Chem. 31 – 2/25 Lecture. Announcements I Exam 1 –On Monday (3/2) –Will Cover the parts we have covered in Ch. 1, 3 and 4 plus parts of Ch. 6 (through.

Slides:



Advertisements
Similar presentations
Notes: Equilibrium: Le Châtelier’s Principle (18.1 & 18.2)
Advertisements

Applications of Aqueous Equilibria Chapter 15. Common Ion Effect Calculations Calculate the pH and the percent dissociation of a.200M HC 2 H 3 O 2 (K.
Chapter 19 - Neutralization
CHAPTER 14 CHEMICAL EQUILIBRIUM
Chemical Equilibrium CHAPTER 15
Chem. 31 – 2/23 Lecture. Announcements I Exam 1 –Next Monday (3/2) –Will Cover the parts we have covered in Ch. 1, 3 and 4 plus parts of Ch. 6 (through.
Chem. 31 – 3/16 Lecture. Announcements I More on Additional Problem + Quiz –When stoichiometry is the same, K sp gives solubility (e.g. K sp (AgCl) =
Equilibrium PhaseSolutionChemical. Reversible Reactions a number of chemical reactions have a ΔH and ΔS that are both positive or both negative; one force.
1 Solubility Equilibria Solubility Product Constant K sp for saturated solutions at equilibrium.
Ch 18: Chemical Equilibrium
Some reactions do not go to completion as we have assumed They may be reversible – a reaction in which the conversion of reactants to products and the.
Announcements Homework – Chapter 4 8, 11, 13, 17, 19, 22 Chapter 6 6, 9, 14, 15 Exam Next Thursday.
The K sp of chromium (III) iodate in water is 5.0 x Estimate the molar solubility of the compound. Cr(IO 3 ) 3 (s)  Cr 3+ (aq) + 3 IO 3 - (aq)
Copyright McGraw-Hill Chapter 17 Acid-Base Equilibria and Solubility Equilibria Insert picture from First page of chapter.
CH 18: CHEMICAL EQUILIBRIUM. SECTION 18.2 SHIFTING EQUILIBRIUM.
1 Salt Solubility Chapter Solubility product constant K sp K sp Unitless Unitless CaF 2(s)  Ca 2+ (aq) + 2F - (aq) CaF 2(s)  Ca 2+ (aq) + 2F -
Unless otherwise stated, all images in this file have been reproduced from: Blackman, Bottle, Schmid, Mocerino and Wille, Chemistry, 2007 (John Wiley)
Strong Acid-Base Titrations Chapter 17. Neutralization Reactions Review Generally, when solutions of an acid and a base are combined, the products are.
Chem. 31 – 2/18 Lecture. Announcements Turn in AP1.2 Quiz today Exam 1 coming up (1 week from next Monday) Today’s Lecture –Chapter 4 Material Calibration.
Ch. 16: Ionic Equilibria Buffer Solution An acid/base equilibrium system that is capable of maintaining a relatively constant pH even if a small amount.
Chem. 31 – 2/2 Lecture. Announcements Due Wednesday –Turn in corrected diagnostic quiz –HW Set 1.1 – just additional problem Quiz on Wednesday (covering.
CHM 112 Summer 2007 M. Prushan Acid-Base Equilibria and Solubility Equilibria Chapter 16.
Chapter 16: Applications of Aqueous Equilibria Renee Y. Becker Valencia Community College 1.
Additional Aspects of Aqueous Equilibria BLB 11 th Chapter 17.
Buffered Solutions (sections 1-2) Acid/Base Reactions & Titration Curves (3) Solubility Equilibria (sections 4-5) Two important points: 1. Reactions with.
1 Solutions Chapter Solutions Solutions are homogeneous mixtures Solute is the dissolved substance –Seems to “disappear” or “Takes on the state”
Daniel L. Reger Scott R. Goode David W. Ball Chapter 14 Chemical Equilibrium.
Solutions Solubility -the amount of solute that can be dissolved to form a solution. Solvent – the substance in a solution present in the greatest amount.
Copyright©2004 by Houghton Mifflin Company. All rights reserved. 1 Introductory Chemistry: A Foundation FIFTH EDITION by Steven S. Zumdahl University of.
Le Châtelier’s principle. The significance of Kc values If Kc is small (0.001 or lower), [products] must be small, thus forward reaction is weak If Kc.
Equilibrium SCH4U organic photochromic molecules respond to the UV light.
Updates Assignment 06 is due Mon., March 12 (in class) Midterm 2 is Thurs., March 15 and will cover Chapters 16 & 17 –Huggins 10, 7-8pm –For conflicts:
Friday, March 21 st : “A” Day Monday, March 24 th : “B” Day Agenda  Homework questions/collect  Finish section 14.2: “Systems At Equilibrium”  Homework:
Additional Aqueous Equilibria CHAPTER 16
Announcements Homework – Chapter 4 8, 11, 13, 17, 19, 22 Chapter 6 6, 9, 14, 15 Exam Thursday.
Acid-Base Equilibria and Solubility Equilibria Chapter 16 Dr. Ali Bumajdad.
Chem. 31 – 3/4 Lecture. Announcements I Exam 1 –Still Grading –Key Posted Next Lab Report Due: Cl lab report –Due next Wednesday –Must turn in in Excel.
Prepared by PhD Halina Falfushynska 1 Lecture 7. Electrolytes. Reactions in Aqueous Solutions.
Chem. 31 – 3/11 Lecture. Announcements I Exam 1 –Grading error on p. 3 (problem 4); was graded as though 10 pts for entire problem – not just part a)
Chem. 1B – 9/10 Lecture. Announcements Mastering Chemistry Online Homework for Ch. 14 due Tuesday (we still need to cover use of Q to predict reactions.
Ch. 15: Applications of Aqueous Equilibria 15.6: Solubility Equilibria and Solubility Products.
02/24/10 Lecture. Announcements Corrections to Monday’s Powerpoint Lecture Slides Posted (Slides 3, 9 and 15) I have posted last semester’s Exam 1 plus.
Le Chatelier’s Principle
Chem. 1B – 9/29 Lecture. Announcements I Exam 1 –On Oct. 1 – here except for Sect. 7 students (in Sequoia 426) –Will Need Scantron Form SC982-E (blue.
Copyright©2000 by Houghton Mifflin Company. All rights reserved. 1 Chemistry FIFTH EDITION by Steven S. Zumdahl University of Illinois Chapter 15 Applications.
Chemical Systems & Equilibrium
Chem. 1B – 10/8 Lecture. Announcements I Lab –Quiz 5 next Monday and Tuesday – Topics: titrations, solubility and experiments 3 and 4 –Experiment 4 –
1 Solubility Equilibria Dissolution M m X x (s)  m M n+ (aq) + x X y- (aq) Precipitation m M n+ (aq) + x X y- (aq)  M m X x (s) For a dissolution process,
By Steven S. Zumdahl & Don J. DeCoste University of Illinois Introductory Chemistry: A Foundation, 6 th Ed. Introductory Chemistry, 6 th Ed. Basic Chemistry,
Recall that the chemical and physical properties
Ch 17: Additional Aspects of Aqueous Equilibria Brown, LeMay Ch 17 AP Chemistry.
Chem. 1B – 10/27 Lecture. Announcements I Exam 2 –Thurs. (10/29) –Will cover: Ch. 16 (Titrations, Solubility, Complex Ions), Ch. 17 (all sections) –Similar.
Complex Ion Equilibria and Solubility A complex ion can increase the solubility of a salt. Ag + (aq) + 2 NH 3 (aq) Ag(NH 3 ) 2 + (aq) K f = [Ag(NH.
Ch. 15: Applications of Aqueous Equilibria 15.4 Titrations and pH curves.
Chem. 1B – 10/15 Lecture. Announcements I Exam 2: Two Weeks from Today (10/29) Lab: Experiment 4 Report – due Mon./Tues. Today’s Lecture –Complex Ion.
Ch 18: Chemical Equilibrium. Section 18.2 Shifting Equilibrium.
…concentrations are ________ constant …forward and reverse rates are ________ equal At Equilibrium…
Chem. 1B – 10/13 Lecture. Announcements I Lab –Starting Wednesday: Experiment 5 (Acids/Bases and Buffers) –Report for Lab #3 due Mastering Assignments.
CHE1102, Chapter 17 Learn, 1 Chapter 17 Solubility and Simultaneous Equilibria.
Kinetics, Thermodynamics and Equilibrium Regents Chemistry.
Solutions, Solubility Rules, and Molarity. Solutions Solutions are defined as homogeneous mixtures of two or more pure substances. Aqueous solution –
Solutions - Quantitatively. Solutions Mixture of at least two components Mixture of at least two components Solute Solute Solvent Solvent Components can.
Chem. 1B – 9/13 Lecture. Announcements First Mastering Homework due Tonight Starting Lab #7 on Wednesday Today’s Lecture – cont. –Le Châtelier’s Principle.
Chem. 1B – 9/6 Lecture. Announcements 2 nd Quiz (and all future quizzes) will be on Monday and Tuesday in lab First Mastering Homework due Tuesday Today’s.
Unit 5 (Chp 15,17): Chemical & Solubility Equilibrium (K eq, K c, K p, K sp ) John D. Bookstaver St. Charles Community College St. Peters, MO  2006, Prentice.
Updated 9/27 - See slides 2 and 3
Chem. 31 – 10/2 Lecture.
Applications of Aqueous Equilibria
Chem. 31 – 10/9 Lecture.
Chem. 31 – 10/11 Lecture.
Presentation transcript:

Chem. 31 – 2/25 Lecture

Announcements I Exam 1 –On Monday (3/2) –Will Cover the parts we have covered in Ch. 1, 3 and 4 plus parts of Ch. 6 (through Le Châtelier’s Principle) –Some of HW1.3 postponed (see posted solutions) –Help session (11:00 to 12:00 on Friday – after office hours)

Announcements II Today’s Lecture –Chapter 6 Material – Le Châtelier’s Principle (last part on Exam1) –Review of Material on Exam 1 (including Equation) –Chapter 6 Material not on Exam 1 (Sparingly soluble salts)

Le Châtelier’s Principle Stess Number Two: Dilution Side with more moles is favored at lower concentrations Example: HNO 2 (aq) ↔ H + + NO 2 - If solution is diluted, reaction goes to products If diluted to 2X the volume: So Q<K, products favored

Le Châtelier’s Principle Stess Number Two: Dilution – Molecular Scale View H+H+ NO 2 - Concentrated Solution H+H+ NO 2 - H+H+ H+H+ H+H+ Diluted Solution – dissociation allows ions to fill more space H+H+ NO 2 - H+H+ H+H+ H+H+ H+H+

Le Châtelier’s Principle Stress Number 3: Temperature If ΔH>0, as T increases, products favored If ΔH<0, as T increases, reactants favored Easiest to remember by considering heat a reactant or product Example: OH - + H + ↔ H 2 O(l) + heat Increase in T

Some Le Chatelier’s Principle Examples Looking at the reaction below, that is initially at equilibrium, AgCl(s) ↔ Ag + (aq) + Cl - (aq) (ΔH°>0) determine the direction (toward products or reactants) each of the following changes will result in a)increasing the temperature b)addition of water c)addition of AgCl(s) d)addition of NaCl

Review for Exam Know the following (from Ch. 1) –Common base units (m, kg, s, mol, K) + common multipliers (nano to kilo) –How to convert between different units* –Definitions of main concentration units (M, weight fractions including % and ppm, and mass/volume) –How to convert between concentration units* –Steps to make solutions of known concentration + calculations for solution preparation* –How to do stoichiometry problems (involving solids or solutions)* Note: *means need quantitative knowledge

Review for Exam – cont. Know the following (from Ch. 1 – cont.) –Titration definitions (titrant, equivalence point, end point, standardization titrations, analyte titrations, back titrations) –Practical titration requirements –How to solve normal and back titration problems* Know the following (from Ch. 3) –Rules for significant figures (including for calculations with +, -, *, or / and when uncertainties are given)* –Definitions for: systematic and random error, accuracy and precision, uncertainty, relative error and relative uncertainty

