Newton-Raphson Method

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Presentation transcript:

Newton-Raphson Method Major: All Engineering Majors Authors: Autar Kaw, Jai Paul http://numericalmethods.eng.usf.edu Transforming Numerical Methods Education for STEM Undergraduates 4/22/2017 http://numericalmethods.eng.usf.edu

Newton-Raphson Method http://numericalmethods.eng.usf.edu

Newton-Raphson Method Figure 1 Geometrical illustration of the Newton-Raphson method. 3 http://numericalmethods.eng.usf.edu

Derivation Figure 2 Derivation of the Newton-Raphson method. http://numericalmethods.eng.usf.edu

Algorithm for Newton-Raphson Method http://numericalmethods.eng.usf.edu

Step 1 Evaluate symbolically. 6 http://numericalmethods.eng.usf.edu

Step 2 Use an initial guess of the root, , to estimate the new value of the root, , as 7 http://numericalmethods.eng.usf.edu

Find the absolute relative approximate error as Step 3 Find the absolute relative approximate error as 8 http://numericalmethods.eng.usf.edu

Go to Step 2 using new estimate of the root. Compare the absolute relative approximate error with the pre-specified relative error tolerance . Also, check if the number of iterations has exceeded the maximum number of iterations allowed. If so, one needs to terminate the algorithm and notify the user. Go to Step 2 using new estimate of the root. Yes Is ? No Stop the algorithm 9 http://numericalmethods.eng.usf.edu

Example 1 You are working for ‘DOWN THE TOILET COMPANY’ that makes floats for ABC commodes. The floating ball has a specific gravity of 0.6 and has a radius of 5.5 cm. You are asked to find the depth to which the ball is submerged when floating in water. Figure 3 Floating ball problem. 10 http://numericalmethods.eng.usf.edu

Example 1 Cont. The equation that gives the depth x in meters to which the ball is submerged under water is given by Figure 3 Floating ball problem. Use the Newton’s method of finding roots of equations to find the depth ‘x’ to which the ball is submerged under water. Conduct three iterations to estimate the root of the above equation. The absolute relative approximate error at the end of each iteration, and The number of significant digits at least correct at the end of each iteration. 11 http://numericalmethods.eng.usf.edu

Example 1 Cont. Solution To aid in the understanding of how this method works to find the root of an equation, the graph of f(x) is shown to the right, where Figure 4 Graph of the function f(x) http://numericalmethods.eng.usf.edu

Example 1 Cont. Solve for Let us assume the initial guess of the root of is . This is a reasonable guess (discuss why and are not good choices) as the extreme values of the depth x would be 0 and the diameter (0.11 m) of the ball. http://numericalmethods.eng.usf.edu

Example 1 Cont. Iteration 1 The estimate of the root is http://numericalmethods.eng.usf.edu

Example 1 Cont. Figure 5 Estimate of the root for the first iteration. http://numericalmethods.eng.usf.edu

Example 1 Cont. The absolute relative approximate error at the end of Iteration 1 is The number of significant digits at least correct is 0, as you need an absolute relative approximate error of 5% or less for at least one significant digits to be correct in your result. http://numericalmethods.eng.usf.edu

Example 1 Cont. Iteration 2 The estimate of the root is http://numericalmethods.eng.usf.edu

Example 1 Cont. Figure 6 Estimate of the root for the Iteration 2. http://numericalmethods.eng.usf.edu

Example 1 Cont. The absolute relative approximate error at the end of Iteration 2 is The maximum value of m for which is 2.844. Hence, the number of significant digits at least correct in the answer is 2. http://numericalmethods.eng.usf.edu

Example 1 Cont. Iteration 3 The estimate of the root is http://numericalmethods.eng.usf.edu

Example 1 Cont. Figure 7 Estimate of the root for the Iteration 3. http://numericalmethods.eng.usf.edu

Example 1 Cont. The absolute relative approximate error at the end of Iteration 3 is The number of significant digits at least correct is 4, as only 4 significant digits are carried through all the calculations. http://numericalmethods.eng.usf.edu

Advantages and Drawbacks of Newton Raphson Method http://numericalmethods.eng.usf.edu

Advantages Converges fast (quadratic convergence), if it converges. Requires only one guess http://numericalmethods.eng.usf.edu

Drawbacks Divergence at inflection points Selection of the initial guess or an iteration value of the root that is close to the inflection point of the function may start diverging away from the root in ther Newton-Raphson method. For example, to find the root of the equation . The Newton-Raphson method reduces to . Table 1 shows the iterated values of the root of the equation. The root starts to diverge at Iteration 6 because the previous estimate of 0.92589 is close to the inflection point of . Eventually after 12 more iterations the root converges to the exact value of http://numericalmethods.eng.usf.edu

Drawbacks – Inflection Points Table 1 Divergence near inflection point. Iteration Number xi 5.0000 1 3.6560 2 2.7465 3 2.1084 4 1.6000 5 0.92589 6 −30.119 7 −19.746 18 0.2000 Figure 8 Divergence at inflection point for http://numericalmethods.eng.usf.edu

Drawbacks – Division by Zero For the equation the Newton-Raphson method reduces to For , the denominator will equal zero. Figure 9 Pitfall of division by zero or near a zero number http://numericalmethods.eng.usf.edu

Drawbacks – Oscillations near local maximum and minimum Results obtained from the Newton-Raphson method may oscillate about the local maximum or minimum without converging on a root but converging on the local maximum or minimum. Eventually, it may lead to division by a number close to zero and may diverge. For example for the equation has no real roots. http://numericalmethods.eng.usf.edu

Drawbacks – Oscillations near local maximum and minimum Table 3 Oscillations near local maxima and mimima in Newton-Raphson method. Iteration Number 1 2 3 4 5 6 7 8 9 –1.0000 0.5 –1.75 –0.30357 3.1423 1.2529 –0.17166 5.7395 2.6955 0.97678 3.00 2.25 5.063 2.092 11.874 3.570 2.029 34.942 9.266 2.954 300.00 128.571 476.47 109.66 150.80 829.88 102.99 112.93 175.96 Figure 10 Oscillations around local minima for . http://numericalmethods.eng.usf.edu

Drawbacks – Root Jumping In some cases where the function is oscillating and has a number of roots, one may choose an initial guess close to a root. However, the guesses may jump and converge to some other root. For example Choose It will converge to instead of Figure 11 Root jumping from intended location of root for . http://numericalmethods.eng.usf.edu

Additional Resources For all resources on this topic such as digital audiovisual lectures, primers, textbook chapters, multiple-choice tests, worksheets in MATLAB, MATHEMATICA, MathCad and MAPLE, blogs, related physical problems, please visit http://numericalmethods.eng.usf.edu/topics/newton_raphson.html

THE END http://numericalmethods.eng.usf.edu