Unit 1 Lessons B, C, D, E Review **Note – This will also be posted online for your reference as you study. The answers are on the last slide.

1.Solve the equation. 2(x – 5) = 8 + 2x A) X = 8 B) X = -10 C) No solution D) All real numbers

2. Is it a function? What is the domain and range? A) Yes, Domain {4, 8, 9}, Range {-5, 3, 5, 7} B) Yes, Domain {-5, 3, 5, 7}, Range {4, 8, 9} C) No, Domain {4, 8, 9}, Range {-5, 3, 5, 7} D) No, Domain {-5, 3, 5, 7}, Range {4, 8, 9}

3. Is it a function? What is the domain and range? A) Yes, Domain all real #s, Range y ≥ -3 B) Yes, Domain all real #s, Range all real #s C) No, Domain -5 ≤ x ≤ 5, Range y ≥ -3 D) No, Domain x ≥ -3, Range all real #s

4. What is f(4)? A) -2 B) 1 C) 2 D) 3

5. What is f(0)? A) 0 B) -1 C) 2/3 D) 2

6. What is x if f(x) = 4? A) 4 B) 2 C) 0 D) -2

7. If f(x) = 8 – x, what is f(-2)? A) 16 B) 10 C) 6 D) -16

7. If f(x) = 8 – x, what is f(-2)? f(-2) = 8 – (-2) = = 10

8. If f(x) = -2x – 7, and f(x) = 9, what is x? A) -25 B) 9 C) -8 D) -1

8. If f(x) = -2x – 7, and f(x) = 9, what is x? f(x) = -2x – 7 9 = -2x – 7 16 = -2x -8 = x

9. Gas prices can be modeled by P(y) = 0.2y , where P = price per gallon and y = number of years since According to this model, what will the price be in 2015? A) $5.50 B) $62.50 C) $2.70 D) $4.50

9. Gas prices can be modeled by P(y) = 0.2y , where P = price per gallon and y = number of years since According to this model, what will the price be in 2015? P(15) = 0.2(15) = = 5.50

10. Graph the equation. Use slope- intercept form. -x + 2y = -10

10. Graph the equation. Use slope- intercept form. -x + 2y = -10 2y = x – 10 y = ½ x – 5

11.Graph the equation. x = 3

11.Graph the equation. x = 3

12. Write the equation of the line that passes through (-5, 2) and (-6, 4). A) y = -2x + 12 B) y = -2x - 8 C) y = ½x + 7 D) y = 2x + 16

12. Write the equation of the line that passes through (-5, 2) and (-6, 4).

13. Write the equation of the line that is perpendicular to y = 4x – 5 and passes through (8, 0). A) y = -¼x – 5 B) y = -¼x + 8 C) y = -¼x + 2 D) y = -¼x

13. Write the equation of the line that is perpendicular to y = 4x – 5 and passes through (8, 0). m = - ¼ y = - ¼ x + b 0 = - ¼ (8) + b 0 = -2 + b 2 = b y = - ¼ x + 2

14. Write the equation of the line that is parallel to 3x – 6y = 6 and passes through (-4, 1). A) y = ½x - 1 B) y = -2x - 7 C) y = -½x - 1 D) y = ½x + 3

14. Write the equation of the line that is parallel to 3x – 6y = 6 and passes through (-4, 1). - 6y = -3x + 6 y = ½ x – 1 m = ½ y = ½ x + b 1 = ½ (-4) + b 1 = -2 + b 3 = b y = ½ x + 3

15. Write the equation of the line shown. A) y = ½x - 1 B) y = -2x – 2 C) y = -½x - 2 D) y = -½x - 1

16. Write the equation of the line shown. A) y = -2 B) y = 0 C) x = -2 D) undefined

17. Write the equation of the line that has an undefined slope and passes through (6, -10). A) x = 6 B) y = -10 C) x = -5/3 D) y = 6x - 10

18. Are the lines parallel, perpendicular, or neither? 2x + 3y = 9 -½x + y = 7 A) Parallel B) Perpendicular C) Neither

18. Are the lines parallel, perpendicular, or neither? 2x + 3y = 9 3y = -2x + 9 y = -2/3 x + 3 -½x + y = 7 y = ½ x + 7 Slopes are not the same or opposite reciprocals.

19. Are the lines parallel, perpendicular, or neither? x = -4 x = ¼ A) Parallel B) Perpendicular C) Neither

20. In 2010, Bob’s salary was $62,000. Now in 2012, it is $65,000. Write a linear equation to model his salary if it continues to increase at this rate. Let S = salary and y = years since A) S = 3,000y + 62,000 B) S = 1,500y + 62,000 C) S = -3,000y + 65,000 D) S = y + 62,000

Answer Key 1.C 2.C 3.A 4.B 5.B 6.DSee me or the Math Resource Center if 7.Byou have any questions about these! 8.C 9.A 10.Graph (see slide) 11.Graph (see slide) 12.B 13.C 14.D 15.D 16.A 17.A 18.C 19.A 20.B