Web search basics (Recap) The Web Web crawler Indexer Search User Indexes Query Engine 1 Ad indexes

Query Engine’s operations Process query Look-up the index (and ad indices) Retrieve list of documents (and ads) Order documents Content relevance Link analysis Popularity Prepare results page Today’s question: Given a large list of documents that match a query, how to order them according to their relevance? 2

Answer: Scoring Documents Given document d, Given query q Calculate score(q,d) Rank documents in decreasing order of score(q,d) “Bag of words” Model: Documents = bag of [unordered] words (in set theory a bag is a multiset) John is quicker than Mary and Mary is quicker than John have the same words A document is composed of terms A query is composed of terms score(q,d) will depend on terms 3

Method 1: Term Frequency tf t,d Assign to each term a weight tf t,d - term frequency (how often term t occurs in document d) query = ‘who wrote wild boys’ doc1 = ‘Duran Duran sang Wild Boys in 1984.’ doc2 = ‘Wild boys don’t remain forever wild.’ doc3 = ‘Who brought wild flowers?’ doc4 = ‘It was John Krakauer who wrote In to the wild.’ query = {boys: 1, who: 1, wild: 1, wrote: 1} doc1 = {1984: 1, boys: 1, duran: 2, in: 1, sang: 1, wild: 1} doc2 = {boys: 1, don’t: 1, forever: 1, remain: 1, wild: 2}… score(q, doc1) = = 2score(q, doc2) = = 3 score(q,doc3) = = 2score(q, doc4) = = 3 4

Why is using just tf t,d is not good? All terms have equal importance. Bigger documents have more terms, thus the score is larger. It ignores term order. Postulate: If a word appears in every document, probably it is not that important (it has no discriminatory power). 5

Method 2: Weights according to rarity Rare terms are more informative than frequent terms Recall stop words Consider a term in the query that is rare in the collection (e.g., arachnocentric) A document containing this term is very likely to be relevant to the query arachnocentric → We want a high weight for rare terms like arachnocentric. df t - document frequency for term t idf t - inverse document frequency for term t Sec N - total number of documents

idf example, suppose N = 1 million termdf t idf t calpurnia1 animal100 sunday1,000 fly10,000 under100,000 the1,000,000 There is one idf value for each term t in a collection. Sec

Effect of idf on ranking Does idf have an effect on ranking for one-term queries, like iPhone idf has no effect on ranking one term queries idf affects the ranking of documents for queries with at least two terms For the query capricious person, idf weighting makes occurrences of capricious count for much more in the final document ranking than occurrences of person. 8

Method 3: Better tf-idf weighting The tf-idf weight of a term is the product of its tf weight and its idf weight. Best known weighting scheme in information retrieval Note: the “-” in tf-idf is a hyphen, not a minus sign! Alternative names: tf.idf, tf x idf Increases with the number of occurrences within a document Increases with the rarity of the term in the collection Sec

Final ranking of documents for a query 10 Sec

Binary → count → weight matrix Each document is now represented by a real-valued vector of tf-idf weights ∈ R |V| Sec. 6.3

Documents are vectors So we have a |V|- dimensional vector space Terms are axes of the space Documents are points or vectors in this space Very high-dimensional: tens of millions of dimensions when you apply this to a web search engine These are very sparse vectors - most entries are zero. Sec. 6.3 t1t1 d2d2 d1d1 d3d3 d4d4 d5d5 t3t3 t2t2 θ φ

Queries are also vectors Key idea 1: Represent queries as vectors in the space Key idea 2: Rank documents according to their proximity to the query in this space proximity = similarity of vectors proximity ≈ inverse of “distance” Recall: We do this because we want to get away from the you’re-either-in-or-out Boolean model. Instead: rank more relevant documents higher than less relevant documents Sec. 6.3

Determine vector space proximity First cut: distance between two points ( = distance between the end points of the two vectors) Euclidean distance? Euclidean distance is a bad idea because Euclidean distance is large for vectors of different lengths. Sec. 6.3 t1t1 d2d2 d1d1 d3d3 d4d4 d5d5 t3t3 t2t2 θ φ

Why Euclidean distance is a bad idea The Euclidean distance between q and d 2 is large even though the distribution of terms in the query q and the distribution of terms in the document d 2 are very similar. Sec. 6.3

Use angle instead of distance Thought experiment: take a document d and append it to itself. Call this document d′. “Semantically” d and d′ have the same content The Euclidean distance between the two documents can be quite large The angle between the two documents is 0, corresponding to maximal similarity. Key idea: Rank documents according to angle with query. Sec. 6.3

From angles to cosines The following two notions are equivalent. Rank documents in decreasing order of the angle between query and document Rank documents in increasing order of cosine(query,document) Cosine is a monotonically decreasing function for the interval [0 o, 180 o ] Sec. 6.3

Length normalization A vector can be (length-) normalized by dividing each of its components by its length – for this we use the L 2 norm: Dividing a vector by its L 2 norm makes it a unit (length) vector (on surface of unit hypersphere) Effect on the two documents d and d′ (d appended to itself) from earlier slide: they have identical vectors after length-normalization. Long and short documents now have comparable weights Sec. 6.3

cosine(query,document) Dot product Unit vectors q i is the tf-idf weight of term i in the query d i is the tf-idf weight of term i in the document cos(q,d) is the cosine similarity of q and d … or, equivalently, the cosine of the angle between q and d. Sec. 6.3

Cosine similarity illustrated 20

Cosine similarity amongst 3 documents termSaSPaPWH affection jealous10711 gossip206 wuthering0038 How similar are the novels SaS: Sense and Sensibility PaP: Pride and Prejudice, and WH: Wuthering Heights? Term frequencies (counts) Sec. 6.3 Note: To simplify this example, we don’t do idf weighting.

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