Lecture 61/30/06 Seminar TODAY at 4
Effect of a catalyst Increases the rate at which reaction gets to equilibrium Doesn’t change the equilibrium concentrations How does it affect K? Many industrial processes use heterogeneous catalysts
Example For the following reaction: ΔH˚ = 2816 KJ/mol 6 CO 2 (g) + 6 H 2 O (l) ⇄ C 6 H 12 O 6 (s) + 6 O 2 (g) How is the equilibrium yield of C 6 H 12 O 6 affected by: Increasing P CO2 ? Increasing temperature? Removing CO 2 ? Decreasing the total pressure? Removing part of the C 6 H 12 O 6 ? Adding a catalyst?
C (s) + CO 2 (g) ⇄ 2 CO (g) P total = 1 atm Endothermic or exothermic? Calculate K p and K c at 850 ˚C T (˚C)CO 2 (mol %)CO (mol %)
Problem A sample of pure SO 3, weighing g was placed in a 1.00-L flask and heated to 1100 K to decompose it partially. 2SO 3 (g) ⇄ 2 SO 2 (g) + O 2 (g) If a total pressure of atm was developed, find the value of K c for this reaction at this temperature.
Precipitation reactions What are they? Solubility?
Solubility Rules Soluble CompoundsExceptions NO 3 - None C 2 H 3 O 2 - (acetate)None Cl -, Br -, I - Compounds with Ag +, Hg 2 2+, Pb 2+ SO 4 2- Compounds with Sr 2+, Ba 2+, Hg 2 2+, Pb 2+ Group 1A and NH 4 + None Insoluble CompoundsExceptions S 2- Group 1A and NH 4 +, Ca 2+, Sr 2+, Ba 2+ CO 3 2-,PO 4 3-, C 2 O 4 2-, CrO 4 2- Group 1A and NH 4 + OH - Group 1A and NH 4 +, Ca 2+, Sr 2+, Ba 2+
Equations Pb(NO 3 ) 2 reacts with NaI (aq) to form the insoluble compound, PbI 2. Molecular Equation? Complete Ionic Equation? Net Ionic Equation?
Solubility vs. Solubility constant (K sp ) What is the difference? BaSO 4 (s) ⇄ Ba 2+ (aq) + SO 4 2- (aq) Ba 2+ (aq) + SO 4 2- (aq) ⇄ BaSO 4 (s)
What is the K sp for AgI if the solubility equals 9.2 x M at 25˚ C?
The K sp of AgBr at 100 ˚C is 5 x Calculate the solubility of AgBr at that temperature in molarity.
A saturated solution of silver oxalate (Ag 2 C 2 O 4 ) contains 6.9 x M of C 2 O 4 2- at 25˚C. Calculate the K sp of silver oxalate at that temperature.
The K sp of MgF 2 = 5.2 x Calculate the solubility in molarity and grams per liter.
Comparison of solubility based on K sp AgI (K sp = 8.5 x ) < AgBr (K sp = 5.4 x ) < AgCl (K sp = 1.8 x ) PbI 2 (K sp = 9.8 x ) < PbBr 2 (K sp = 6.6 x ) < PbCl 2 (K sp = 1.7 x ) Can only compare salts with same ion ratio AgCl (K sp = 1.8 x ) vs. Ag 2 CO 3 (K sp = 8.5 x ) Solubility of AgCl = 1.3 x mol/L Solubility of Ag 2 CO 3 = 1.3 x mol/L