NEXT Click the ‘NEXT’ button to continue  Today, in Ms. Stechschulte’s 7 th grade class, we will be learning how to solve one-step equations. To navigate.

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Presentation transcript:

NEXT Click the ‘NEXT’ button to continue

 Today, in Ms. Stechschulte’s 7 th grade class, we will be learning how to solve one-step equations. To navigate through this presentation, click on the arrows and buttons at the bottom of the screen. The arrow labeled ‘NEXT’, will take you to the next slide. The arrow labeled ‘BACK’, will take you back to the previous slide. When you get to the Main Menu, click on the first link to begin the lesson. If you need to go back to the previous lessons to clarify concepts, please do so.  Click the arrow below to continue. NEXT

 Your goal is to learn the concept of solving equations so you are successful answering the quiz questions. You must know the concepts well enough to solve two-step equations for tomorrow’s class. When you are finished with the first 2 Lessons, go to Lesson 3 and play the online math games for the remainder of the class period.  Good luck and have fun NEXT BACK

 “An equation is a written statement indicating the equality of two expressions”  It consists of a sequence of symbols that are split into left and right sides joined by an equal sign.  For example, = 6 is an equation. NEXT Left side Right side BACK

* Remember * 2x + 3 = 5 NEXT Coefficient: the number that is in front of the x. This means that 2 and x are multiplied. Variable: the letter you are solving for; it needs to be isolated on one side of the equation. A variable can be any letter. Left sideRight side BACK

Lesson 1: Using adding & subtractingUsing adding & subtracting Lesson 2: Using multiplication & divisionUsing multiplication & division Lesson 3: Online Math GamesOnline Math Games Click on the link for Lesson 1 to begin. When finished with Lesson 1, continue with Lesson 2 then 3.

 Hoop Shoot Hoop Shoot  Equation Buster Equation Buster  Easy Algebra Equations Easy Algebra Equations  Say the ‘2 – steps’: Rags to Riches Say the ‘2 – steps’: Rags to Riches BACK

1 x = x + 1 = 3 To solve an equation you must get x by itself on one side of the equal sign, while keeping the scale balanced NEXT BACK

= x NEXT To get x by itself you have to take away (subtract) 1. However, this will cause the scale to become unbalanced, so you also have to take away 1 from the other side of the equal sign. BACK

1 x = x + 1 = x = 2 NEXT After you subtract 1 from both sides of the equal sign, you are left with x = 2 BACK

NEXT  “Two operations are said to be inverse to each other if one operation undoes the effect of the other operation.”  Addition and Subtraction are inverse operations  Multiplication and Division are inverse operations BACK

NEXT Inverse operations must be used when solving equations. In the previous example we SUBTRACTED to undo the ADDITION to get x by itself. To solve x – 5 = 3, what operation must you use to get x by itself? BACK

MORE EXAMPLES If you said ADDITION you are correct! To undo SUBTRACTION you must ADD. To solve x – 5 = x = 8 Add 5 to both sides to keep the equation balanced. Begin Quiz 1 BACK

1 x = x + 2 = 4 To solve an equation get rid of whatever is with the variable (x). What you do to one side, you must also do to the other side. NEXT 1 1

1 x = x + 2 = 4 Subtract 2 from both sides to keep the scale balanced 11 x = 2 To Quiz 1 NEXT BACK

Since 2 is SUBTRACTED from x, you must ADD 2 to both sides to solve x – 2 = x = 5 Add 2 to both sides to keep the equation balanced. To Quiz 1 NEXT BACK

-1 = 7 + x is the same as saying 7 + x = -1 Since 7 is ADDED to x, you must SUBTRACT 7 from both sides to solve -1 = 7 + x = x x = -8 Subtract 7 from both sides to keep the equation balanced. To Quiz 1 BACK

Question 1: Solve x + 4 = 9 A.A. x = 13 B.B. x = 5 C.C. x = 9 Click on a letter to continue.

