Slide 2/21 Schedule Lecture 7: M-M bonds  -bonds and bonding in metal clusters Lecture 8: Rates of reaction Ligand-exchange reactions, labile and inert metal ions Lecture 9: Redox reactions Inner and outer-sphere reactions

Slide 3/21 Summary of Last Lecture Ligand substitution reactions Dissociative and associative mechanisms possible Rates vary widely for transition metal complexes  M 3+ slower than M 2+  d n with large LFSE are slow (d 3, d 8 and low spin d 5-7 ) Today’s lecture e - transfer reactions

Slide 4/21 Redox Reactions Redox reactions are very important in inorganic and bioinorganic chemistry. The shuttling of electrons between transition metal cations is at the centre of a wide variety of vital biological processes Redox reactions involving transition metal complexes generally occur very rapidly:  thermodynamics (using E 0 values) is very useful in predicting the outcome of reactions e - transfer reactions appear to occur via two reaction mechanisms  outer sphere  inner sphere

Slide 5/21 Outer Sphere e - Transfer The self-exchange reaction below is believed to occur via an outer sphere mechanism The two complexes (the reductant and the oxidant):  diffuse together in solution to form outer sphere complex,  an electron is transferred from reductant to oxidant  the complexes diffuse apart  the ligands remain attached throughout the reaction Most redox reactions in biology occur via this mechanism  Marcus theory explains the rate of these reactions (1992 Nobel prize for Chemistry) *Fe(H 2 O) Fe(H 2 O) 6 3+  *Fe(H 2 O) Fe(H 2 O) 6 2+ reductant oxidant  G = 0

Slide 6/21 Outer Sphere e - Transfer The self-exchange reaction below is believed to occur via an outer sphere mechanism *Fe(H 2 O) Fe(H 2 O) 6 3+  *Fe(H 2 O) Fe(H 2 O) 6 2+ reductant oxidant e - transfer occurs very rapidly – nuclei are too heavy to responds the Franck-Condon principle The products are formed with the geometries of the reactants After formation, they can relax to their true bond lengths AJB – lecture 2, CHEM2401  G = 0

e  transfer The products are formed with the geometries of the reactants:  ionic radii: Fe 2+ (75 pm) > Fe 3+ (69 pm)  if reactants are in their ground states, the products will be formed in excited states:  These excited states will then relax, releasing energy  BUT  G = 0 so energy seems to have been created from nothing Outer Sphere e - Transfer *[(H 2 O) 5 Fe ― OH 2 ] 2+ *[(H 2 O) 5 Fe ― OH 2 ] 3+ [(H 2 O) 5 Fe - OH 2 ] 3+ [(H 2 O) 5 Fe-OH 2 ] 2+ bonds too long bonds too short *[(H 2 O) 5 Fe-OH 2 ] 3+ [(H 2 O) 5 Fe ― OH 2 ] 2+ relax REACTION CANNOT BE OCCURING FROM GROUND STATES

Slide 8/21 There is an activation step in which bonds in Fe(H 2 O) 5 2+ are shortened and those in Fe(H 2 O) 6 3+ are lengthened so they are exactly the same Outer Sphere e - Transfer activation energy provided in (1) = relaxation energy in (3) so  G = 0

Slide 9/21 The activation step involves making the bond lengths in oxidant and reductant the same:  if oxidant and reductant have very different bond lengths  activation energy is large  reaction is slow  if oxidant and reductant have similar bond lengths  activation energy is small  reaction is fast Outer Sphere e - Transfer JKB – lecture 8, Need to compare bond lengths in oxidant and reductant to understand rate: Metals get smaller across period due to increasing Z Occupation of e g * orbitals lengthens bonds M 3+ are smaller than M 2+ due to charge

Slide 10/21 Ionic Radii - Recap Occupation of e g * orbitals lengthens bonds Metals get smaller across period due to increasing Z radii of M 2+ ions (pm) dndn egeg t 2g high spin low spin

Slide 11/21 Ionic Radii - Recap Occupation of e g * orbitals lengthens bonds Metals get smaller across period due to increasing Z M 3+ are smaller than M 2+ due to charge radii of M 2+ ions (pm) dndn high spin low spin radii of M 3+ ions (pm) dndn high spin low spin

Slide 12/21 The activation step involves making the bond lengths in oxidant and reductant the same:  if oxidant and reductant have very different bond lengths  activation energy is large  reaction is slow  if oxidant and reductant have similar bond lengths  activation energy is small  reaction is fast Outer Sphere e - Transfer metal ion pair Fe 2+ (aq) (d 6 ), Fe 3+ (aq) (d 5 ) difference in M-O bond lengths rate constant (M -1 s -1 ) 13 pm4 Cr 2+ (aq) (d 4 ), Cr 3+ (aq) (d 3 ) 18 pm 2  10 -5

Slide 13/21 A different and faster mechanism operates if  either the oxidant or the reductant possesses a ligand capable of bonding to two metals at once (“bridging”) AND  the other reactant is labile (able to exchange ligands Inner Sphere e - Transfer

