15.082 and 6.855J Cycle Canceling Algorithm. 2 A minimum cost flow problem 1 24 35 10, $4 20, $1 20, $2 25, $2 25, $5 20, $6 30, $7 25 0 0 0-25.

Slides:



Advertisements
Similar presentations
TWO STEP EQUATIONS 1. SOLVE FOR X 2. DO THE ADDITION STEP FIRST
Advertisements

You have been given a mission and a code. Use the code to complete the mission and you will save the world from obliteration…
Advanced Piloting Cruise Plot.
Copyright © 2003 Pearson Education, Inc. Slide 1 Computer Systems Organization & Architecture Chapters 8-12 John D. Carpinelli.
Chapter 1 The Study of Body Function Image PowerPoint
1 Copyright © 2010, Elsevier Inc. All rights Reserved Fig 2.1 Chapter 2.
1 Chapter 40 - Physiology and Pathophysiology of Diuretic Action Copyright © 2013 Elsevier Inc. All rights reserved.
By D. Fisher Geometric Transformations. Reflection, Rotation, or Translation 1.
Business Transaction Management Software for Application Coordination 1 Business Processes and Coordination.
and 6.855J Dijkstras Algorithm with simple buckets (also known as Dials algorithm)
and 6.855J Spanning Tree Algorithms. 2 The Greedy Algorithm in Action
Jeopardy Q 1 Q 6 Q 11 Q 16 Q 21 Q 2 Q 7 Q 12 Q 17 Q 22 Q 3 Q 8 Q 13
Jeopardy Q 1 Q 6 Q 11 Q 16 Q 21 Q 2 Q 7 Q 12 Q 17 Q 22 Q 3 Q 8 Q 13
Title Subtitle.
My Alphabet Book abcdefghijklm nopqrstuvwxyz.
Multiplying binomials You will have 20 seconds to answer each of the following multiplication problems. If you get hung up, go to the next problem when.
Exponents You will have 20 seconds to complete each of the following 16 questions. A chime will sound as each slide changes. Read the instructions at.
0 - 0.
2 pt 3 pt 4 pt 5 pt 1 pt 2 pt 3 pt 4 pt 5 pt 1 pt 2 pt 3 pt 4 pt 5 pt 1 pt 2 pt 3 pt 4 pt 5 pt 1 pt 2 pt 3 pt 4 pt 5 pt 1 pt Time Money AdditionSubtraction.
ALGEBRAIC EXPRESSIONS
DIVIDING INTEGERS 1. IF THE SIGNS ARE THE SAME THE ANSWER IS POSITIVE 2. IF THE SIGNS ARE DIFFERENT THE ANSWER IS NEGATIVE.
MULTIPLYING MONOMIALS TIMES POLYNOMIALS (DISTRIBUTIVE PROPERTY)
ADDING INTEGERS 1. POS. + POS. = POS. 2. NEG. + NEG. = NEG. 3. POS. + NEG. OR NEG. + POS. SUBTRACT TAKE SIGN OF BIGGER ABSOLUTE VALUE.
MULTIPLICATION EQUATIONS 1. SOLVE FOR X 3. WHAT EVER YOU DO TO ONE SIDE YOU HAVE TO DO TO THE OTHER 2. DIVIDE BY THE NUMBER IN FRONT OF THE VARIABLE.
SUBTRACTING INTEGERS 1. CHANGE THE SUBTRACTION SIGN TO ADDITION
MULT. INTEGERS 1. IF THE SIGNS ARE THE SAME THE ANSWER IS POSITIVE 2. IF THE SIGNS ARE DIFFERENT THE ANSWER IS NEGATIVE.
FACTORING Think Distributive property backwards Work down, Show all steps ax + ay = a(x + y)
FACTORING ax2 + bx + c Think “unfoil” Work down, Show all steps.
Addition Facts
Year 6 mental test 5 second questions
C1 Sequences and series. Write down the first 4 terms of the sequence u n+1 =u n +6, u 1 =6 6, 12, 18, 24.
SOLVING EQUATIONS AND EXPANDING BRACKETS
ZMQS ZMQS
Richmond House, Liverpool (1) 26 th January 2004.
REVIEW: Arthropod ID. 1. Name the subphylum. 2. Name the subphylum. 3. Name the order.
BT Wholesale October Creating your own telephone network WHOLESALE CALLS LINE ASSOCIATED.
ABC Technology Project
Shadow Prices vs. Vickrey Prices in Multipath Routing Parthasarathy Ramanujam, Zongpeng Li and Lisa Higham University of Calgary Presented by Ajay Gopinathan.
Outline Minimum Spanning Tree Maximal Flow Algorithm LP formulation 1.
1 Undirected Breadth First Search F A BCG DE H 2 F A BCG DE H Queue: A get Undiscovered Fringe Finished Active 0 distance from A visit(A)
© S Haughton more than 3?
VOORBLAD.
1 Breadth First Search s s Undiscovered Discovered Finished Queue: s Top of queue 2 1 Shortest path from s.
1 Directed Depth First Search Adjacency Lists A: F G B: A H C: A D D: C F E: C D G F: E: G: : H: B: I: H: F A B C G D E H I.
Twenty Questions Subject: Twenty Questions
Factor P 16 8(8-5ab) 4(d² + 4) 3rs(2r – s) 15cd(1 + 2cd) 8(4a² + 3b²)
Squares and Square Root WALK. Solve each problem REVIEW:
Basel-ICU-Journal Challenge18/20/ Basel-ICU-Journal Challenge8/20/2014.
SYSTEMS OF EQUATIONS.
© 2012 National Heart Foundation of Australia. Slide 2.
Lets play bingo!!. Calculate: MEAN Calculate: MEDIAN
Past Tense Probe. Past Tense Probe Past Tense Probe – Practice 1.
Understanding Generalist Practice, 5e, Kirst-Ashman/Hull
Chapter 5 Test Review Sections 5-1 through 5-4.
GG Consulting, LLC I-SUITE. Source: TEA SHARS Frequently asked questions 2.
Addition 1’s to 20.
25 seconds left…...
Test B, 100 Subtraction Facts
Januar MDMDFSSMDMDFSSS
Week 1.
We will resume in: 25 Minutes.
©Brooks/Cole, 2001 Chapter 12 Derived Types-- Enumerated, Structure and Union.
1 Unit 1 Kinematics Chapter 1 Day
PSSA Preparation.
Essential Cell Biology
Cycle Canceling Algorithm
Introduction to Minimum Cost Flows
Presentation transcript:

and 6.855J Cycle Canceling Algorithm

2 A minimum cost flow problem , $4 20, $1 20, $2 25, $2 25, $5 20, $6 30, $

3 The Original Capacities and Feasible Flow ,10 20,20 20,10 25,5 25,15 20,0 30, The feasible flow can be found by solving a max flow.

4 Capacities on the Residual Network

5 Costs on the Residual Network Find a negative cost cycle, if there is one.

6 Send flow around the cycle Send flow around the negative cost cycle The capacity of this cycle is 15. Form the next residual network.

7 Capacities on the residual network

8 Costs on the residual network Find a negative cost cycle, if there is one. 5

9 Send flow around the cycle Send flow around the negative cost cycle The capacity of this cycle is 10. Form the next residual network

Capacities on the residual network

11 Costs in the residual network Find a negative cost cycle, if there is one.

12 Send Flow Around the Cycle Send flow around the negative cost cycle The capacity of this cycle is 5. Form the next residual network

13 Capacities on the residual network

14 Costs in the residual network Find a negative cost cycle, if there is one.

15 Send Flow Around the Cycle Send flow around the negative cost cycle The capacity of this cycle is 5. Form the next residual network

16 Capacities on the residual network

17 Costs in the residual network Find a negative cost cycle, if there is one. There is no negative cost cycle. But what is the proof?

18 Compute shortest distances in the residual network Let d(j) be the shortest path distance from node 1 to node j. Next let (j) = -d(j) And compute c

19 Reduced costs in the residual network The reduced costs in G(x*) for the optimal flow x* are all non-negative.