Question 2: Solve x – 5 = 2 A.A. x = -3 B.B. x = 2 C.C. x = 7 Click on a letter to continue.

Question 3: Solve – 5 = 4 + x A.A. x = -9 B.B. x = -1 C.C. x = 9 Click on a letter to continue.

Correct!! Nice Work! NEXT

Correct!! Great Job! NEXT

Correct!! Fabulous! NEXT

Incorrect Try Again Let’s look at another example NEXT

1 x = x + 2 = 4 To solve an equation get rid of whatever is with the variable (x). What you do to one side, you must also do to the other side. NEXT 1 1

1 x = x + 2 = 4 Subtract 2 from both sides to keep the scale balanced 11 x = 2 To Quiz 1 BACK

Incorrect Try Again Let’s look at another example NEXT

Since 2 is SUBTRACTED from x, you must ADD 2 to both sides to solve x – 2 = x = 5 Add 2 to both sides to keep the equation balanced. To Quiz 1

Incorrect Try Again Let’s look at another example NEXT

-1 = 7 + x is the same as saying 7 + x = -1 Since 7 is ADDED to x, you must SUBTRACT 7 from both sides to solve -1 = 7 + x = x x = -8 Subtract 7 from both sides to keep the equation balanced. To Quiz 1

What is the inverse operation of MULTIPLICATION? NEXT BACK

The answer is… DIVISION NEXT BACK

What is the inverse operation of DIVISION? NEXT BACK

The answer is… MULTIPLICATION NEXT BACK

When you have an equation with multiplication or division, you will do the inverse operation to solve! NEXT BACK

Since 6 and x are multiplied, to solve, we divide by 6. 6x = 48 6 x = 8 Divide by 6 on both sides to keep the equation balanced. BACK NEXT Reminder: When a number is divided by itself, it equals 1.

Since x is divided by 4, to solve, we multiply by 4. x = 5 4 (4)x = 5(4) 4 x = 20 Multiply by 4 on both sides to keep the equation balanced. To Quiz 2 BACK MORE EXAMPLES

The inverse operation of MULTIPLICATION is DIVISION, so we divide by x = x = 3 Divide by 10 on both sides to keep the equation balanced. NEXT To Quiz 2 BACK

The inverse operation of DIVISION is MULTIPLICATION, so we multiply by -5. x = 3 -5 (-5)x = 3(-5) -5 x = -15 Multiply by -5 on both sides to keep the equation balanced. NEXT To Quiz 2 ** Remember: Negative times a positive = negative BACK

The inverse operation of MULTIPLICATION is DIVISION, so we divide by x = x = 5 Divide by -2 on both sides to keep the equation balanced. To Quiz 2 ** Remember: Negative times a negative = positive BACK

Question 1: Solve 5x = 35 A.A. x = 175 B.B. x = 30 C.C. x = 7 Click on a letter to continue.

Incorrect Try Again Let’s look at another example NEXT

Correct!! Super! NEXT

Question 2: Solve x = 4 -2 A.A. x = -8 B.B. x = 6 C.C. x = -2 Click on a letter to continue.

Incorrect Try Again Let’s look at another example NEXT

Correct!! Fantastic! NEXT

Question 3: Solve -3x = 6 A.A. x = 2 B.B. x = -2 C.C. x = -18 Click on a letter to continue.

Incorrect Try Again Let’s look at another example NEXT

Correct!! Great Job! NEXT

The inverse operation of MULTIPLICATION is DIVISION, so we divide by x = x = 3 Divide by 10 on both sides to keep the equation balanced. To Quiz 2

The inverse operation of DIVISION is MULTIPLICATION, so we multiply by -5. x = 3 -5 (-5)x = 3(-5) -5 x = -15 Multiply by -5 on both sides to keep the equation balanced. To Quiz 2 ** Remember: Negative times a positive = negative

The inverse operation of MULTIPLICATION is DIVISION, so we divide by x = x = 5 Divide by -2 on both sides to keep the equation balanced. To Quiz 2 ** Remember: Negative times a negative = positive