Start By Ezekiel Dawson Stoichiometry.

Slides:

Advertisements

Similar presentations

Can you tell the letter each picture begins with?

Advertisements

STOICHIMETRY Limiting Reagents

Limiting Reactants and Percent Yield

Higher Chemistry Unit 1(a) Identifying a reactant in excess.

Limiting Reagent  1. Limits or determines the amount of product that can be formed  2. The reagent that is not used up is therefore the excess reagent.

Limiting Reactant. + ? 2B + S ?

Limiting Reactant + ? 2B + S ? +

 Balance the following equation.  Fe + O 2  Fe 2 O 3  4Fe + 3O 2  2Fe 2 O 3  This means that when we combine four atoms of iron with three molecules.

Limiting Reagents. If you are making tricycles, and you have 23 wheels, 20 handlebars, and 53 seats, how many tricycles can you make? 23 w (1 tricycle/

Chapter 9 Notes Part I Mole to Mole Calculations.

Limiting Reagent Problem. Calculate the mass of aluminum chloride that can be produced from 20.0 g of aluminum and 30.0 g of chlorine gas. Step 1: Write.

9.3 Notes Limiting reagents.

Limiting Reagents and Percent Yield

Solving Equations = 4x – 5(6x – 10) -132 = 4x – 30x = -26x = -26x 7 = x.

Limiting Reagents Stoichiometry Luckett. What is a limiting reagent? The reagent (reactant) that determines the amount of product that can be formed by.

12.3 Limiting Reagent and Percent Yield

/t/ / I d/ /d/ Try Again Go on /t/ / I d/ /d/

and cooking with chemicals

The Math of Equations Stoichiometry

Aim: Using mole ratios in balanced chemical equations.

Equivalent Weight of Magnesium

 All stoichiometry problems start with a balanced equation.  You must check for this!  If it is not balanced, BALANCE IT!

Chapter 9 Stoichiometry. Definition of “Stoichiometry”: the mathematics of chemical equations Important Concepts: 1. You MUST have a balanced equation!

Stoichiometry. I. Quantity in Chemical Reactions  (stoicheion) = element  (metreion) = measurement Stoichiometry = measurement of the.

Stoichiometry Ashley Thomson Period 8 April 10, 2011 Begin!

Calculation of excess In an excess calculation you will be given

Calculations in Chemistry To calculate the number of moles in a solid we use the following Mole Triangle g n gfm g = Mass in Grams n= Number of moles gfm=gram.

Solving Stoichiometry Problems

Chemical Equations. Chemical equations Represent chemical change Reactants Products (Starting (Substances Materials) Produced)

Stoichiometry By: Cierra Frymark. The Question How many grams of NH 3 can be produced from the reaction of 28g of N 2 and 25g of H 2 ?

Home Page 1 Write out the answer on your own paper and raise your hand when you are finished. Factoring Mini-Quiz: 2345.

THE MAGIC OF SUBTRACTION 2009 Quinín Freire 1 LEARNING.

Stoichiometry. Reading Equations using Moles Ca + H 2 SO 4 CaSO 4 + H 2 The above reaction reads: 1 amount of Ca reacts with 1 amount of H 2 SO 4 to give.

By: Barbara Goodwin Pd. 7 April 2009 BEGIN. When steam (hot water) is passed over iron, hydrogen gas and iron (III) oxide are formed. What weight of steam.

 If you have 3.2 g of magnesium to start with (and plenty of oxygen) how many grams of MgO will be produced in this reaction? Mg + O 2  MgO.

Continuing Stoichiometry…. The idea.  In every chemical reaction, there is one reactant that will be run out (called the limiting reactant).  This will.

By: Destina Slone May 9, How much ammonium hydroxide is needed to react completely with 75.0g of copper (II) nitrate in a double replacement reaction?

Stoichiometry and cooking with chemicals.  Interpret a balanced equation in terms of moles, mass, and volume of gases.  Solve mole-mole problems given.

Balancing Equations H 2 + Cl 2 → HCl. Balancing Equations KI + Br 2 → KBr + I 2.

