What does the little number below each

Slides:



Advertisements
Similar presentations
Lecture 0302 Molecular Wt. % Composition and Elemental Analysis
Advertisements

Stoichiometry “In solving a problem of this sort, the grand thing is to be able to reason backward. This is a very useful accomplishment, and a very easy.
Chapter 7- Molecular Formulas
Use of Formulae Masses and Moles (but no badgers).
Stoichiometry: Basic Concepts
Chapter 9 Chemical Quantities.
Chemical Quantities or
Chemistry, The Central Science, 10th edition
Stoichiometry: The study of quantitative measurements in chemical formulas and reactions Chemistry – Mrs. Cameron.
Atomic Mass Atoms are so small, it is difficult to discuss how much they weigh in grams Use atomic mass units. an atomic mass unit (amu) is one twelfth.
HOLD UP YOUR BOARD! Chapter 7 Review game.
Chapter 7 Chemical Quantities
What is the % composition of carbon in benzene (C6H6)?
From percentage to formula
Chapter 12 “Stoichiometry”
Chemical Quantities The Mole.
AP Notes Chapter 4 Stoichiometry.
AP Chemistry Chapter 3 Chemical Quantities (The Mole)
Mass Relationships in Chemical Reactions
Stoichiometry: Calculations with Chemical Formulas and Equations
Mass Relationships in Chemical Reactions
Lecture Presentation Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations LO 1.17, 1.18, 3.1, 3.5, 1.4, 3.3, 1.2, 1.3 Ashley Warren.
Percent Composition Percent = part / whole Example: MgO
HKCEE Chemistry Volumetric Analysis &
Molar Conversions (p.80-85, )
IIIIIIIV Ch. 10 – The Mole I. Molar Conversions A. What is the Mole? n A counting number (like a dozen) n Avogadros number (N A ) n 1 mole =
Topic 16 Access Code: EC787C089C.
Chemical Quantities or
Unit 4 – The Mole Honors Chemistry Part 1.
Unit 6 Chapter 12 Chemical Quantities or
Chemical Stoichiometry
Formulas and Percent Composition
The Mole Chapter 6.
Chapter 9 Calculations from Chemical Equations
Calculations with Elements and Compounds
Stoichiometry.
MOLAR MASS The molar mass is the mass, in grams, of one mole (6.02  1023 particles) of an element (ion), a covalent molecule or a formula unit. molar.
Molar mass, percent composition, empirical and molecular formulas
Thursday, April 7th : “A” Day Friday, April 8th: “A” Day Agenda
The mole.
% Composition, Empirical and Molecular Formulas
Unit 11 Stoichiometry CP Chemistry.
Love, Life and Stoichiometry
Chemistry, The Central Science, 10th edition
Honors Chemistry Unit 7: Moles & Formulas Do Now Exercises
The Mole.
Stoichiometry.
EMPIRICAL FORMULA The empirical formula represents the smallest ratio of atoms present in a compound. The molecular formula gives the total number of atoms.
All Roads Lead to the Mole
Avogadro and the Mole.
How Scientists Determine Formulas
Please pick up the materials in the front and take a seat
Mass Relationship in Chemical Reaction
Mass Relationships in Chemical Reactions
Stoichiometry A measure of the quantities consumed and produced in chemical reactions.
Atomic Mass l Atoms are so small, it is difficult to discuss how much they weigh in grams. l Use atomic mass units. l an atomic mass unit (amu) is one.
Stoichiometry © 2009, Prentice-Hall, Inc. Warmup – Mass Percent Find the percent by mass: 1.What is the mass % of silver in silver nitrate? (63.5%) 2.
Finding Theoretical Yield and Percent Yield
Chapter 3 – Stoichiometry: Calculations with Chemical Formulas and Equations Jennie L. Borders.
Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations.
Atomic Mass l Atoms are so small, it is difficult to discuss how much they weigh in grams. l Use atomic mass units. l an atomic mass unit (amu) is one.
Empirical Formulas. Empirical formula tells the relative number of atoms of each element in a compound Mole concept provides a way of calculating the.
Choose Your Category The MoleAverage Atomic Mass and Molar Mass FormulasPercentage Composition Limiting Reactants Percentage Yield and Error Vocab 100.
Conversion Factors Molar mass Molar mass atomic mass in g = 1 mole atomic mass in g = 1 mole Volume of gas at STP Volume of gas at STP 1 mole gas = 22.4L.
Chapter 12 Review “Stoichiometry”
Mass % and % Composition Mass % = grams of element grams of compound X 100 % 8.20 g of Mg combines with 5.40 g of O to form a compound. What is the mass.
Chapter 3 sample problems. Average atomic mass Calculate the average atomic mass of magnesium given the following isotopic mass and mass percent data.
The Mole & Stoichiometry!
Mass % and % Composition Mass % = grams of element grams of compound X 100 % 8.20 g of Mg combines with 5.40 g of O to form a compound. What is the mass.
H.W. # 7 Study pp Ans. ques. p. 189 # 33, 34 p. 190 # 37,40,42
Presentation transcript:

What does the little number below each Element mean? What are its’ units? amu/atom

one amu is defined as 1/12th What is an amu one amu is defined as 1/12th of 12C

Average atomic mass or atomic weight is determined by a mass spectroscope. example: Analysis of a sample of carbon was found to have the following isotopes 12C – 11.999 97.3% 13C – 12.998 2.6% 14C – 13.966 0.10% What is the atomic weight of Carbon

12C – (11.999) (.973) = 11.675 13C – (12.998) (.026) = .33795 14C – (13.966) (.0010) = .013966 12.0269

How high could you stack a mole of sheets of paper? How much is a mole? How high could you stack a mole of sheets of paper?

