A Charged, Thin Sheet of Insulating Material + + + + + + + + + + +

Slides:



Advertisements
Similar presentations
Conductors in Electrostatic Equilibrium
Advertisements

Announcements Monday guest lecturer: Dr. Fred Salsbury. Solutions now available online. Will strive to post lecture notes before class. May be different.
Chapter 22--Examples.
CONDUCTORS + CAPACITORS
Rank the electric fluxes through each Gaussian surface shown in the figure from largest to smallest. Display any cases of equality in your ranking.
Chapter 22: The Electric Field II: Continuous Charge Distributions
Applications of Gauss’s Law
Electric Potential AP Physics Montwood High School R. Casao.
Conductors in Electrostatic Equilibrium
Example: An insulating solid sphere of radius R has a uniform positive volume charge density and total charge Q. a)Find the electric potential at a point.
Physics 2102 Lecture 4 Gauss’ Law II Physics 2102 Jonathan Dowling Carl Friedrich Gauss Version: 1/23/07 Flux Capacitor (Operational)
© 2012 Pearson Education, Inc. A spherical Gaussian surface (#1) encloses and is centered on a point charge +q. A second spherical Gaussian surface (#2)
C. less, but not zero. D. zero.
Phy 213: General Physics III Chapter 23: Gauss’ Law Lecture Notes.
Conductors in Electrostatic Equilibrium. Electrostatic Equilibrium No net flow of electric charge No current.
Conductors and Dielectrics in Static Electric Fields
Objectives: 1. Define and calculate the capacitance of a capacitor. 2. Describe the factors affecting the capacitance of the capacitor. 3. Calculate the.
Hw: All Chapter 5 problems and exercises. Test 1 results Average 75 Median 78 >90>80>70>60>50
If I put no excess charge on the conductor, the net charge on its inner surface will be: a] 0 b] +Q c] -Q d] -2Q e] cannot determine.
A Charged, Thin Sheet of Insulating Material
A sphere of radius A has a charge Q uniformly spread throughout its volume. Find the difference in the electric potential, in other words, the voltage.
Real Insulators (Dielectrics)
Hw: All Chapter 4 problems and exercises Chapter 5: Pr. 1-4; Ex. 1,2 Reading: Chapter 5.
Electricity and Magnetism
Example: Potential Difference of Point Charges Consider a point charge q. What is the potential difference between point x 1 and point x 2 ? q x2x2 x1x1.
Average 68.4 Median Highest 100 Lowest 26 Section Section Section Section
Electricity and Magnetism
Outline Applications of Gauss’s Law - The single Fixed Charge -Field of a sphere of charge -Field of a spherical shell -A Line of Charge Conductors and.
Calculate Electric Potential: Example A conducting sphere of radius R 1 =0.5m is placed at the center of a conducting spherical shell of inner and outer.
Slide 1 Electric Field Lines 10/29/08. Slide 2Fig 25-21, p.778 Field lines at a conductor.
Exam Average 78.4 Median 84 Outline Applications of Gauss’s Law - The single Fixed Charge -Field of a sphere of charge -Field of a.
General Physics 2, Lec 5, By/ T.A. Eleyan 1 Additional Questions (Gauss’s Law)
Nadiah Alanazi Gauss’s Law 24.3 Application of Gauss’s Law to Various Charge Distributions.
Today’s agenda: Announcements. Gauss’ Law Examples. You must be able to use Gauss’ Law to calculate the electric field of a high-symmetry charge distribution.
Example: calculate the electric field for 0
4. Electrostatics with Conductors
Hw: All Chapter 5 problems and exercises. Outline Applications of Gauss’s Law - The single Fixed Charge -Field of a sphere of charge -Field of a spherical.
General Physics 2, Lec 5, By/ T.A. Eleyan 1 Additional Questions (Gauss’s Law)
III.A 3, Gauss’ Law.
Fig 24-CO, p.737 Chapter 24: Gauss’s Law قانون جاوس 1- Electric Flux 2- Gauss’s Law 3-Application of Gauss’s law 4- Conductors in Electrostatic Equilibrium.
© 2012 Pearson Education, Inc. { Chapter 22 Applying Gauss’s Law.
Q21. Gauss’ Law. 1.A particle with charge 5.0-  C is placed at the corner of a cube. The total electric flux in N  m 2 /C through all sides of the cube.
Electricity and Magnetism Review 1: Units 1-6
Chapter 25 Capacitors Capacitor and Capacitance A capacitor consists of two isolated conductors (the plates) with charges + q and - q. Its capacitance.
Physics 2112 Unit 4: Gauss’ Law
Chapter 21 Electric Charge and Electric Field HW #4: Chapter 21: Pb.21,Pb.38, Pb.40, Pb.52, Pb.59, Pb.80 Due Friday, Feb 20.
Application of Gauss’ Law to calculate Electric field:
ELECTRICITY PHY1013S GAUSS’S LAW Gregor Leigh
Lecture 7-1 Gravitational vs Electrostatic Potential Energy a b GravityCoulomb b a.
Q22.1 A spherical Gaussian surface (#1) encloses and is centered on a point charge +q. A second spherical Gaussian surface (#2) of the same size also encloses.
Tue. Feb. 3 – Physics Lecture #26 Gauss’s Law II: Gauss’s Law, Symmetry, and Conductors 1. Electric Field Vectors and Electric Field Lines 2. Electric.
Physics 2102 Gauss’ law Physics 2102 Gabriela González Carl Friedrich Gauss

Physics 212 Lecture 4, Slide 1 Physics 212 Lecture 4 Today's Concepts: Conductors + Using Gauss’ Law Applied to Determine E field in cases of high symmetry.
Electric Field Lines Contents: Basic Concept Field Lines and point charges Field Lines and conductors.
Objectives: 1. Define and calculate the capacitance of a capacitor. 2. Describe the factors affecting the capacitance of the capacitor. 3. Calculate the.
Help Session Ch-23.
+q r A A) |E| = kq/r2, to left B) kq/r2 > |E| > 0, to left
Electric flux To state Gauss’s Law in a quantitative form, we first need to define Electric Flux. # of field lines N = density of field lines x “area”
Physics 2102 Lecture: 06 MON 26 JAN 08
Electric flux To state Gauss’s Law in a quantitative form, we first need to define Electric Flux. # of field lines N = density of field lines x “area”
Last Lectures This lecture Gauss’s law Using Gauss’s law for:
An insulating spherical shell has an inner radius b and outer radius c
E. not enough information given to decide Gaussian surface #1
C. less, but not zero. D. zero.
Last Lectures This lecture Gauss’s law Using Gauss’s law for:
Electricity and Magnetism
Electric flux To state Gauss’s Law in a quantitative form, we first need to define Electric Flux. # of field lines N = density of field lines x “area”
Chapter 21, Electric Charge, and electric Field
Electricity and Magnetism
Presentation transcript:

A Charged, Thin Sheet of Insulating Material

1) There is a conducting spherical shell, inner radius A and outer radius B. If you put a charge Q on it, find the charge density everywhere. 2) There is a conducting spherical shell, inner radius A and outer radius B. A charge Q is put at the center. If you put a charge Q 2 on the shell, find the charge density everywhere.

Electric field near a surface of a conductor a

d a (the total field at any point between the plates) Two parallel conducting plates

An Apparent Contradiction

Near the surface of any conductor in electrostatics