How do you think through and answer a real world problem involving cones?   For example: A conical glass flower vase has a base that is 6 inches in diameter and the vase holds approximately 113 cubic inches of water. What is the height of the vase? How do you think through and answer a real world problem involving cylinders?   Example: A cylindrical rain barrel has a radius of 1.5 ft and holds approximately 28.25 cubic ft of water. The barrel is three-quarters full. Find the approximate volume of water in the barrel.

In this lesson you will learn how to solve real world problems by finding the volume of cones.

B= πr2

in in2 in3 length area volume

V = 1 3 πr2h LearnZillion Notes: First we

V = 1 3 πr2h Given: radius = 3 in volume = 113 in3 Find: height = ??? LearnZillion Notes: we can now apply the idea that V=Bh to solve our original problem. Here we have a cylinder with radius 2 and height 7cm.

V = 1 3 πr2h 113 in3 = 1 3 π(3in)2 xh 113 in3 = 3πin2 xh height ≈ 12 in LearnZillion Notes: we can now apply the idea that V=Bh to solve our original problem. Here we have a cylinder with radius 2 and height 7cm.

V = 1 3 πr2h V = 1 3 π(2in)2 x 25.13 in3 = 1.33πin2 x 25.13 in3 ≈ 105 in5 Actual: h = 6 in

In this lesson you learned how to solve real world problems by finding the volume of cones. LearnZillion Notes: --This is the lesson conclusion. On this slide you’ll change your original lesson objective to past tense and explain what the student has just learned. You can retype it here or you can delete the text on this slide and then just copy and paste the text box from the original Lesson Objective slide and then edit it to make it past tense!

LearnZillion Notes: --The “Guided Practice” should include 1 practice problem that targets the skill that was used in the Core Lesson. Use the same vocabulary and process you used in the original lesson to solve this problem. You’ll be making a video in which you solve this question using your tablet and pen, so all you need to do is write the question on this slide.

113.1 cm3 = π(r)2 x9cm Find: radius= ?? r2 = 113.1 cm3 9π cm V = 1 3 πr2h 113.1 cm3 = π(r)2 x9cm r2 = 113.1 cm3 9π cm r = 4 cm2 = 2 cm Find: radius= ?? Given: height = 9 cm volume = 113.1 cm3 LearnZillion Notes: --The “Guided Practice” should include 1 practice problem that targets the skill that was used in the Core Lesson. Use the same vocabulary and process you used in the original lesson to solve this problem. You’ll be making a video in which you solve this question using your tablet and pen, so all you need to do is write the question on this slide.

LearnZillion Notes: --The “Guided Practice” should include 1 practice problem that targets the skill that was used in the Core Lesson. Use the same vocabulary and process you used in the original lesson to solve this problem. You’ll be making a video in which you solve this question using your tablet and pen, so all you need to do is write the question on this slide.

37.7 ft3 = 1 3 π(3ft)2 xh Find: height = ?? Given: diameter = 6 ft V = 1 3 πr2h 37.7 ft3 = 1 3 π(3ft)2 xh h = 37.7 ft3 3π ft2 h = 4 ft Find: height = ?? Given: diameter = 6 ft volume = 37.7 ft3 LearnZillion Notes: --The “Guided Practice” should include 1 practice problem that targets the skill that was used in the Core Lesson. Use the same vocabulary and process you used in the original lesson to solve this problem. You’ll be making a video in which you solve this question using your tablet and pen, so all you need to do is write the question on this slide.

LearnZillion Notes:

LearnZillion Notes: --”Quick Quiz” is an easy way to check for student understanding at the end of a lesson. On this slide, you’ll simply display 2 problems that are similar to the previous examples. That’s it! You won’t be recording a video of this slide and when teachers download the slides, they’ll direct their students through the example on their own so you don’t need to show an answer to the question.