4.3 Intermolecular Forces

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Presentation transcript:

4.3 Intermolecular Forces R. Doon – Slough Grammar School

SIMPLE COVALENT MOLECULES Bonding Atoms are joined together within the molecule by covalent bonds. Electrical Don’t conduct electricity as they have no mobile ions or electrons Solubility Tend to be more soluble in organic solvents than in water; some are hydrolysed Boiling point Low - intermolecular forces (van der Waals’ forces) are weak; they increase as molecules get a larger surface area e.g. CH4 -161°C C2H6 - 88°C C3H8 -42°C as the intermolecular forces are weak, little energy is required to separate molecules from each other so boiling points are low some boiling points are higher than expected for a given mass because you can get additional forces of attraction

INSTANTANEOUS DIPOLE-INDUCED DIPOLE FORCES VAN DER WAALS’ FORCES INSTANTANEOUS DIPOLE-INDUCED DIPOLE FORCES Although the bonding within molecules is strong, that between molecules is weak. Molecules and monatomic noble gases are subject to weak attractive forces. Instantaneous dipole-induced dipole forces Because electrons move quickly in orbitals, their position is constantly changing; at any given instant they could be anywhere in an atom. The possibility will exist that one side will have more electrons than the other. This will give rise to a dipole...

Learning Objectives Describe the types of intermolecular force (hydrogen bond, dipole–dipole attraction and van der Waals’ forces) and explain how they arise from the structural features of molecules. All these intermolecular forces are weaker than covalent bonds. For substances of similar molar mass, hydrogen bonds are stronger than dipole–dipole attractions which are stronger than van der Waals' forces. Van der Waals’ forces arise from the electrostatic attraction between temporary induced dipoles in both polar and non-polar molecules. Describe and explain how intermolecular forces affect the boiling points of substances. The hydrogen bond can be illustrated by comparing physical properties of: H2O and H2S NH3 and PH3 C3H8, CH3CHO and C2H5OH.

VAN DER WAALS’ FORCES INSTANTANEOUS DIPOLE-INDUCED DIPOLE FORCES The dipole on one atom induces dipoles on nearby atoms Atoms are now attracted to each other by a weak forces The greater the number of electrons, the stronger the attraction and the greater the energy needed to separate the particles.

INSTANTANEOUS DIPOLE-INDUCED DIPOLE FORCES VAN DER WAALS’ FORCES INSTANTANEOUS DIPOLE-INDUCED DIPOLE FORCES NOBLE GASES Electrons B pt. He 2 -269°C Ne 10 -246°C Ar 18 -186°C Kr 36 -152°C ALKANES Electrons B pt. CH4 10 -161°C C2H6 18 - 88°C C3H8 26 - 42°C

ELECTRONEGATIVITY “The ability of an atom to attract the pair of electrons in a covalent bond to itself.” Non-polar bond similar atoms have the same electronegativity they will both pull on the electrons to the same extent the electrons will be equally shared

ELECTRONEGATIVITY Polar bond Pauling Scale different atoms have different electronegativities one will pull the electron pair closer to its end it will be slightly more negative than average, δ- the other atom will be slightly less negative, or more positive, δ+ a dipole is formed and the bond is said to be polar the greater the electronegativity difference, the greater the polarity Pauling Scale a scale for measuring electronegativity

ELECTRONEGATIVITY Pauling Scale “The ability of an atom to attract the pair of electrons in a covalent bond to itself.” Pauling Scale a scale for measuring electronegativity values increase across periods values decrease down groups fluorine has the highest value H 2.1 Li Be B C N O F 1.0 1.5 2.0 2.5 3.0 3.5 4.0 Na Mg Al Si P S Cl 0.9 1.2 1.5 1.8 2.1 2.5 3.0 K Br 0.8 2.8 INCREASE INCREASE

DIPOLE-DIPOLE INTERACTION Occurrence occurs between molecules containing polar bonds acts in addition to the basic van der Waals’ forces the extra attraction between dipoles means that more energy must be put in to separate molecules get higher boiling points than expected for a given mass

Boiling points of hydrides Mr °C CH4 16 -161 SiH4 32 -117 GeH4 77 -90 SnH4 123 -50 NH3 17 -33 PH3 34 -90 AsH3 78 -55 SbH3 125 -17 Mr °C H2O 18 +100 H2S 34 -61 H2Se 81 -40 H2Te 130 -2 HF 20 +20 HCl 36.5 -85 HBr 81 -69 HI 128 -35

