Chemistry Raymond Chang 10 th edition Chapter 3 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display.

Slides:



Advertisements
Similar presentations
Chapter 3 Stoichiometry: Ratios of Combination
Advertisements

CHAPTER 3 STOICHIOMETRY. ATOMIC MASS Atoms are so small, it is difficult to discuss how much they weigh in grams. Use atomic mass units. an atomic mass.
Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations.
Chapter 3 Chemical Reactions and Reaction Stoichiometry
Excess.
Atomic Mass l Atoms are so small, it is difficult to discuss how much they weigh in grams. l Use atomic mass units. l an atomic mass unit (amu) is one.
Atomic Mass Atoms are so small, it is difficult to discuss how much they weigh in grams. Use atomic mass units. an atomic mass unit (amu) is one twelfth.
Raymond Chang 10th edition Chapter 4
Calculate the Molar Mass  Magnesium chloride Ammonium sulfate  Answers: g/mol; g/mol.
Quantities in Chemical Reactions Review Definitions $100 $200 $300 $400 $500 Quantities Balanced Chemical Equations Additional Calculations Team 1Team.
Anatomy of a Chemical Equation
CHAPTER 3b Stoichiometry.
Ch. 3 Stoichiometry: Calculations with Chemical Formulas.
 Atoms are so small, it is difficult to discuss how much they weigh in grams.  Use atomic mass units.  an atomic mass unit (amu) is one twelth the.
Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations.
Chapter 3: Calculations with Chemical Formulas
Atomic Mass l Atoms are so small, it is difficult to discuss how much they weigh in grams. l Use atomic mass units. l an atomic mass unit (amu) is one.
Final Information Open-ended: 6/11 (review 6/10) Last day to ask questions for MC 6/14 Topics: –Bonding –Reactions Chemical Equations (balancing, types)
Stoichiometry  2009, Prentice-Hall, Inc. Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations Chemistry, The Central Science, 11th.
Choose Your Category The MoleAverage Atomic Mass and Molar Mass FormulasPercentage Composition Limiting Reactants Percentage Yield and Error Vocab 100.
Chapter 3 Stoichiometry. Atomic Mass Carbon-12 is assigned a mass of exactly atomic mass units (amu) Masses of other elements are compared to Carbon-12.
Mass Relationships in Chemical Reactions Chapter 3 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display.
Mass Relationships in Chemical Reactions Chapter 3 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display.
Mass Relationships in Chemical Reactions Chapter 3 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display.
Mass Relationships in Chemical Reactions Chapter 3 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display. PowerPoint.
Stoichiometry Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations John D. Bookstaver St. Charles Community College St. Peters, MO.
Chemistry, The Central Science, 10th edition
Mass Relationships in Chemical Reactions Chapter 3 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display.
© 2012 Pearson Education, Inc. Chemical Equations Chemical equations are concise representations of chemical reactions.
Mass Relationships in Chemical Reactions Chapter 3 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display.
Mole, gas volume and reactions, Chemical energy and Enthalpy,
Moles and Stoichiometry Chapters 11 & 12. Counting Particles Particles are counted in moles Types of representative particles Atoms- smallest unit of.
Chapter 11 : Matter Notes. Mole (mol) is equal to 6.02x10 23 The mole was named in honor of Amedeo Avogadro. He determined the volume of one mole of gas.
© 2009, Prentice-Hall, Inc. Chapter 3: Stoichiometry Formula Weight A formula weight is the sum of the atomic weights for the atoms in a chemical formula.
Calculations with Chemical Formulas and Equations.
Stoichiometry! The heart of chemistry. The Mole The mole is the SI unit chemists use to represent an amount of substance. 1 mole of any substance = 6.02.
Stoichiometry Chapter 11 & 12. I. Things you should remember From the Moles Unit: Identify particles as atoms, molecules (mc), and formula units (fun)
1 The Mole 6.02 X What is “The Mole??” A counting unit (similar to a dozen) 6.02 X (in scientific notation) = 602 billion trillion = 602,000,000,000,000,000,000,000.
C HAPTER 3 - S TOICHIOMETRY. 3.1 – A TOMIC M ASSES Carbon-12, the relative standard C-12 is assigned a mass of exactly 12 atomic mass units (amu) Masses.
Stoichiometry: Ratios of Combination
Chemical quantities Chapter Ways to measure matter Length/width/height Volume Density Surface Area Etc.
Molar Mass Mole to Mole Mass to mass Avogadro’s Number Grab Bag
Unit 4: Formula Stoichiometry. What is stoichiometry? Deals with the quantitative information in chemical formula or chemical reaction. Deals with the.
NOTES: Quantifying Chemical Compounds Chapter 11.
Stoichiometry. What is stoichiometry? Involves the mass relationships between reactants and products in a chemical reaction ▫Based on the law of conservation.
Chapter 3: Stoichiometry: Calculations with Chemical Formulas and Equations AP Chemistry
AP CHEMISTRYNOTES Ch 3 Stoichiometry. 3.1 Counting by Weighing Find the average mass = total mass of substance / number of substance.
Chapter 3 Review.
Mass Relationships in Chemical Reactions
Mass Relationships in Chemical Reactions
Moles Noadswood Science, 2016.
John D. Bookstaver St. Charles Community College Cottleville, MO
Drill – Predict why some reactions do not occur..
St. Charles Community College
Chemical Reactions Unit
Chapter 12 Review.
Chapter 12 Review.
Mass Relationships in Chemical Reactions
Mass Relationships in Chemical Reactions
Stoichiometry Review.
Stoichiometry Chapter 11.
Mass Relationships in Chemical Reactions
Mass Relationships in Chemical Reactions
Mass Relationships in Chemical Reactions
Mass Relationships in Chemical Reactions
Chemical Reactions, Chemical Equations, and Stoichiometry
Mass Relationships in Chemical Reactions
Chemistry Calculations
III. Formula Calculations (p )
Stoichiometry: Ratios of Combination
Presentation transcript:

Chemistry Raymond Chang 10 th edition Chapter 3 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display.