Review for Exam Know the following (from Ch. 3 – cont.) -How to do propagation of uncertainty problems (+, -, *, /, exponent, and mixed operations) and to convert between absolute and relative uncertainty* Know the following (from Ch. 4) -What a Gaussian distribution represents -How to calculate mean values and standard deviations (can use calculators)* -The differences between populations and samples -How to calculate Z values*

Review for Exam – Ch. 4 (cont.) How to use Table 4-1 and Z values to calculate probabilities between limits* How to determine confidence intervals* + factors which influence confidence intervals Difference between Z and t based confidence intervals (lecture only) What confidence intervals tell you How to perform t-test (case 1)* How to recognize and select a proper test (3 t tests, F test and Grubbs test) How to deal with poor data points (including use of Grubbs test)*

Review for Exam Chapter 4 – cont. -How method of least squares works (qualitatively) -Steps to the calibration process -Assumptions required for least squares analysis -How to determine concentrations of unknowns* + limitations in this Chapter 6 -Be able to write equilibrium equations from given equilibrium reactions -Manipulate equilibrium reactions/equations* -Definitions of changes in Enthalpy, Entropy and Free Energy plus predictions given reaction

Review for Exam – Ch. 6 (cont.) Chapter 6 Be able to determine K from  G° or visa versa Be able to calculate  G from  H and  S Be able to predicts shift in equilibrium due to changes in conditions (Le Châtelier’s Principle)

Review for Exam Equations I will give -Basic propagation of uncertainty equations (e.g. for Y = a + b, Y = a·b, and Y = x n ) -Equation for calculation of standard deviation -Grubb’s test equation -Equation for converting K to  Gº

Ch. 6 – Solubility Problems Why Solubility is Important Use in gravimetric analysis (predict if precipitation is complete enough) Use in precipitation titrations (not covered) Use in separations (e.g. separation of Mg 2+ from Ca 2+ in tap water for separate analysis) Understand phase in which analytes will exist Problem Overview Dissolution of sparingly soluble salts in water Dissolution of sparingly soluble salts in common ion Precipitation problems (and selective precipitation problems)

Solubility Product Problems - Solubility in Water Example: solubility of Mg(OH) 2 in water Solubility defined as mol Mg(OH) 2 dissolved/L sol’n or g Mg(OH) 2 dissolved/L sol’n or other units Use ICE approach: Mg(OH) 2 (s) ↔ Mg OH - Initial0 0 Change +x +2x Equilibriumx 2x Note: x = [Mg 2+ ] = solubility

Solubility Product Problems - Solubility of Mg(OH) 2 in water Equilibrium Equation: K sp = [Mg 2+ ][OH - ] 2 K sp = 7.1 x = x(2x) 2 = 4x 3 (see Appendix F for K sp ) x = (7.1 x /4) 1/3 = 1.2 x M Solubility = 1.2 x M = [Mg 2+ ] Conc. [OH - ] = 2x = 2.4 x M

Solubility Product Problems - Solubility of Mg(OH) 2 in Common Ion If we dissolve Mg(OH) 2 in a common ion (OH - or Mg 2+ ), from Le Châtelier’s principle, we know the solubility will be reduced Example 1) What is the solubility of Mg(OH) 2 in a pH = 11.0 buffer? No ICE table needed because, from pH, we know [OH - ] eq and buffer means dissolution of Mg(OH) 2 doesn’t affect pH.

Solubility Product Problems - Solubility of Mg(OH) 2 at pH 11 – cont. [H + ] = 10 -pH = M and [OH - ] = K w /[H + ] = M K sp = [Mg 2+ ][OH - ] 2 Moles Mg(OH) 2 dissolved = moles Mg 2+ [Mg 2+ ] = K sp /[OH - ] 2 = 7.1 x /(10 -3 ) 2 [Mg 2+ ] = 7 x M

Solubility Product Problems - Solubility of Mg(OH) 2 in Common Ion Example 2) Solubility of Mg(OH) 2 in 5.0 x M MgCl 2.

Solubility Product Problems Precipitation Problems What occurs if we mix 50 mL of M BaCl 2 with 50 mL of 3.0 x M (NH 4 ) 2 SO 4 ? Does any solid form from the mixing of ions? What are the concentrations of ions remaining?