Balancing Equations. Chemical Reactions   All chemical reactions can be represented by an equation.   The arrow means that a reaction has taken place.

Mol ratio: coefficients of a balanced equation 2 H 2 + O 2 → 2 H 2 O 2 mol H 2 for every 1 mol O 2 In chemical calculations, mol ratios convert moles of.

Stoichiometry Page 39. Essential Question How can the mole ratio of a chemical equation be determined and used for conversions?

Calculations using balanced chemical equations Revision

Stoichiometry Chapter 12.

AQA GCSE QUANTITATIVE CHEMISTRY 1

UNIT 9: STOICHIOMETRY.

Limiting Reagents.

Solving Stoichiometry Problem

Stoichiometry Ch 9.

EQUATIONS AND DIAGRAMS

2 H2 + O2 → 2 H2O 2 mol H2 for every 1 mol O2

Workbook 1 Pages

Section 2: Stoichiometric Calculations

UNIT 7: STOICHIOMETRY.

STOICHIOMETRY – To determine, using stoichiometric calculations, the quantity of a substance involved in a chemical reaction. 5.8 – To solve numerical.

m n SOLVING EQUATIONS How many sweets were in each type of bag?

Lesson 2 LT: I can explain how a voltaic cell works.

Limiting Reactants and Percent Yield

Warm-up 50 grams of H2O 100 grams of CaCO3 150 grams of NaOH

Stoichiometric Calculations

Limiting Reactants and Percent Yield

Solving Stechiometry Problems

Practice Chemical Reactions and Balancing Equations

Balanced scales and equations

e.g. H2O. Mass of hydrogen = 1. Mass of oxygen = 16.

Presentation transcript:

start By Ezekiel Dawson Stoichiometry

Problem Mg + HCL MgCl2 + H2 What volume of hydrogen is produced from the reaction of 50.0g of mg and the equivalent of 75g of HCL? What do you think goes first? Balance equation Pray 1 mol Mg 1 mol H2

What volume of hydrogen is produced from the reaction of 50 What volume of hydrogen is produced from the reaction of 50.0g of mg and the equivalent of 75g of HCL? Mg + 2HCL MgCl2 + H2 Great job! Now what? 1 50gMg 50g Mg 1 1 mol Mg 1

Try again

Try again

What volume of hydrogen is produced from the reaction of 50 What volume of hydrogen is produced from the reaction of 50.0g of mg and the equivalent of 75g of HCL? Mg + 2HCL MgCl2 + H2 50g Mg 1 Then? 1 mol Mg 25.3g Mg 25.3g Mg 1 mol Mg 1 mol Mg 32.1g Mg

Previous page

What volume of hydrogen is produced from the reaction of 50 What volume of hydrogen is produced from the reaction of 50.0g of mg and the equivalent of 75g of HCL? Mg + 2HCL MgCl2 + H2 50g Mg 1 mol Mg 1 25.3g Mg 1 mol H2 1 mol Mg And now? 1 mol Mg 1 mol H2 1 mol Mg 25.3g Mg

Back

What volume of hydrogen is produced from the reaction of 50 What volume of hydrogen is produced from the reaction of 50.0g of mg and the equivalent of 75g of HCL? Mg + 2HCL MgCl2 + H2 50g Mg 1 mol Mg 1 mol H2 1 25.3g Mg 1 mol Mg 22.4L H2 1 mol H2 1 mol H2 22.4L H2 solve

Previous page

What volume of hydrogen is produced from the reaction of 50 What volume of hydrogen is produced from the reaction of 50.0g of mg and the equivalent of 75g of HCL? Mg + 2HCL MgCl2 + H2 Next? 50g Mg 1 1 mol Mg 25.3g Mg 1 mol Mg 1 mol H2 22.4L H2 1 mol H2 ? 2g H2 1 mol H2 scream! calculate

Try again Nice Try 

Set up another equation What volume of hydrogen is produced from the reaction of 50.0g of mg and the equivalent of 75g of HCL? Mg + 2HCL MgCl2 + H2 1 mol H2 1 mol Mg 22.4L H2 1 mol H2 50g Mg 1 1 mol Mg 25.3g Mg 44.3L H2 Now What? Set up another equation finish Go to website for help

