Review of Chapters 20, 26, 27

Hint: Be able to do the homework (both the problems to turn in AND the recommended ones) you’ll do fine on the exam! Monday, May 10, :30am - 11:20am Chs. 20, 26, and 27 You may bring one 3”X5” index card (hand-written on both sides), a pencil or pen, and a scientific calculator with you. Same format!

Hint: Review notes from my review lectures! Try to do some of the old homework recommended homework, and exam problems. Monday, May 10, :30am - 12:30pm everything we’ve covered You may bring one 8.5”X11” sheet (hand-written on both sides), a pencil or pen, and a scientific calculator with you.

Monday, December 15, :30am - 12:30pm everything we’ve covered Format: 5 problems, 1 multiple-choice, pick 4. 1 problem on each of the following topics: ElectrostaticsCircuitsMagnetism Optics Modern

Magnetic Flux Induced EMF Motional EMF Inductance Wien’s Law Photoelectric Effect Heisenberg Uncertainty Principle de Broglie Wavelength Length Contraction Time Dilation Relativistic Energy Relativistic Momentum Rest Energy Michelson-Morley Exp. Magnetic Flux Induced EMF Motional EMF Inductance Wien’s Law Photoelectric Effect Heisenberg Uncertainty Principle de Broglie Wavelength Length Contraction Time Dilation Relativistic Energy Relativistic Momentum Rest Energy Michelson-Morley Exp.

30 o 60 o top view B tot  This is also the direction of the normal to the loop!

The induced current tries to maintain the original flux through the circuit. The polarity of the induced emf is such that it produces a current whose magnetic field opposes the change in magnetic flux through the loop. Emf!

A I S N L is the inductance and is defined to be FOR A SOLENOID!!!! B =  o n I

V R + _ L  = the time constant = L / R

x x x x x x x x x x x L v F+F+ F-F- F E = F B F E = q E F B = q v B E = v B |V| = E d = B L v x x x x x x R L v I

Increasing Temperature max

V + _ V A A C evacuated chamber High intensity Low intensity Stopping potential Applied Voltage Current frequency fcfc stopping potential Cut-off frequency

energy of the incident light The work function: Energy required to escape the metal. Characteristic of the metal! Explains the photoelectric effect Explains the photoelectric effect Where V 0 is the stopping potential and KE max is the maximum kinetic energy of the emitted electrons KE max = e V o Photoelectric effect, light acts like particle. Einstein says photons carry energy given by E = h f

If light does act as a particle, it should carry momentum…(and using relativity, we can derive the momentum of a photon of light) de Broglie’s hypothesis was that any particle with momentum p should also exhibit wave properties with characteristic wavelength... Here, p is the momentum and c the speed of light. Recalling that E = hf, we find that

GM R/R Physics Rules u S The “lab” frame. It’s the one “at rest.” S’ u the moving frame Moves with a velocity u relative to frame S.

The world BEFORE Einstein... x’ = x - ut Positions of stationary objects y’ = yz’ = z t’ = t Time is the same in both frames... v’ = v - u An object moving with velocity v in the lab frame appears to move with velocity v’ in a frame which moves with velocity u

1) absolute, uniform motion cannot be detected Einstein’s Assumptions 2) c always is 3 X 10 8 m/s in vacuum y’ = yz’ = z Absolute time on clocks (NOT the duration of events). This will NOT be on the exam.

m 0 is the rest mass (the mass in the frame in which the object is at rest).  t 0 is the proper time (the time between events as measured in the rest frame of the experiment). TIME DILATION LENGTH CONTRACTION LENGTH CONTRACTION L 0 is the proper length (the length measured in the rest frame of the object).

m 0 rest mass L 0 proper length  t 0 proper time m 0 rest mass L 0 proper length  t 0 proper time In the rest frame of the object: In the rest frame of the object: In the lab (where the observer is): In the lab (where the observer is): m mass L length  t time m mass L length  t time

GM R/R Physics Rules u So, whether we sit on the boxcar or stand alongside the tracks, light from the two paths will appear to arrive at the detector simultaneously. Using our relativistic formula for length contraction, we now get  t = 0, as observed. Using our relativistic formula for length contraction, we now get  t = 0, as observed.

where p = m v Kinetic energy: Rest energy: Total energy:

(Total Energy) 2 = (momentum) 2 c 2 +(rest energy) 2 Finally, we can relate Total Energy to Momentum using: