어휘분석 (Lexical Analysis)

Overview Main task: to read input characters and group them into “ tokens. ” Secondary tasks: –Skip comments and whitespace; –Correlate error messages with source program (e.g., line number of error).

Overview (cont ’ d)

Lexical Analysis: Terminology token: a name for a set of input strings with related structure. Example: “ identifier, ” “ integer constant ” pattern: a rule describing the set of strings associated with a token. Example: “ a letter followed by zero or more letters, digits, or underscores. ” lexeme: the actual input string that matches a pattern. Example: count

Examples Input: count = 123 Tokens: identifier : Rule: “ letter followed by …” Lexeme: count assg_op : Rule: = Lexeme: = integer_const : Rule: “ digit followed by …” Lexeme: 123

Why token? Language syntax is specified with token types, not words (lexeme) 1. goal  expr 2. expr  expr op term 3. | term 4. term  number 5. | id 6. op  + 7. | – S = goal T = { number, id, +, - } N = { goal, expr, term, op } P = { 1, 2, 3, 4, 5, 6, 7}

Specifying Tokens: regular expressions Terminology: –alphabet : a finite set of symbols –string : a finite sequence of alphabet symbols –language : a (finite or infinite) set of strings. Regular Operations on languages: Union: R  S = { x | x  R or x  S} Concatenation: RS = { xy | x  R and y  S} Kleene closure: R* = R concatenated with itself 0 or more times = {  }  R  RR  RRR  = strings obtained by concatenating a finite number of strings from the set R.

Regular Expressions A pattern notation for describing certain kinds of sets over strings: Given an alphabet  : –  is a regular exp. (denotes the language {  }) –for each a  , a is a regular exp. (denotes the language {a}) –if r and s are regular exps. denoting L(r) and L(s) respectively, then so are: (r) | (s) ( denotes the language L(r)  L(s) ) (r)(s) ( denotes the language L(r)L(s) ) (r)* ( denotes the language L(r)* )

Common Extensions to r.e. Notation One or more repetitions of r : r+ A range of characters : [a-zA-Z], [0-9] An optional expression: r? Any single character:. Giving names to regular expressions, e.g.: –letter = [a-zA-Z_] –digit = 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 –ident = letter ( letter | digit )* –Integer_const = digit+

Examples of Regular Expressions Identifiers: Letter  (a|b|c| … |z|A|B|C| … |Z) Digit  (0|1|2| … |9) Identifier  Letter ( Letter | Digit ) * Numbers: [0-9][0-9]+[0-9]* [1-9][0-9]* ([1-9][0-9]*)|0 -?[0-9]+ [0-9]*\.[0-9]+([0-9]+)|([0-9]*\.[0-9]+) [eE][-+]?[0-9]+([0-9]*\.[0-9]+)([eE][-+]?[0-9]+)? -?( ([0-9]+) | ([0-9]*\.[0-9]+)([eE][-+]?[0-9]+)? )

Examples of Regular Expressions Numbers: Integer  (+|-|  ) (0| (1|2|3| … |9)(Digit * ) ) Decimal  Integer. Digit * Real  ( Integer | Decimal ) E (+|-|  ) Digit * Complex  ( Real, Real )

Exercise of Regular Expressions 문자열 [a-z][a-zA-Z][a-zA-Z0-9] [a-zA-Z][a-zA-Z0-9]* 스트링 –"this is a string" \".*\"<- wrong!!! why? \"[^"]*\" 몇가지 연습 0 과 1 로 이루어진 문자열 중에서... –0 으로 시작하는 문자열 0[01]* –0 으로 시작해서 0 으로 끝나는 문자열 0[01]*0 –0 과 1 이 번갈아 나오는 문자열 ______ –0 이 두번 계속 나오지 않는 문자열 ______

Recognizing Tokens: Finite Automata A finite automaton is a 5-tuple (Q, , T, q0, F), where: –  is a finite alphabet; –Q is a finite set of states; –T: Q    Q is the transition function; –q0  Q is the initial state; and –F  Q is a set of final states.

Finite Automata: An Example A (deterministic) finite automaton (DFA) to match C-style comments:

Consider the problem of recognizing register names Register  r (0|1|2| … | 9) (0|1|2| … | 9) * Allows registers of arbitrary number Requires at least one digit RE corresponds to a recognizer (or DFA ) Transitions on other inputs go to an error state, s e Example 2 S0S0 S2S2 S1S1 r (0|1|2| … 9) accepting state (0|1|2| … 9) Recognizer for Register

DFA operation Start in state S 0 & take transitions on each input character DFA accepts a word x iff x leaves it in a final state (S 2 ) So, r17 takes it through s 0, s 1, s 2 and accepts r takes it through s 0, s 1 and fails a takes it straight to s e Example 2 ( continued ) S0S0 S2S2 S1S1 r (0|1|2| … 9) accepting state (0|1|2| … 9) Recognizer for Register

Example 2 (continued) To be useful, recognizer must turn into code sese sese sese sese sese s2s2 sese s2s2 sese s2s2 sese s1s1 sese sese s1s1 s0s0 All others 0,1,2,3,4,5, 6,7,8,9r  Char  next character State  s 0 while (Char  EOF) State   (State,Char) Char  next character if (State is a final state ) then report success else report failure Skeleton recognizer Table encoding RE

r Digit Digit * allows arbitrary numbers Accepts r00000 Accepts r99999 What if we want to limit it to r0 through r31 ? Write a tighter regular expression –Register  r ( (0|1|2) (Digit |  ) | (4|5|6|7|8|9) | (3|30|31) ) –Register  r0|r1|r2| … |r31|r00|r01|r02| … |r09 Produces a more complex DFA Has more states Same cost per transition Same basic implementation What if we need a tighter specification?

Tighter register specification (continued) The DFA for Register  r ( (0|1|2) (Digit |  ) | (4|5|6|7|8|9) | (3|30|31) ) Accepts a more constrained set of registers Same set of actions, more states S0S0 S5S5 S1S1 r S4S4 S3S3 S6S6 S2S2 0,1,20,1,2 3 0,10,1 4,5,6,7,8,94,5,6,7,8,9 (0|1|2| … 9)

sese sese sese sese sese S1S1 s0s0 sese sese sese sese sese sese sese sese sese sese sese sese sese s6s6 sese sese sese sese s6s6 sese s5s5 sese sese sese sese sese sese s4s4 sese sese sese sese sese sese s3s3 sese s3s3 s3s3 s3s3 s3s3 sese s2s2 sese s4s4 s5s5 s2s2 s2s2 sese s1s1 All others4-9320,1r  Table encoding RE for the tighter register specification Tighter register specification (continued)

Automating Scanner Construction RE→ NFA (Thompson’s construction) –Build an NFA for each term –Combine them with ε-moves NFA → DFA (subset construction) –Build the simulation DFA → Minimal DFA –Hopcroft’s algorithm DFA →RE (Not part of the scanner construction) –All pairs, all paths problem –Take the union of all paths from s0 to an accepting state