What volume of hydrogen is produced from the reaction of 50 What volume of hydrogen is produced from the reaction of 50.0g of mg and the equivalent of 75g of HCL? Mg + 2HCL MgCl2 + H2 50g Mg 1 1 mol Mg 25.3g Mg 1 mol H2 1 mol Mg 22.4L H2 1 mol H2 44.3L H2 Now, what do you start with? 75g HCL 1 50.0g HCL 1 75g Mg 1

What volume of hydrogen is produced from the reaction of 50 What volume of hydrogen is produced from the reaction of 50.0g of mg and the equivalent of 75g of HCL? Mg + 2HCL MgCl2 + H2 50g Mg 1 1 mol Mg 25.3g Mg 1 mol H2 1 mol Mg 22.4L H2 1 mol H2 44.3L H2 75g HCL 1 Fantastic! And now? 1 mol HCL 25.3g HCL 1 mol HCL 36.5g HCL 36.5g HCL 1 mol HCL

Go Back Oops!

Previous Page

What volume of hydrogen is produced from the reaction of 50 What volume of hydrogen is produced from the reaction of 50.0g of mg and the equivalent of 75g of HCL? Mg + 2HCL MgCl2 + H2 50g Mg 1 1 mol Mg 25.3g Mg 1 mol H2 1 mol Mg 22.4L H2 1 mol H2 44.3L H2 75g HCL 1 1 mol HCL 36.5g HCL What next? you've got skills! 1 mol HCL 1 mol H2 22.4L 1 mol HCL 1 mol H2 2 mol HCL

Run back Uhh Ohh!

What volume of hydrogen is produced from the reaction of 50 What volume of hydrogen is produced from the reaction of 50.0g of mg and the equivalent of 75g of HCL? Mg + 2HCL MgCl2 + H2 50g Mg 1 1 mol Mg 25.3g Mg 1 mol H2 1 mol Mg 22.4L H2 1 mol H2 44.3L H2 75g HCL 1 1 mol HCL 36.5g HCL 1 mol H2 2 mol HCL Which One? 22.4L H2 1mol H2 1mol H2 1mol Mg 1mol H2 22.4L H2

Great Work!

What volume of hydrogen is produced from the reaction of 50 What volume of hydrogen is produced from the reaction of 50.0g of mg and the equivalent of 75g of HCL? Mg + 2HCL MgCl2 + H2 50g Mg 1 1 mol Mg 25.3g Mg 1 mol H2 1 mol Mg 22.4L H2 1 mol H2 44.3L H2 75g HCL 1 1 mol HCL 36.5g HCL 1 mol H2 2 mol HCL 22.4L H2 1 mol H2 ? Now What ? 1 mol Mg 22.4L H2 calculate Just Quit

I don’t think so Return

What volume of hydrogen is produced from the reaction of 50 What volume of hydrogen is produced from the reaction of 50.0g of mg and the equivalent of 75g of HCL? Mg + 2HCL MgCl2 + H2 alright! 50g Mg 1 1 mol Mg 25.3g Mg 1 mol H2 1 mol Mg 22.4L H2 1 mol H2 44.3L H2 75g HCL 1 1 mol HCL 36.5g HCL 1 mol H2 2 mol HCL 22.4L H2 1 mol H2 23L H2 Mg is the limiter HCL is the limiter H2 is the limiter

What volume of hydrogen is produced from the reaction of 50 What volume of hydrogen is produced from the reaction of 50.0g of mg and the equivalent of 75g of HCL? Mg + 2HCL MgCl2 + H2 Correct! 50g Mg 1 1 mol Mg 25.3g Mg 1 mol H2 1 mol Mg 22.4L H2 1 mol H2 44.3L H2 75g HCL 1 1 mol HCL 36.5g HCL 1 mol H2 2 mol HCL 22.4L H2 1 mol H2 23L H2 So? 23L H2 44.3L H2 I have no idea

Escape

23L H2

Run!