Query Optimization Zachary G. Ives University of Pennsylvania CIS 550 – Database & Information Systems November 18, 2003 Slide content courtesy Raghu Ramakrishnan.

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Presentation transcript:

Query Optimization Zachary G. Ives University of Pennsylvania CIS 550 – Database & Information Systems November 18, 2003 Slide content courtesy Raghu Ramakrishnan & Johannes Gehrke

2 A Brief Look at a Different Method for Processing XML… Griffith Sims 12 Pike Pl. Seattle Jones 30 Main St. Berkeley Element Data value

3 Querying XML with XQuery “Query over all stores, managers, and cities”: Query operations evaluated over all possible tuples of ( $s, $m, $c ) that can be matched on input FOR $s = (document) /db/store, $m = $s/manager/data(), $c = $s//city/data() WHERE {join + select conditions} RETURN {XML output}

4 Processing XML  Bind variables to subtrees; treat each set of bindings as a tuple  Select, project, join, etc. on tuples of bindings  Plus we need some new operators:  XML construction:  Create element (add tags around data)  Add attribute(s) to element (similar to join)  Nest element under other element (similar to join)  Path expression evaluation – create the binding tuples

5 Standard Method: XML Query Processing in Action Parse XML: Griffith Sims 12 Pike Pl. Seattle … Match paths: $s = (root) /db/store $m = $s/manager/data() $c = $s//city/data() $s$m$c #1GriffithSeattle #1SimsSeattle #2JonesMadison

6 X-Scan: “Scan” for Streaming XML, Based on SAX  We often re-read XML from net on every query Data integration, data exchange, reading from Web  Could use an XML DBMS, which looks like an RDBMS except for some small extensions  But cannot amortize storage costs for network data  X-scan works on streaming XML data  Read & parse  Evaluate path expressions to select nodes

7 $s$m$c X-Scan: Incremental Parsing & Path Matching Jones 30 Main St. Berkeley Griffith Sims 12 Pike Pl. Seattle #1Griffith #1Sims Seattle #2JonesBerkeley #1 #2 Tuples for query: $s $m $c 12 3 dbstore 45 6 manager data() 67 8 citydata()

8 Building XML Output  Need the following operations:  Create XML Element  Create XML Attribute  Output Value/Variable into XML content  Nest XML subquery results into XML element  (Looks very much like a join between parent query and subquery!)

9 An XML Query  X-scan creates tuples  Select, join as usual  Construct results  Output variable  Create element around content  A few key extensions to standard models!

10 Query Execution Is Still a Vibrant Research Topic  Adaptive scheduling of operations – combining with optimization (discussed next!)  Robust – exploit replicas, handle failures  Show and update partial/tentative results  More interactive and responsive to user  More complex data models – XML, semistructured data  Now: how the cost equations you saw are useful in optimizing queries!

Overview of Query Optimization  Plan: Tree of R.A. ops, with choice of alg for each op.  Each operator typically implemented using a `pull’ interface: when an operator is `pulled’ for the next output tuples, it `pulls’ on its inputs and computes them.  Two main issues:  For a given query, what plans are considered?  Algorithm to search plan space for cheapest (estimated) plan.  How is the cost of a plan estimated?  Ideally: Want to find best plan. Practically: Avoid worst plans!  We will study the System R approach.

Highlights of System R Optimizer  Impact:  Most widely used currently; works well for < 10 joins.  Cost estimation: Approximate art at best.  Statistics, maintained in system catalogs, used to estimate cost of operations and result sizes.  Considers combination of CPU and I/O costs.  Plan Space: Too large, must be pruned.  Only the space of left-deep plans is considered.  Left-deep plans allow output of each operator to be pipelined into the next operator without storing it in a temporary relation.  Cartesian products avoided.

Schema for Examples  Reserves:  Each tuple is 40 bytes long, 100 tuples per page, 1000 pages.  Sailors:  Each tuple is 50 bytes long, 80 tuples per page, 500 pages. Sailors ( sid : integer, sname : string, rating : integer, age : real) Reserves ( sid : integer, bid : integer, day : dates, rname : string)

Query Blocks: Units of Optimization  An SQL query is parsed into a collection of query blocks, and these are optimized one block at a time.  Nested blocks are usually treated as calls to a subroutine, made once per outer tuple. (This is an over- simplification, but serves for now.) SELECT S.sname FROM Sailors S WHERE S.age IN ( SELECT MAX (S2.age) FROM Sailors S2 GROUP BY S2.rating ) Nested blockOuter block  For each block, the plans considered are: – All available access methods, for each reln in FROM clause. – All left-deep join trees (i.e., all ways to join the relations one- at-a-time, with the inner reln in the FROM clause, considering all reln permutations and join methods.)

Relational Algebra Equivalences  Allow us to choose different join orders and to `push’ selections and projections ahead of joins.  Selections: (Cascade) ( Commute )  Projections: (Cascade)  Joins: R ⋈ (S ⋈ T)  (R ⋈ S) ⋈ T (Associative) (R ⋈ S)  (S ⋈ R) (Commute) R ⋈ (S ⋈ T)  (T ⋈ R) ⋈ S  Show that:

More Equivalences  A projection commutes with a selection that only uses attributes retained by the projection.  Selection between attributes of the two arguments of a cross-product converts cross-product to a join.  A selection on just attributes of R commutes with R ⋈ S. (i.e., (R ⋈ S) (R) ⋈ S )  Similarly, if a projection follows a join R ⋈ S, we can `push’ it by retaining only attributes of R (and S) that are needed for the join or are kept by the projection.

