1 Fall 2004 Physics 3 Tu-Th Section Claudio Campagnari Lecture 10: 28 Oct. 2004 Web page:

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Presentation transcript:

1 Fall 2004 Physics 3 Tu-Th Section Claudio Campagnari Lecture 10: 28 Oct Web page:

2 Today: Electric Potential Energy You should be familiar with the concept of gravitational potential energy from Physics 1 Let's review If a force acts on a particle as the particle moves from a  b, then is the work done by the force ( is the infinitesimal displacement along the path)

3 a b Careful: the force does not necessarily line up with the displacement For example, a block sliding down an inclined plane under the influence of gravity:

4 Conservative force A force is conservative if the work done by the force is independent of path  Only depends on the initial and final points Then the work done can be written as function of the difference between some properties of the begin and final point a b

5 U is the potential energy W = -  U Work energy theorem: work = change in kinetic energy W a  b = K(b) – K(a) K(a) + U(a) = K(b) + U(b) Potential energy defined up to additive constant

6 Remember gravitational field, force, potential energy Near the surface of the earth, constant force Think of it as mass times constant gravitational field Then gravitational potential energy U=mgh

7 Now imagine charge q 0 in constant electric field Constant force By analogy with gravity U = q 0 Ey U = electric potential energy of the charge q 0 Electric field lines q0q0 y x Careful: the y-axis points opposite to the E field

8 Electric field lines q0q0 y x U = q 0 Ey If q 0 is positive  The force is downwards  The force "pushes" the charge downwards, towards smaller y  The force tends to make U smaller If q 0 is negative  The force is upwards  The force "pushes" the charge upwards towards larger y  This also tends to make U smaller because of the –ve sign of the q 0 in the expression U=q 0 Ey

9 Potential energy of two point charges Remember the definition Consider displacement along line joining the two charges ("radial displacement Tempting to identify

10 This holds if the work is independent of path  Look at a different path r a  r b  The work depends only on the radial displacement It does not depend on the amount of "sideways" displacement Work only depends on initial and final values of r

11 Summary: Potential energy of two point charges where r is the distance between the two charges Most often we take Const=0 for simplicity Then U  0 as r  ∞ Repulsion: charges want to move apart Attraction: charges want to move together Always tendency to reduce potential energy

12 If we have many charges... Consider electric field caused by a bunch of charges q 1, q 2, q 3,... Bring a test charge q 0 into the picture Potential energy associated with q 0 Potential energy is an additive quantity

13 Many charges (cont.) If I have a collection of charges, the interaction of each pair will contribute to the total potential energy of the system A compact way of writing it is Where  q i and q j are the i-th and j-th charge  r ij is the distance between i-th and j-th charge  i<j insures no double counting

14 You should try to get used to this kind of compact notation! Let's see an example. Three charges. What are the terms? Possibilities are i=1 and j=1 i=1 and j=2 i=1 and j=3 i=2 and j=1 i=2 and j=2 i=2 and j=3 i=3 and j=1 i=3 and j=2 i=3 and j=3 Only some of these satisfy the i<j condition Then the sum becomes You see that each pair of charges enters once and only once

15 Work to and from infinity Work done by the electric field in going from a  b = 0 Convention! U(  )=0  U(r) can be thought of as the work that the electric field would do in moving the test charge q 0 from its position to  Conversely, the work that an external force would need to do to bring the charge from  to its current position is –U

16 Example A particle of charge q and mass m is accelerated from rest by a constant electric field E. What is the velocity after the particle travelled a distance L? qq x x initial x x final v Electric Field Lines Before: v=0 After: x final -x initial = L, v=??? Guiding principle: conservation of energy K initial + U initial = K final + U final

17 qq x x initial x x final v Electric Field Lines Before: v=0 After: x final -x initial = L, v=??? K initial + U initial = K final + U final K initial = 0 and K final = ½ m v 2 The electric potential energy is a function of x U(x) = - qEx + Constant Careful: earlier we defined it without a minus sign This is because before we had the axis pointing opposite to the electric field. But here the x-axis points in the same direction as the electric field!