Question 1 A mole of carbon (molar mass about 12) contains fewer atoms than a mole of oxygen (molar mass about 16). A) True B) False

Question 2 One atom of oxygen weighs about 16 g. A) True B) False

Question 3 One atom of carbon weighs about 12 amu. A) True B) False

Question 4 One mole of carbon weighs about 12 g. A) True B) False

Question 5 If the ratio of moles of carbon to hydrogen in a hydrocarbon compound is found by experiment to be : then the most likely empirical formula is A) C 2 H 3. B) C 15 H 30. C) C 2 H 6. D) CH 2.

Question 6 If 1.00 g of a compound composed of hydrogen and oxygen is found to contain 0.94 g oxygen, then which of the following molecular formulas is likely? A) H 2 O B) H 2 O 2 C) HO 2 D) None of the above

Question 7 Which of the following chemical equations represents the decomposition of solid calcium carbonate to yield oxygen gas and solid calcium oxide? 1. A) CaCO 2(s) → CaO (s) + O 2(g) 2. B) CaCO 3(s) → CaO (s) + O 2(l) 3. C) CaCO 3(s) → CaO (s) + O (g) 4. D) CaCO 3(s) → CaO (s) + O 2(g)

Question 8 How many moles of Zn would be required to produce 4 moles of hydrogen gas using the following reaction? Zn (s) + 2HCl (aq) → ZnCl 2(aq) +H 2(g) A) 8 mol B) 4 mol C) 2 mol D) 1 mol

Question 9 How many moles of Zn would be required to completely react with 1 mole of HCl using the following reaction? Zn (s) + 2HCl (aq) → ZnCl 2(aq) +2H 2(g) A) 0.5 mol B) 1 mol C) 2 mol D) 4 mol

Question 10 How much zinc chloride could be made from one mole of Zn and 1 mole of HCl if the reaction is? Zn (s) + 2HCl (aq) → ZnCl 2(aq) +H 2(g) A) 1 mol B) 2 mol C) 0.5 mol D) 0 mol since the molar ratio is incorrect

Question 11 Avogadro's number represents A) the number of particles in a mole. B) the ratio between 1 g and 1 amu. C) the ratio between the molar mass of NaCl and the molecular mass of NaCl. D) the ratio between the molar mass of Cu and the average atomic mass of Cu. E) all of the above.

Question 12 Which of the following statements is/are true? A) mol sodium weighs g B) mol sodium chloride contains x10 24 ions C) 1.0 mol of aluminum chloride contains twice as many ions as 1.0 mol of sodium chloride D) All of the above E) None of the above

Question 13 What is the mass of 1.0 kmol of water? A) 18 g B) 18 amu C) 18 kg D) 1000 amu E) None of the above

Question 14 The mass % of manganese in potassium permanganate is A) %. B) %. C) %. D) %. E) None of the above.

Question 15 The empirical formula of mercurous chloride is A) Hg 2 Cl 2. B) HgCl. C) HgCl 2. D) Hg 2 Cl. E) (HgCl)n.

Question 16 The mass percent composition of an oxoacid of sulfur is : 1.75 % H, % S, % O. Determine the empirical formula of the acid. A) H 2 SO 4 B) H 2 SO 3 C) H 2 S 2 O 3 D) H 2 SO 5 E) HSO 1.5

Question 17 The chemical equation (NH 4 ) 2 Cr 2 O 7 → Cr 2 O 3 + N 2 + 4H 2 O tells us the following: A) From 1 mol of (NH 4 ) 2 Cr2O7 we get 1 mol of Cr 2 O 3 B) From 1 mol of (NH 4 ) 2 Cr 2 O 7 we get 1 mol of N 2 C) From 1 mol of (NH 4 ) 2 Cr 2 O 7 we get 4 mol of H 2 O D) All of the above E) None of the above

Question 18 A balanced chemical equation tells us: A) The ratios of moles of reactants that participate in the reaction. B) The ratios of moles of products that are formed in the reaction. C) That we can calculate the amount of a reactant needed based on how much of a specific product we need. D) That we can calculate the amount of product formed based on the amount of one reactant and excess of other reactants. E) All of the above.

Question 19 Given the reaction: SO 3 (g) + H 2 O(g) → H 2 SO 4 (l), calculate the amount of sulfur trioxide necessary to produce 196 kg sulfuric acid assuming 100% yield. A) 80 kg B) 80 g C) 160 g D) 160 kg E) None of the above

Question 20 Given the reaction: SO 3 (g) + H 2 O(g) → H 2 SO 4 (l), which proceeds with a yield of 85.0%, calculate the amount of sulfuric acid that is formed when 120. kg sulfur trioxide is mixed with 32.4 kg water. A) 147 kg B) 125 kg C) 176 kg D) 150 kg E) None of the above

Answer Key – Chapter 3 1. B 2. B 3. A 4. A 5. D 6. B 7. D 8. C 9. A 10. C 11. E 12. D 13. C 14. B 15. B 16. C 17. D 18. E 19. D 20. B