Chapter 9 Stoichiometry.

Slides:



Advertisements
Similar presentations
Stoichiometry: The study of quantitative measurements in chemical formulas and reactions Chemistry – Mrs. Cameron.
Advertisements

VI. Organic Compounds = carbon containing compounds
Reaction Stoichiometry Chapter 9. Reaction Stoichiometry Reaction stoichiometry – calculations of amounts of reactants and products of a chemical reaction.
Chapter 12 Stoichiometry.
Chemical Quantities Chapter 9
Stoichiometry Chapter 12.
Copyright © Houghton Mifflin Company. All rights reserved. 9 | 1 Information Given by the Chemical Equation Balanced equations show the relationship between.
Zumdahl • Zumdahl • DeCoste
Stoichiometry Chap. 12. I.What is stoichiometry? Study of quantitative relationships between amounts of reactants and products.
Mathematics of Chemical Equations By using “mole to mole” conversions and balanced equations, we can calculate the exact amounts of substances that will.
Chapter 9 Chemical Quantities. 9 | 2 Information Given by the Chemical Equation Balanced equations show the relationship between the relative numbers.
Unit 4 Lecture 4 - Limiting Reactants
Stoichiometry.
Stoichiometry.
Limiting Reagents and Percent Yield
Stoichiometry The Math of Chemical Reactions Unit 9.
Unit 8: Percent Yield Calculations
Classic Butter Cookies 2 1/2 cups all-purpose flour 1 cup butter 1/2 cup white sugar 2 eggs 1/2 teaspoon almond extract Bake at 350ºF for 10 minutes.
The Math of Equations Stoichiometry
Chapter 3 - Stoichiometry It is important to be able to quantify the amount of reagent(s) that will be needed to produce a given amount of product(s).
Stoichiometry Needs a balanced equation Use the balanced equation to predict ending and / or starting amounts Coefficients are now mole ratios.
1 Chapter 9-Stoichiometry Stoichiometry – measures and calculates amounts of chemicals in a reaction. A.Mole/Mole Problems Coefficients: Show # of molecules.
Chapter 12 Stoichiometry part 1. Stoichiometry The study of quantitative relationships between amounts of reactants used and products formed by a chemical.
Chapter 12 Stoichiometry.
Chapter 11 Stoichiometry.
Unit 8~ Stoichiometry Most of your notebooks are NOT graded. Please make sure to leave them in the same stack (NEATLY) after taking notes for me to grade!
Things you must KNOW and what to expect  Things you must KNOW  You must KNOW your polyatomics  You must KNOW how to write a balanced formula  You have.
Stoichiometry Chapters 7 and 9.
Stoichiometry Calculations based on Chemical Reactions.
Test Review Chemical Reactions and Stoichiometry.
Stoichiometry – “Fun With Ratios” Main Idea: The coefficients from the balanced equation tell the ratios between reactants and products. This ratio applies.
Stoichiometry Notes (Chapter 9). I. Problems Involving Compounds a. Compounds are measured in molecules (or formula units) and single elements are measured.
Stoichiometry. Information Given by the Chemical Equation  The coefficients in the balanced chemical equation show the molecules and mole ratio of the.
I. I.Stoichiometric Calculations Topic 9 Stoichiometry Topic 9 Stoichiometry.
Chapter 9 Notes I Stoichiometry. Stoichiometry Calculations of quantities in chemical reactions This means using balanced equations to calculate quantities.
Chapter 9 Chemical Quantities. Copyright © Houghton Mifflin Company. All rights reserved. 9 | 2 Information Given by the Chemical Equation Balanced equations.
The Mole & Stoichiometry!
Solving a Stoichiometry Problem 1.Balance the equation. 2.Convert given to moles. 3.Determine which reactant is limiting. 4.Use moles of limiting reactant.
The Math of Chemical Reactions
CHAPTER 9 Design: Winter Colors: Elemental STOICHIOMETRY.
Stoichiometry Warmup I have 1 mole of CO 2 gas at STP. How many grams of CO 2 do I have? How many Liters of CO 2 do I have? How many molecules of CO 2.
Chapter 12: Stoichiometry
Warm Up 5.5: Determine all possible Mole Ratio’s from last class’s warm up 1.2NH 3 + H 2 SO 4  (NH 4 ) 2 SO C 5 H 9 O + 27 O 2  20 CO H.
Video 9-1 Reaction Stoichiometry Steps for Problem Solving.
Copyright©2004 by Houghton Mifflin Company. All rights reserved. 1 Introductory Chemistry: A Foundation FIFTH EDITION by Steven S. Zumdahl University of.
Can’t directly measure moles Measure units related to moles: –Mass (molar mass) –Number of particles (6.02 x ) –Liters of gas (22.4 Liters at STP)
Chapter 9-Stoichiometry 9.1-Introduction to Stoichiometry 9.2-Ideal Stoichiometric Calculations 9.3-Limiting Reactants & Percent Yield.
Unit 9: Stoichiometry Chapter 12 Exam: February 11, 2009.
Stoichiometry Notes (Chapter 12). Review of Molar Mass Recall that the molar mass of a compound is the mass, in grams, of one mole of that compound.
When gases react, the coefficients in the balanced chemical equation represent both molar amounts and relative volumes. Section 3: Gas Stoichiometry K.
Chapter 12 Stoichiometry. Stoichiometry Topics Conservation of mass and the balanced chemical equation Mole ratios in a chemical equation Stoichiometric.
Chemistry Chapter 9 - Stoichiometry South Lake High School Ms. Sanders.
Challenge Problem When nitrogen and hydrogen react, they form ammonia gas, which has the formula NH 3. If 56.0 g of nitrogen are used up in the reaction,
Mass-Mass Conversions 56.0 g N 2 x g N 2 g NH = 1904 = When nitrogen and hydrogen react, they form ammonia gas, which has the formula.
Ch. 12 Stoichiometry Objective: To learn how to use a complete chemical equation to calculate quantities of a substance.
Solving a Stoichiometry Problem
Stoichiometry II.
Chemistry: Chapter 11 Note Packet
Stoichiometry Stoichiometry: is the study of the calculations of amounts of substances involved in chemical equations.
Chemical Reactions Unit
Ch. 9: Calculations from Chemical Equations
Chapter 12 Review.
Chapter 12 Review.
Stoichiometry Review.
Stoichiometry Chapter 11.
Mathematics of Chemical Equations
Reaction Stoichiometry
Unit 4: Chemical Equations and Stoichiometry
9.1 NOTES Stoichiometry.
Presentation transcript:

