X=0 x<5 “Hai” X=X+1 True False XX<5? Output DO-WHILE x=0; do { cout<<“Hai”; x++; } while(x<5);

Slides:



Advertisements
Similar presentations
The Important Thing About By. The Important Thing About ******** The important thing about ***** is *****. It is true s/he can *****, *****, and *****.
Advertisements

Warm Up Example 1 Check whether the ordered pair is a solution of 2x – 3y > -2 a.(0,0) 2(0)-3(0)> -2 0> -2 True b.(0,1) 2(0)-3(1)> -2 -3> -2 False.
The "if structure" is used to execute statement(s) only if the given condition is satisfied.
CDA 3100 Recitation Week 10.
X=0 x
Universal Gates Sum of Products Products of Sum
Section 4.2: Functions that Test Conditions (continued)
Do/while Structure (L15) * do/while structure * break Statement * continue Statement * Loop Programming Techniques - Interactive input within a loop -
True/False. False True Subject May Go Here True / False ? Type correct answer here. Type incorrect answer here.
 x (x 2  0) 1. True2. False.  x (3x + 2 = 12) 1. True2. False.
Graph G is shown: And 7 of its subgraphs are: How many of these subgraphs are induced?
Determine whether each curve below is the graph of a function of x. Select all answers that are graphs of functions of x:
Generalized De Morgan’s Theorem Lecture L5.4 Section 5.1.
PolynomdivisionPolynomdivision. (x 3 – 3 x 2 – 2 x + 4) : (x – 1) =
9/9/2011 ©Evergreen Public Schools Rate Of Change Key Concepts : rate of change slope slope formula.
Notes 2.4 Number Patterns: Prime Factorization A prime number has exactly two factors: 1 and itself. Two is the only even prime number. A composite number.
Chapter 61 More about Loop Do ….. Loop Write Down “Do” and “Loop”
1. 3 x = x 3 2. K + 0 = K (3 + r) = (12 + 3) + r 4. 7 (3 + n) = n Name the Property Commutative of Multiplication Identity of Addition.
2.8 – Graphing Inequalities. Steps for graphing inequalities:
Инвестиционный паспорт Муниципального образования «Целинский район»
LOOPS In the Name of Allah The Most Merciful The Most Compassionate LOOPS
Combination of logic gates  Logic gates can be combined to produce more complex functions.  They can also be combined to substitute one type of gate.
(x – 8) (x + 8) = 0 x – 8 = 0 x + 8 = x = 8 x = (x + 5) (x + 2) = 0 x + 5 = 0 x + 2 = x = - 5 x = - 2.
 In computer programming, a loop is a sequence of instruction s that is continually repeated until a certain condition is reached.  PHP Loops :  In.
int num = 22; if (num > 0) if (num % 5 == 0) System.out.println(num); else System.out.println(num + “ is negative”);
A: A: double “4” A: “34” 4.
1 st Semester Module4-1 Iteration statement - while อภิรักษ์ จันทร์สร้าง Aphirak Jansang Computer.
Chapter 1 Review - Get a whiteboard and marker per pair - Take out a blank sheet of paper.
4.3 Solving Systems of Linear Inequalities 11/7/12.
Title Category #1 Category #2 Category #3Category #
照片档案整理 一、照片档案的含义 二、照片档案的归档范围 三、 卷内照片的分类、组卷、排序与编号 四、填写照片档案说明 五、照片档案编目及封面、备考填写 六、数码照片整理方法 七、照片档案的保管与保护.
공무원연금관리공단 광주지부 공무원대부등 공적연금 연계제도 공무원연금관리공단 광주지부. 공적연금 연계제도 국민연금과 직역연금 ( 공무원 / 사학 / 군인 / 별정우체국 ) 간의 연계가 이루어지지 않고 있 어 공적연금의 사각지대가 발생해 노후생활안정 달성 미흡 연계제도 시행전.
Жюль Верн ( ). Я мальчиком мечтал, читая Жюля Верна, Что тени вымысла плоть обретут для нас; Что поплывет судно громадней «Грейт Истерна»; Что.
מאת: יעקב דדוש. פיסול –בין יחיד לרבים יחידה 1 לתלמיד המתבונן לפניך שתי יצירות פיסוליות. התבונן וכתוב (בשקופית הבאה) מהם ההבדלים בין הפסלים המוצגים לפניך?
LESSON 5 Loop Control Structure. Loop Control Structure  Operation made over and over again.  Iterate statement.
ЛАТИНСКА АМЕРИКА И Колонизирането на Африка. РЕЧНИК: експанзия разширяване империализъм създаване и поддържане на неравностойни икономически, културни.
Control Structures.
Which polynomials have a Greatest Common Factor of 3x2 ?
Factors, multiple, primes: Factors from prime factors
Loop Control Structure.
Computers & Programming Languages
البرمجة بلغة الفيجول بيسك ستوديو
Who Wants To Be A Millionaire?
Factors, multiple, primes: Prime factors
True or False: {image} is one-to-one function.
Order of Operations Properties Distributive 2/22/2019 Verbal
Find the reference angle for the angle measuring {image}
Bellwork Solve by graphing y < x + 2 y > -1/2x + 5.
Decimals: Multiplying by 2.5
Evaluating Boolean expressions
© T Madas.
Straight line graphs: Horizontal and vertical lines
Variables and Equations
Composition & Inverses Review
Solving Systems by Substitution
Chapter 2 Sets Active Learning Lecture Slides
Inequalities TRUE FALSE.
Factors, multiple, primes: Multiples
Fractions: Simplifies to a unit fraction?
Straight line graphs: Horizontal and vertical lines
Algebra 1 Warm Ups 12/11.
Standard Form: Multiplying powers of 10
If there is any case in which true premises lead to a false conclusion, the argument is invalid. Therefore this argument is INVALID.
MENTAL MATH Here We Go….
A-Geometry Ch 6 Review Prize Show.
Standard form: In standard form?
True or False True or False
Coordinates: Naming 2D coordinates – quadrant 1
If there is any case in which true premises lead to a false conclusion, the argument is invalid. Therefore this argument is INVALID.
Digital Logic Design.
Presentation transcript:

X=0 x<5 “Hai” X=X+1 True False XX<5? Output DO-WHILE x=0; do { cout<<“Hai”; x++; } while(x<5);

XX<5? Output 0 X=0 x<5 “Hai” X=X+1 True False

XX<5? Output 0 X=0 x<5 “Hai” X=X+1 True False Hai

X=0 x<5 “Hai” X=X+1 True False XX<5? Output 0 Hai 1

X=0 x<5 “Hai” X=X+1 True False XX<5? Output 0 Hai 1 True

X=0 x<5 “Hai” X=X+1 True False XX<5? Output 0 Hai 1 True Hai

X=0 x<5 “Hai” X=X+1 True False XX<5? Output 0 Hai 1 True Hai 2

X=0 x<5 “Hai” X=X+1 True False XX<5? Output 0 Hai 1 True Hai 2 True

X=0 x<5 “Hai” X=X+1 True False XX<5? Output 0 Hai 1 True Hai 2 True Hai

X=0 x<5 “Hai” X=X+1 True False XX<5? Output 0 Hai 1 True Hai 2 True Hai 3

X=0 x<5 “Hai” X=X+1 True False XX<5? Output 0 Hai 1 True Hai 2 True Hai 3 True

X=0 x<5 “Hai” X=X+1 True False XX<5? Output 0 Hai 1 True Hai 2 True Hai 3 True Hai

X=0 x<5 “Hai” X=X+1 True False XX<5? Output 0 Hai 1 True Hai 2 True Hai 3 True Hai 4

X=0 x<5 “Hai” X=X+1 True False XX<5? Output 0 Hai 1 True Hai 2 True Hai 3 True Hai 4True

X=0 x<5 “Hai” X=X+1 True False XX<5? Output 0 Hai 1 True Hai 2 True Hai 3 True Hai 4True Hai

X=0 x<5 “Hai” X=X+1 True False XX<5? Output 0 Hai 1 True Hai 2 True Hai 3 True Hai 4True Hai 5

X=0 x<5 “Hai” X=X+1 True False XX<5? Output 0 Hai 1 True Hai 2 True Hai 3 True Hai 4True Hai 5False