, the exponential function f(x) = e x has the property that it is its own derivative. The geometrical significance of this fact is that the slope of a tangent line to the curve y = ex is equal to the coordinate of the point.

If f(x) = ex - x, find f’ and f’’. Compare the graphs of f and f’. EXPONENTIAL FUNCTIONS Example 8 If f(x) = ex - x, find f’ and f’’. Compare the graphs of f and f’.

Using the Difference Rule, we have: EXPONENTIAL FUNCTIONS Example 8 Using the Difference Rule, we have:

EXPONENTIAL FUNCTIONS Example 8 In Section 2.8, we defined the second derivative as the derivative of f’. So,

The function f and its derivative f’ are graphed here. EXPONENTIAL FUNCTIONS Example 8 The function f and its derivative f’ are graphed here. Notice that f has a horizontal tangent when x = 0. This corresponds to the fact that f’(0) = 0.

Notice also that, for x > 0, f’(x) is positive and f is increasing. EXPONENTIAL FUNCTIONS Example 8 Notice also that, for x > 0, f’(x) is positive and f is increasing. When x < 0, f’(x) is negative and f is decreasing.

EXPONENTIAL FUNCTIONS Example 9 At what point on the curve y = ex is the tangent line parallel to the line y = 2x?

Since y = ex, we have y’ = ex. EXPONENTIAL FUNCTIONS Example 9 Since y = ex, we have y’ = ex. Let the x-coordinate of the point in question be a. Then, the slope of the tangent line at that point is ea.

EXPONENTIAL FUNCTIONS Example 9 This tangent line will be parallel to the line y = 2x if it has the same slope, that is, 2. Equating slopes, we get: ea = 2 a = ln 2

Thus, the required point is: (a, ea) = (ln 2, 2) EXPONENTIAL FUNCTIONS Example 9 Thus, the required point is: (a, ea) = (ln 2, 2)