Chapter 9 Stoichiometry

9.1 & 9.2 Ideal Stoichiometric Calculations Stoichiometry - the study of the quantitative measurement problems between chemical formulas, reactions and equations.

Atoms, molecules, particles The Mole Map Liters Atoms, molecules, particles Grams Mole 22.4 L 6.022 x1023 Molar Mass

Stoichiometric Conversions Quick Review using the mole map Ex1: 0.15 mol NaOH convert to grams Ex2: 9.00g MgCl2 convert to atoms of Chlorine

Stoichiometric Conversions Reaction stoichiometry Example - combustion of propane: C3H8 + __O2  __CO2 + __H2O Thus, for every 1 propane, 5 moles of diatomic oxygen are required to produce 3 moles of carbon dioxide and 4 moles of water.

The New Mole Map Mole Grams Liters Molecules Coefficients Molecules

Stoichiometric Conversions Four Core Steps: Step #1 Write a BALANCED equation Step #2 Go to moles Step #3 Mole to Mole - cross the bridge Step #4 Go to the desired unit

Stoichiometric Conversions Ex1: How many moles of water vapor are created from 2 moles of Hydrogen? Balanced equation Go to Mole Mole to Mole Desired Unit

Stoichiometric Conversions Ex2: How many grams of water vapor are created from 64.0 grams of Oxygen? Balanced equation 2H2(g) + O2(g)  2H2O(g) Go to Mole Mole to Mole Desired Unit

Stoichiometric Conversions Ex3: How many liters of H2O (g) are made from 5.00 L of Oxygen? Balanced equation 2H2(g) + O2(g)  2H2O(g) Go to Mole Mole to Mole Desired Unit

Stoichiometric Conversions Ex4: How many Liters of Oxygen are needed to react with 14.40 g C5H12? Balanced equation Go to Mole Mole to Mole Desired Unit

Stoichiometric Conversions Ex5: How many grams of solid lithium hydroxide are needed to react with 8.50 grams of carbon dioxide gas? (Lithium hydroxide + carbon dioxide yields Lithium carbonate and water) 9.23g LiOH

Stoichiometric Conversions Ex6: How many grams of water are produced from 2.00 moles of carbon dioxide and excess amount of lithium hydroxide? 36.0g Ex7: How many moles of lithium carbonate are produced from 152 grams of carbon dioxide and an excess amount of lithium hydroxide? 3.45mol

9.3 Limiting Reactant Problems and % Yield... The Limiting Reactant causes the reaction to stop…it is the reactant that is all used up in the chemical reaction.

Limiting Reactant Ex1: How many grams of Magnesium Chloride can be made from 3.64 g of magnesium and 7.10 g of Chlorine gas? a: How much of the excess reactant did you use? b: What percent of the excess was unused? ……

Limiting Reactant How many grams of Magnesium Chloride can be made from 3.64 g of magnesium and 7.10 g of Chlorine gas?

Limiting Reactant How much of the excess reactant did you use?

Limiting Reactant What percent of the excess was unused?

Limiting Reactant and % Yield .From the equation: 2 HCl + Zn  ZnCl2 + H2 How many liters of H2 can be made starting with 20.0 grams of Zn and 25.5 g HCl? How many grams of Zinc chloride will be made? Identify the limiting and excess reactants. How much of the excess reactant is needed? How much of the excess reactant is left over?

Limiting Reactant 2 HCl + Zn  ZnCl2 + H2 How many liters of H2 can be made starting with 20.0 grams of Zn and 25.5 g HCl?

Limiting Reactant 2 HCl + Zn  ZnCl2 + H2 How many grams of Zinc chloride will be made?

Limiting Reactant 2 HCl + Zn  ZnCl2 + H2

Limiting Reactant Identify the limiting and excess reactants. How much of the excess reactant is needed? How much of the excess reactant is left over?

% Yield % yield = mass produced x 100 mass theoretically produced

% Yield Ex1: If combusting 9.62 g of SO2 produces 11.95 g of SO3, calculate the % yield.

So, if the % yield is ________, then the actual yield is: Ex2: Reacting 4.20 grams of Nitrogen with 0.800 g of Hydrogen produces ?g of NH3 if there is a 75.5 % yield? Thus, the limiting reactant, H2, theoretically produces _________ grams of NH3. So, if the % yield is ________, then the actual yield is: