Phys 102 – Lecture 19 Refraction & lenses.

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Presentation transcript:

Phys 102 – Lecture 19 Refraction & lenses

Today we will... Review refraction Learn applications of refraction Snell’s law Learn applications of refraction Total internal reflection Converging & diverging lenses Learn how lenses produce images Ray diagrams – principal rays Lens & magnification equations

Review: Snell’s Law Light bends when traveling into material with different n If n1 > n2 then θ2 > θ1 Light bends away from normal as it goes into a medium with lower n incident reflected refracted θ1 θ2 θr n2 n1 > n2

Total internal reflection From Snell’s law, if n1 > n2 then θ2 > θ1 So, θ1 θr θ2 Light incident at critical angle θ1= θc refracts || to surface (θ2 = 90°) = 90° Light incident at angle θ1> θc will only have reflection (θ1 = θr)! n2 n1 > n2 = θc

Calculation: underwater view Explain why the diver sees a circle of light from outside surrounded by darkness θi θc nair = 1 nwater = 1.33

ACT: CheckPoint 1.1 Can the person standing on the edge of the pool be prevented from seeing the light by total internal reflection? A. Yes B. No

Fiber Optics Optical fibers consist of “core” surrounded by “cladding” with ncladding < ncore. Light hits core-cladding interface at θi > θc, undergoes total internal reflection and stays in the fiber. θi > θc Core Only works if ncladding < ncore Cladding Telecommunication Arthroscopy Laser surgery DEMO

Converging lens Lenses use refraction and curved surface(s) to bend light in useful ways If n1 > n2 then θ2 > θ1 θ2 θ1 f p.a. “Focal length” DEMO Converging lens – rays || to p.a. refract through focal point f after lens

CheckPoint 2.1 A beacon in a lighthouse produces a parallel beam of light. The beacon consists of a bulb and a converging lens. Where should the bulb be placed? p.a. f p.a. f At f Inside f Outside f

Diverging lens Lenses use refraction and curved surface(s) to bend light in useful ways If n1 > n2 then θ2 > θ1 θ2 θ1 f p.a. DEMO Diverging lens – rays || to p.a. reflect as if they originated from focal point f before lens

Converging & diverging lenses Converging lens: Rays parallel to p.a. converge on focal point after lens = = Converging = thick in the middle “Plano-convex” “Double convex” “Concave-convex” Diverging lens: Rays parallel to p.a. diverge as if originating from focal point before lens = = “Plano-concave” “Double concave” “Convex-concave” Diverging = thin in the middle

ACT: Lens geometry The following lenses are all made from the same material but have different geometry Which lens has the shortest (positive) focal length? A. B. C. D.

ACT: CheckPoint 3.1 A glass converging lens placed in air has focal length f. nwater = 1.33 nglass nair = 1.0 Now the lens is placed in water. Its focal length: Stays the same Increases Decreases

Images & lenses Like mirrors, lenses produce images of objects Key approaches: Ray diagrams Thin lens & magnification equations

Principal rays – converging lens Ray from object traveling: parallel to principal axis, refracts through f through f, refracts parallel to principal axis through C, travels straight 3 1 Object f f Image 2 Image is: Real (light rays cross) Inverted (opposite direction as object) Reduced (smaller than object)

Principal rays – diverging lens Ray from object traveling: parallel to principal axis, refracts through f through f, refracts parallel to principal axis through C, travels straight 1 3 2 Image Object f f Image is: Virtual (light rays don’t really cross) Upright (same direction as object) Reduced (smaller than object)

ACT: CheckPoint 4.1 A converging lens produces a real image onto a screen. A piece of black tape is then placed over the upper half of the lens. Object f f Image Which of the following is true: Only the lower half of the object will show Only the upper half of the object will show The whole object will still show

Thin lens & magnification equations Image Object f f Thin lens equation So, Same as mirror equations!

Distance & magnification conventions Object Image ho di f hi do f do = distance object is from lens: > 0: object before lens < 0: object after lens ho = height of object: > 0: always di = distance image is from lens: > 0: real image (after lens) < 0: virtual image (before lens) hi = height of image: > 0: image is upright < 0: image is inverted f = focal length lens: > 0: converging lens < 0: diverging lens |m| = magnification: < 1: image is reduced > 1: image is enlarged Note similarities to mirror conventions

3 cases for concave mirrors Object is: Image is: f Image Object 2f Past 2f: 2f < do Inverted: hi < 0 Reduced: m < 1 Real: di > 0 f Image Object Between 2f & f: f < do < 2f Inverted: hi < 0 Enlarged: m > 1 Real: di > 0 f Image Object Inside f: do < f Upright: hi > 0 Enlarged: m > 1 Virtual: di < 0 DEMO

ACT: Converging Lens A candle is placed in front of a converging lens. The lens produces a well-focused image of the flame on a screen a distance di away. f di p.a. do f Screen If the candle is moved farther away from the lens, how should the screen be adjusted to keep a well-focused image? Closer to lens Further from lens At the same place

Calculation: diverging lens A 6-cm tall candle is placed 12 cm in front of a diverging lens with a focal length f = –6 cm. Determine the image location, size, and whether it is upright or inverted p.a. f f 4 cm Diagram should agree!

ACT: Diverging Lenses Where in front of a diverging lens should you place an object so the image is real? p.a. f f Closer to lens Further from lens Diverging lens can’t create real image

Summary of today’s lecture Total internal reflection Lenses – principal rays Parallel to p.a. –> refracts through f Through f -> refracts parallel to p.a. Through C -> straight through Thin lens & magnification equations Numerical answer consistent with ray diagram