Enumeration of Alternative Plans  There are two main cases:  Single-relation plans  Multiple-relation plans  For queries over a single relation, queries consist of a combination of selects, projects, and aggregate ops:  Each available access path (file scan / index) is considered, and the one with the least estimated cost is chosen.  The different operations are essentially carried out together (e.g., if an index is used for a selection, projection is done for each retrieved tuple, and the resulting tuples are pipelined into the aggregate computation).

Cost Estimation  For each plan considered, must estimate cost:  Must estimate cost of each operation in plan tree.  Depends on input cardinalities.  Must also estimate size of result for each operation in tree!  Use information about the input relations.  For selections and joins, assume independence of predicates.

Cost Estimates for Single-Relation Plans  Index I on primary key matches selection:  Cost is Height(I)+1 for a B+ tree, about 1.2 for hash index.  Clustered index I matching one or more selects:  (NPages(I)+NPages(R)) * product of RF’s of matching selects.  Non-clustered index I matching one or more selects:  (NPages(I)+NTuples(R)) * product of RF’s of matching selects.  Sequential scan of file:  NPages(R).

Example  If we have an index on rating:  (1/NKeys(I)) * NTuples(R) = (1/10) * tuples retrieved.  Clustered index: (1/NKeys(I)) * (NPages(I)+NPages(R)) = (1/10) * (50+500) pages are retrieved. (This is the cost.)  Unclustered index: (1/NKeys(I)) * (NPages(I)+NTuples(R)) = (1/10) * ( ) pages are retrieved.  If we have an index on sid:  Would have to retrieve all tuples/pages. With a clustered index, the cost is , with unclustered index,  Doing a file scan:  We retrieve all file pages (500). SELECT S.sid FROM Sailors S WHERE S.rating=8

Queries Over Multiple Relations  Fundamental decision in System R: only left-deep join trees are considered.  As the number of joins increases, the number of alternative plans grows rapidly; we need to restrict the search space.  Left-deep trees allow us to generate all fully pipelined plans.  Intermediate results not written to temporary files.  Not all left-deep trees are fully pipelined (e.g., SM join). B A C D B A C D C D B A

Enumeration of Left-Deep Plans  Left-deep plans differ only in the order of relations, the access method for each relation, and the join method  Enumerated using N passes (if N relations joined):  Pass 1: Find best 1-relation plan for each relation.  Pass 2: Find best way to join result of each 1-relation plan (as outer) to another relation. (All 2-relation plans.)  Pass N: Find best way to join result of a (N-1)-relation plan (as outer) to the N’th relation. (All N-relation plans.)  For each subset of relations, retain only:  Cheapest plan overall, plus  Cheapest plan for each interesting order of the tuples.

Enumeration of Plans (Contd.)  ORDER BY, GROUP BY, aggregates etc. handled as a final step, using either an `interestingly ordered’ plan or an addional sorting operator.  An N-1 way plan is not combined with an additional relation unless there is a join condition between them, unless all predicates in WHERE have been used up.  i.e., avoid Cartesian products if possible.  In spite of pruning plan space, this approach is still exponential in the # of tables.

Cost Estimation for Multirelation Plans  Consider a query block:  Maximum # tuples in result is the product of the cardinalities of relations in the FROM clause.  Reduction factor (RF) associated with each term reflects the impact of the term in reducing result size. Result cardinality = Max # tuples * product of all RF’s.  Multirelation plans are built up by joining one new relation at a time.  Cost of join method, plus estimation of join cardinality gives us both cost estimate and result size estimate SELECT attribute list FROM relation list WHERE term1 AND... AND termk

Example  Pass1:  Sailors: B+ tree matches rating>5, and is probably cheapest. However, if this selection is expected to retrieve a lot of tuples, and index is unclustered, file scan may be cheaper.  Still, B+ tree plan kept (because tuples are in rating order).  Reserves: B+ tree on bid matches bid=500; cheapest. Sailors: B+ tree on rating Hash on sid Reserves: B+ tree on bid  Pass 2: – We consider each plan retained from Pass 1 as the outer, and consider how to join it with the (only) other relation. u e.g., Reserves as outer : Hash index can be used to get Sailors tuples that satisfy sid = outer tuple’s sid value. Reserves Sailors sid=sid bid=100 rating > 5 sname

Nested Queries  Nested block is optimized independently, with the outer tuple considered as providing a selection condition.  Outer block is optimized with the cost of `calling’ nested block computation taken into account.  Implicit ordering of these blocks means that some good strategies are not considered. The non-nested version of the query is typically optimized better. SELECT S.sname FROM Sailors S WHERE EXISTS ( SELECT * FROM Reserves R WHERE R.bid=103 AND R.sid=S.sid) Nested block to optimize: SELECT * FROM Reserves R WHERE R.bid=103 AND S.sid= outer value Equivalent non-nested query: SELECT S.sname FROM Sailors S, Reserves R WHERE S.sid=R.sid AND R.bid=103

Query Optimization Recapped  Query optimization is an important task in a relational DBMS.  Must understand optimization in order to understand the performance impact of a given database design (relations, indexes) on a workload (set of queries).  Two parts to optimizing a query:  Consider a set of alternative plans.  Must prune search space; typically, left-deep plans only.  Must estimate cost of each plan that is considered.  Must estimate size of result and cost for each plan node.  Key issues: Statistics, indexes, operator implementations.

Single-Relation Queries  Single-relation queries:  All access paths considered, cheapest is chosen.  Issues: Selections that match index, whether index key has all needed fields and/or provides tuples in a desired order.

29 Multiple-Relation Queries  Multiple-relation queries:  All single-relation plans are first enumerated.  Selections/projections considered as early as possible.  Next, for each 1-relation plan, all ways of joining another relation (as inner) are considered.  Next, for each 2-relation plan that is `retained’, all ways of joining another relation (as inner) are considered, etc.  At each level, for each subset of relations, only best plan for each interesting order of tuples is `retained’.