Warm-up… EXPLAIN HOW THE ICE CREAM LAB WORKS

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Presentation transcript:

Warm-up… EXPLAIN HOW THE ICE CREAM LAB WORKS What does the salt do (collig. Pro and temp gap) How does the ice melt– explain the heat movement

Calorimetry CP Unit 9 Chapter 17

CALORIMETRY The enthalpy change associated with a chemical reaction or process can be determined experimentally. Measure the heat gained or lost during a reaction at CONSTANT pressure

Calorimeter Device used to measure the heat absorbed or released during a chemical or physical process Styrofoam cup

Example If you leave your keys and your chemistry book sitting in the sun on a hot summer day, which one is hotter? Why is there a difference in temperature between the two objects?

Because… Different substances have different specific heats (amount of energy needed to raise the temperature of 1 g of a substance by 1 degree Celsius).

Need to know how to calc. heat (review) Heat (q) = mCT If the specific heat of Al is 0.90 J/gC, how much heat is required to raise the temperature of 10,000 g of Al from 25.0 C to 30.0 C? HIDDEN

Calculator says 45,000 J BUT 1 sig fig… HIDDEN

For example (review): HIDDEN If 418 J is required to increase the temperature of 50.0 g of water by 2.0 C, what is the specific heat of water? HIDDEN

What happens in a calorimeter One object will LOSE heat, and the other will ABSORB the heat System loses heat to surroundings = EXO = -q System absorbs heat from surroundings = ENDO = +q When a hot chunk of metal is dropped in a cool glass of water, the metal cools off. Where did the heat from the metal go? Did the metal lose more heat then the water gained? HEAT GAINED = HEAT LOST (ALWAYS!)

To do calorimetry problems… The numbers in these two boxes are always the same, but with different signs (+/-). What heat one lost, the other gained. Make a Chart: Water Object/Reaction Heat Mass Specific Heat 4.184 Final Temp Initial Temp

EXAMPLE: A small pebble is heated and placed in a foam cup calorimeter containing 25.0 g of water at 25.0 C. The water reaches a maximum temperature of 26.4 C. How many joules of heat were released by the pebble? The specific heat of water is 4.184 J/g C. (#13) Water Pebble Heat Mass Specific Heat 4.184 Final Temp Initial Temp The numbers in these two boxes are always the same, but with different signs (+/-). What heat one lost, the other gained. 25.0 g 26.4 oC 25.0 oC

The pebble because the water heated up from 25.0 C to 26.4 C. Pebble loses heat (-q, exothermic) while water gains heat (+q, endothermic) Do you calculation based on water (since the problem gave all the water’s information) 

Water Pebble Heat Mass Specific Heat 4.184 Final Temp Initial Temp 25.0 g 26.4 oC 25.0 oC qwater = mwatercwaterTwater qwater = (25.0g)(4.184J/goC)(26.4oC-25.0oC) qwater = 150 J If the water ABSORBED 150 J of heat, then the pebble _______ ______ J of heat. qpebble = - 150 J

Example 2 (LAB type of CALC) Suppose that 100.00 g of water at 22.4 °C is placed in a calorimeter. A 75.25 g sample of Al is removed from boiling water at a temperature of 99.3 °C and quickly placed in a calorimeter. The substances reach a final temperature of 32.9 °C . Determine the SPECIFIC HEAT of the metal.The specific heat of water is 4.184 J/g C.  MAKE YOUR CHART

Suppose that 100. 00 g of water at 22. 4 °C is placed in a calorimeter Suppose that 100.00 g of water at 22.4 °C is placed in a calorimeter. A 75.25 g sample of Al is removed from boiling water at a temperature of 99.3 °C and quickly placed in a calorimeter. The substances reach a final temperature of 32.9 °C . Determine the SPECIFIC HEAT of the metal.The specific heat of water is 4.184 J/g C. Make chart Calculate q for water Q for water is the same (but with different sign) as q for metal. Using q metal, calculate c metal Water Pebble Heat Mass Specific Heat 4.184 Final Temp Initial Temp 100.00 g 75.25 g 32.9 oC 32.9 oC 22.4 oC 99.3 oC

0.879 J/g °C

Example 3 A lead mass is heated and placed in a foam cup calorimeter containing 40.0 g of water at 17C. The water reaches a temperature of 20.0 C. How many joules of heat were released by the lead? The specific heat of water is 4.184 J/g C.

502 J = 5.0 x 102 J for 2 sig figs