POLAR MOLECULES Occurrence HYDROGEN CHLORIDE TETRACHLOROMETHANE WATER not all molecules containing polar bonds are polar overall if bond dipoles ‘cancel each other out’ the molecule won’t be polar if there is a ‘net dipole’ the molecule will be polar HYDROGEN CHLORIDE TETRACHLOROMETHANE WATER NET DIPOLE - POLAR NON-POLAR NET DIPOLE - POLAR

POLAR MOLECULES Evidence place a liquid in a burette allow it to run out place a charged rod alongside the stream of liquid polar molecules will be attracted by electrostatic attraction non-polar molecules will be unaffected NET DIPOLE - POLAR NON-POLAR

BOILING POINTS OF HYDRIDES Mr °C CH4 16 -161 SiH4 32 -117 GeH4 77 -90 SnH4 123 -50 NH3 17 -33 PH3 34 -90 AsH3 78 -55 SbH3 125 -17 Mr °C H2O 18 +100 H2S 34 -61 H2Se 81 -40 H2Te 130 -2 HF 20 +20 HCl 36.5 -85 HBr 81 -69 HI 128 -35 GROUP IV GROUP VI GROUP V GROUP VII The values of certain hydrides are not typical of the trend you would expect

BOILING POINTS OF HYDRIDES Mr BOILING POINT / C° 100 -160 140 50 GROUP IV The boiling points of the hydrides increase with molecular mass. CH4 has the lowest boiling point as it is the smallest molecule. PbH4 GeH4 SiH4 Larger molecules have greater intermolecular forces and therefore higher boiling points CH4

BOILING POINTS OF HYDRIDES Mr BOILING POINT / C° 100 -160 140 50 GROUP V NH3 has a higher boiling point than expected for its molecular mass. There must be an additional intermolecular force. NH3

BOILING POINTS OF HYDRIDES Mr BOILING POINT / C° 100 -160 140 50 H2O GROUP VI H2O has a very much higher boiling point for its molecular mass. There must be an additional intermolecular force.

BOILING POINTS OF HYDRIDES Mr BOILING POINT / C° 100 -160 140 50 GROUP VII HF has a higher boiling point than expected for its molecular mass. There must be an additional intermolecular force. HF

BOILING POINTS OF HYDRIDES Mr BOILING POINT / C° 100 -160 140 50 H2O The higher than expected boiling points of NH3, H2O and HF are due to intermolecular HYDROGEN BONDING HF NH3 GROUP IV GROUP V GROUP VI GROUP VII

BOILING POINTS OF HYDRIDES Mr BOILING POINT / C° 100 -160 140 50 GROUP IV GROUP V GROUP VI GROUP VII

HYDROGEN BONDING an extension of dipole-dipole interaction gives rise to even higher boiling points bonds between H and the three most electronegative elements, F, O and N are extremely polar because of the small sizes of H, F, N and O the partial charges are concentrated in a small volume thus leading to a high charge density makes the intermolecular attractions greater and leads to even higher boiling points

HYDROGEN BONDING - ICE each water molecule is hydrogen-bonded to 4 others in a tetrahedral formation ice has a “diamond-like” structure volume is larger than the liquid making it when ice melts, the structure collapses slightly and the molecules come closer; they then move a little further apart as they get more energy as they warm up this is why… water has a maximum density at 4°C ice floats. hydrogen bonding

HYDROGEN BONDING - ICE hydrogen bonding

HYDROGEN BONDING - HF d ¯ d ¯ F d + F d + d + d + H H d ¯ d ¯ H H F F hydrogen bonding Hydrogen fluoride has a much higher boiling point than one would expect for a molecule with a relative molecular mass of 20 Fluorine has the highest electronegativity of all and is a small atom so the bonding with hydrogen is extremely polar

DATIVE COVALENT (CO-ORDINATE) BONDING A dative covalent bond differs from covalent bond only in its formation Both electrons of the shared pair are provided by one species (donor) and it shares the electrons with the acceptor Donor species will have lone pairs in their outer shells Acceptor species will be short of their “octet” or maximum. Lewis base a lone pair donor Lewis acid a lone pair acceptor Ammonium ion, NH4+ The lone pair on N is used to share with the hydrogen ion which needs two electrons to fill its outer shell. The N now has a +ive charge as it is now sharing rather than owning two electrons.

Boron trifluoride-ammonia NH3BF3 Boron has an incomplete shell in BF3 and can accept a share of a pair of electrons donated by ammonia. The B becomes -ve as it is now shares a pair of electrons (i.e. it is up one electron) it didn’t have before.