Slide 14/21 The inner sphere reaction is possible as  Cl - has >1 lone pair so can bond to Cr and Co in the inner-sphere complex  Cr 2+ is labile (d 4 – Jahn-Teller distorted) Inner Sphere e - Transfer Note that  once e - transfer has occurred, it is the Co 2+ which is labile and Cr 3+ is inert  therefore bridging ligand leaves with Cr 3+

Slide 15/21 CrO 4 - is a powerful oxidizing agent: CrO H 2 O + 3e -  Cr(OH) 3 + 5OH - E 0 = +0.6 V Toxicity of CrO 4 - It acts as a skin irritant due to oxidation of organic molecules  however, as reduction is a 3e - process, it is metastable as few organic oxidations involve 3 electrons Erin Brockovich It therefore passes through the skin  it has a very similar structure to SO 4 2- and is therefore “allowed” to pass through cell and nuclear membranes In the cell nucleus  it slowly reduces to Cr(III) (by oxidizing DNA or proteins)  Cr 3+ binds to DNA and proteins causing mutations and cancers  Cr 3+ (d 3 ) is inert so it is very difficult to remove

Slide 16/21 Summary By now you should be able to.... Explain that the key steps in the outer sphere mechanism Explain why the activation step involves the bond lengths in oxidant and reductant becoming the same Explain why and predict why the difference in oxidant and reductant bond lengths affects the rate Explain the key steps in the inner sphere mechanism Predict whether an e transfer mechanism can occur via the inner sphere mechanism by looking for the presence of a bridging ligand on one reactant and the lability of the other reactant

Slide 17/21 Practice 1.Explain the differences in the rate constants for the following self-exchange, electron transfer reactions: [Fe(H 2 O) 6 ] 2+ + [Fe(H 2 O) 6 ] 3+  [Fe(H 2 O) 6 ] 3+ + [Fe(H 2 O) 6 ] 2+ k = 4 M -1 s -1 [Fe(bpy) 6 ] 2+ + [Fe(bpy) 6 ] 3+  [Fe(bpy) 6 ] 3+ + [Fe(bpy) 6 ] 2+ k > 10 6 M -1 s -1 [Co(NH 3 ) 6 ] 2+ + [Co(NH 3 ) 6 ] 3+  [Co(NH 3 ) 6 ] 3+ + [Co(NH 3 ) 6 ] 2+ k = 10  6 M -1 s -1 (Hint: bpy = bipyridyl, a strong-field ligand, [Co(NH 3 ) 6 ] 3+ is diamagnetic). 2. The rate of reduction of [Co(NH 3 ) 5 (H 2 O)] 3+ by Cr 2+ (aq) is seven orders of magnitude slower than reduction of its conjugate base, [Co(NH 3 ) 5 (OH)] 3+ by Cr 2+ (aq). The rates of the reduction of the same cobalt complexes by [Ru(NH 3 ) 6 ] 2+ differ by only a factor of 10. Explain these observations. (Hint: OH - is able to bridge)

Slide 18/21 Summary of Course – week 4 Ligand-field (‘d-d’) spectroscopy be able to predict/explain number of bands for d 1 -d 9 (high-spin) be able to calculate  oct for d 1, d 3, d 4, d 6, d 7, d 8 and d 9 be able to explain differences in band intensity (spin forbidden, orbitally forbidden, Laporte forbidden) be able to explain the appearance of charge transfer transitions be able to explain and predict the occurance of the Jahn-Teller effect and its consequences (structural, spectroscopic, reaction rates) Resources Slides for lectures 1-4 Shriver and Atkins “Inorganic Chemistry” Chapter 9 (4 th Edition) Housecroft and Sharpe “Inorganic Chemistry” Chapter (2 nd Edition)

Slide 19/21 Summary of Course – week 5 Complexes of  -acceptor ligands be able to explain synergic (  -donation,  -back donation) model for bonding in M-CO and M-N 2 complexes be able to explain reduction in CO stretching frequency in complex be able to explain changes in CO stretching frequency with metal charge and with ligands electron counting in CO, N 2 and NO complexes: 18 e - rule Resources Slides for lectures 5-6 Shriver and Atkins “Inorganic Chemistry” Chapter , (4 th Edition) Housecroft and Sharpe “Inorganic Chemistry” Chapter 23.2 (2 nd Edition)

Slide 20/21 Summary of Course – week 6 Metal-metal bonding be able to predict bond order for M 2 L x dimers using d-electron count and  and  molecular orbital diagram be able to predict bond order in larger metal-halide clusters using d- electron count shared over edges of cluster be able to predict bond order in metal carbonyl clusters using 18 e - rule Resources Slides for lectures 7-9 Shriver and Atkins “Inorganic Chemistry” Chapter 18.11, 21.20, Housecroft and Sharpe “Inorganic Chemistry” Chapter 23.6, 25 Reaction mechanisms be able to describe ligand exchange mechanisms be able to explain role of metal charge and LFSE in rate of ligand exchange be able to describe electron transfer reaction mechanisms be able to predict relative rate of outer sphere reaction for different metals