How much would a mole of iron weigh? Could you lift it? Look on the back inside cover for amu and mole 6.02214 x 1023 atoms of Fe 55.85 amu 1.66054 x 10-24 g* =55.85 g 1atom of Fe 1 amu

What is the Mole? One mole is equal to the number of carbon atoms in exactly 12.00 grams of C-12: 6.02 x 1023 atoms

The Shopping Mole x g/ mole 22.4 L / mole # of atoms or molecules 6.02 x 10 23 atoms or molecules/mole Mole x g/ mole 22.4 L / mole Mass of atom or molecule volume of gas The Shopping Mole

Calculate the numbers of atoms of cesium found in 3.57 moles of cesium Calculate the numbers of atoms of cesium found in 3.57grams of cesium Calculate the mass of 4.82 x 1023 atoms of cesium

1. Calculate the mass of 4.65 moles of (NH4)2S Calculating the molar mass of a compound (NH4)2S 1. Calculate the mass of 4.65 moles of (NH4)2S 2. Calculate the numbers of atoms of nitrogen found in 3.57grams (NH4)2S 3. Calculate the mass of nitrogen in 3.76 x 1024 formula units of (NH4)2S

Determining Percent Composition of Compounds Given the compound: Al(HPO3)3 What are the percent compositions of each of the atoms from which the above compound is constructed? Mass of Aluminum= 1 mol Al 26.9 grams = 26.9g Al mole of Al Mass of hydrogen = 3 mols H 1.01 gram = 3.03 H mole of H 266 g Al(HPO3)3 Mass of Phosphorus = 3 mols P 30.9 gram = 92.7 g P mole of P Mass of oxygen = 9 mols O 16.0 gram = 144 g O mole of P

10.1% Mass percent of Al: 1.13% Mass percent of H: 34.8% mass of Al 26.9 g 10.1% = x 100 = Mass percent of Al: mass of Al(HPO3)3 266 g mass of H 3.03 g x 100 1.13% = Mass percent of H: = mass of Al(HPO3)3 266 g mass of P 92.7 g 34.8% x 100 Mass percent of P: = = mass of Al(HPO3)3 266 g mass of O 54.1% 144 g = = x 100 Mass percent of O: 266 g mass of Al(HPO3)3

Empirical formula A compound is composed of Cl 71.65% and C 24.27% and H 4.07% what is the empirical formula? The Molar mass is 98.96g/mole, what is the molecular formula?

0.255 g isopropyl alcohol is combusted Determining the Empirical Formula of a Compound Using Combustion Analysis Combustion Analysis 0.255 g isopropyl alcohol is combusted mass difference of H2O absorber = 0.306 g mass difference of CO2 absorber = 0.561 g

mass difference of H2O absorber = 0.306 g mass difference of CO2 absorber = 0.561 g 1 mole CO2 12 g C grams of C: 0.561 g CO2 = 0.153g C 44 g CO2 1 mole CO2 1 mole H2O 2.02 g H grams of H: 0.306 g H2O = 0.0343 g H 18 g H2O 1 mole H2O grams of O: 0.255 g - 0.153 g - 0.0343 g H = 0.0677 g

Assume that the empirical formula for the compound is C3H8O 1 mol C 1 C: 0.153 g C = 2.97 = 0.0128 mol C 12 g C 0.0043 1 mol H 1 H: 0.0343 g H = 7.91 = 0.0340 mol C 0.0043 1.01 g H 1 1 mol O O: 0.0677 g O = 1.00 = 0.0043 mol O 0.0043 16 g O Assume that the empirical formula for the compound is C3H8O

Ascorbic acid (Vitamin C) contains 40. 92 percent C, 4 Ascorbic acid (Vitamin C) contains 40.92 percent C, 4.58 percent H, and 54.50 percent O by mass. What is the empirical formula of ascorbic acid? Ethylene glycol, the substance used in automobile antifreeze, is composed of 48.7 % C, 9.7 percent H, and 51.6 percent O by mass. Its molar mass is 62.1 g/mol. (a) What is the empirical formula of ethylene glycol? (b) What is the molecular formula

So What is Stoichiometry? mass of A in g mole 3(moles C) C g = mass C A g 1(moles A) mole 1A + 2B → 3C + 4D

Na2SO3(aq) + 2AgNO3(aq)  Ag2SO3(s) + 2NaNO3(aq) If 3.4 g of silver nitrate is mixed w/ excess sodium sulfite, what would be the theoretical yield for silver sulfite? in moles in formula units in L at STP in grams

Na2SO3(aq) + 2AgNO3(aq)  Ag2SO3(s) + 2NaNO3(aq) If 3.4 g of silver nitrate is mixed sodium sulfite, how many grams of sodium sulfite would you need to react completely?

Na2SO3(aq) + 2AgNO3(aq)  Ag2SO3(s) + 2NaNO3(aq) If 4.5 g of sodium sulfite is mixed w/ excess silver nitrate, what would be the theoretical yield for silver sulfite? What would be the percent yield if 4.1g was produced in the lab?

Na2SO3(aq) + 2AgNO3(aq)  Ag2SO3(s) + 2NaNO3(aq) If 4.3 g of silver nitrate is mixed w/ 3.2g sodium sulfite, what would be the theoretical yield for silver sulfite? How much of the excess reagent is left over?

Using Stoichiometry in the Laboratory Na2SO3(aq) + 2AgNO3(aq)  Ag2SO3(s) + 2NaNO3(aq) 20 ml 0.12 M 20 ml 0.35 M 1. How many grams of silver sulfite would be produced? 2. What would be the molarity of the sodium nitrate?