 When given the equation of a line that is perpendicular to the one you are interested in and a point on the line of interest, finding an equation for.

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Write an equation given the slope and a point
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Presentation transcript:

 When given the equation of a line that is perpendicular to the one you are interested in and a point on the line of interest, finding an equation for the line of interest is very straight forward.

 Suppose you have a line given by the equation y=5x+2.  Find the equation of a line that passes through the point (2,3) and is perpendicular to the above line.

 Because the line you are trying to describe is perpendicular to the one given, its slope must be the negative reciprocal of the slope of the given line.

 In order to find the slope easily, put the equation of the given line in slope- intercept form if it already is not in that form.

Given line in slope- intercept form (y=mx+b) Slope

Input Output y-coordinate of a point on the line x-coordinate of the same point on the line

Substitute in values and simplify Equation of the line in point-slope form

Distribute Write equation in slope-intercept form (y=mx+b) Combine constant terms

Equation of the line of interest in slope-intercept form

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