Lecture 17 AC Circuit Analysis (2) Hung-yi Lee. Textbook AC Circuit Analysis as Resistive Circuits Chapter 6.3, Chapter 6.5 (out of the scope) Fourier.

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Presentation transcript:

Lecture 17 AC Circuit Analysis (2) Hung-yi Lee

Textbook AC Circuit Analysis as Resistive Circuits Chapter 6.3, Chapter 6.5 (out of the scope) Fourier Series for Circuit Analysis Resonance Chapter 6.4 (out of the scope) Oscillator Example 9.7 and 6.10

Systematic Analysis for AC Steady State

Example – Node Analysis

Supernode

Example – Node Analysis Supernode

Thevenin and Norton Theorem for AC Steady State

Thevenin & Norton Theorem DC circuit Two Terminal Network Thevenin Theorem Norton Theorem

Thevenin & Norton Theorem DC circuit Find the Thevenin parameters Two Terminal Network Two Terminal Network Two Terminal Network Suppress Sources

Thevenin & Norton Theorem AC steady state Two Terminal Network Thevenin Theorem Norton Theorem

Thevenin & Norton Theorem AC steady state Find the Thevenin parameters Two Terminal Network Two Terminal Network Two Terminal Network Suppress Sources

Obtain I o by Norton Theorem Example - Norton Theorem

Obtain I o by Norton Theorem Find Z t Suppress Sources Two-terminal Network

Example - Norton Theorem Obtain I o by Norton Theorem Find

Obtain I o by Norton Theorem Example - Norton Theorem

Superposition for AC Steady State

AC Superposition – Example 6.17 Find v c However, what is the value of ω?

AC Superposition – Example 6.17 Superposition Principle

AC Superposition – Example 6.17 The same element has different impedances.

AC Superposition – Example 6.17

Fourier Series for Circuit Analysis

Beyond Sinusoids 1. Fourier Series: periodic function is a linear combination of sinusoids 2. Superposition: find the steady state of individual sinusoids, and then sum them together

Fourier Series Periodic Function: f(t) = f(t+nT) Period: T Frequency: f 0 = 1/T Circular Frequency: ω 0 = 2πf 0 = 2π/T Fourier Series: You will learn how to find a 0, a n and b n in other courses.

Fourier Series

Network

…… = Network Capacitor = Open Inductor = Short

Example

Application: Resonance

Communication How to change audio into different frequency?

AM Frequency at f Frequency close to f

FM Frequency at f Frequency close to f

Communication How to design a circuit that can only receive the signal of a specific frequency?

Series RLC

Fix V m Change ω

Resonance Antenna If the frequency of the input signal is close to ω 0 Large current Otherwise Like open circuit

Series RLC - Bandwidth

Quality Using quality factor Q to define the selectivity

Quality For radio, cell phone, etc., the quality should be 1. As high as possible? 2. As low as possible? 3. None of the above?

Application: Oscillator

Oscillator Oscillator (Example 9.7 and 6.10) An oscillator is an electric circuit that generate a sinusoidal output with dc supply voltage DC to AC Remote Controller, Cell phone

Oscillator - Example 6.10 First Find

Oscillator - Example 6.10

If we want v in and v x in phase

Oscillator - Example 6.10 If we want v in = v out (v in and v x in phase)

Oscillator - Example 6.10 v in = v out Set Input: Use output as input

Oscillator - Example 6.10 Generate sinusoids without input!  Will the oscillation attenuate with time?  Yes.R dissipate the energy  No.Who supply the power? Amplifier

Oscillator - Example 6.10 TV remote controller Battery of controller

Oscillator - Example 9.7 Set Undamped

Oscillator - Example 9.7 Amplitude and phase are determined by initial condition

Homework

Homework – Mesh Analysis 1

Homework – Mesh Analysis 2

Homework – Thevenin 1 Find the Thevenin equivalent of the following network

Homework – Thevenin 2 Find the Thevenin equivalent of the following network

Homework – Superposition 1 (out of the scope) Calculate v o

Homework – Superposition 2 (out of the scope) Calculate v o

Thank you!

Answer 6.46: v2=8cos(5t+53.1 。 ) 6.52: 6.44

Answer – Mesh Analysis 1

Answer – Mesh Analysis 2

Answer – Thevenin 1 Find the Thevenin equivalent of the following network

Answer – Thevenin 2 Find the Thevenin equivalent of the following network

Answer – Superposition 1 Using superposition

Answer – Superposition 2 Using superposition

Acknowledgement 感謝 陳俞兆 (b02) 在上課時指出投影片中的錯誤 感謝 趙祐毅 (b02) 在上課時指出投影片中的錯誤 感謝 林楷恩 (b02) 修正作業的答案