18 K initial + U initial = K final + U final K initial = 0 and K final = ½ m v 2 U(x) = - qEx + Constant U initial = -qEx initial + Constant U final = -qEx final + Constant 0 – qEx initial + Const. = ½ m v 2 –qEx final + Const. ½ m v 2 = qE(x final – x initial ) = L v 2 = 2qEL/m Note that the arbitrary constant dropped out

19 Another example (Prob. 23.3) A metal sphere, charge q 1 = -2.8  C is held stationary by an insulating support. A 2 nd sphere, q 2 = -7.8  C amd m=1.5 g is moving towards q 1. When the two spheres are d=0.8 m apart, q 2 is moving with v=22 m/sec. (a)What is the speed of q 2 when the spheres are 0.4 m apart? (b)How close does q 2 get to q 1 before turning back? Conservation of energy K 1 + U 1 = K 2 + U 2 K 1 = ½ m v 1 2 U 1 = k q 1 q 2 /d 1 K 2 = ½ m v 2 2 U 2 = k q 1 q 2 /d 2

20 Conservation of energy K 1 + U 1 = K 2 + U 2 K 1 = ½ m v 1 2 U 1 = k q 1 q 2 /d 1 K 2 = ½ m v 2 2 U 2 = k q 1 q 2 /d 2 ½ m v k q 1 q 2 /d 1 = ½ m v k q 1 q 2 /d 2 v 2 2 = v (k/m)q 1 q 2 (1/d 1 - 1/d 2 ) m/s v 2 = 12.5 m/s Next: where does it stop? It stops when v 2 = 0; the conservation of energy equation: ½ m v k q 1 q 2 /d 1 = k q 1 q 2 /d 2

21 Electric potential Definition: if a charge q 0 in an electric field has electric potential energy U, then the electric potential is defined as Think of electric potential as "potential energy per unit charge" Much as electric field is "force per unit charge"

22 Electric Potential Electric potential is a property of the electric field and varies as a function of position in space Since U is defined up to an arbitrary constant, V is also defined up to an arbitrary constant. Only differences in potential between two points are meaningful Jargon: potential of a with respect to b V ab = V a – V b

23 Electric Potential Units: [V] = [U]/[Q] = Joule/Coulomb Definition 1 Volt = 1 J/C  Abbreviation: V Potential of a w.r.t. b (V ab ) also called voltage V ab = work done by electric force in moving unit charge from a to b V ab work done against electric force in moving unit charge from b to a

24 How to not get confused by the signs! Just remember one general principle The electric force does positive work in moving from high electric potential energy to low electric potential energy Just like gravity does positive work in moving a body down towards the surface of the earth  Body is high  potential energy is high  Body is low  potential energy is low

25 Using previous results for U.... And also an (obvious) generalization:

26 V from E Given a charge distribution, it is straight forward (in principle!) to find V Sometimes you can get V starting from E

27 Example Back to charge q in constant electric field qq x x initial x x final v Electric Field Lines Before: v=0 After: x final -x initial = L, v 2 =2qEL/m What is  V = V initial – V final ?

28 The electron volt (eV) Consider an electron accelerated through a potential difference of  V=1 V. Change in potential energy  U = -e  V This must be compensated by a change in kinetic energy  K = e  V = J Definition of electron volt (eV): The kinetic energy gained by an electron accelerated through a  V = 1 Volt 1eV = J Useful unit of energy in atomic physics, chemistry, etc.  This is a unit of energy, not potential  Don't get confused

29 The largest accelerator CERN LHC (Geneva, Switzerland) Underground tunnel 26 Km circumference Accelerates protons to 7 TeV = eV Switzerland France

30 One more word about units These are the same