Chapter 10 Worksheet Examples

Slides:



Advertisements
Similar presentations
Chapter 10 Chemical Quantities
Advertisements

Section Percent Composition and Chemical Formulas
Percentage Composition
The Mole Concept Chapter 9 CHM 130 GCC.
IIIIIIIV Topic 6 The Mole I. Molar Conversions A. What is the Mole? n A counting number (like a dozen) n Avogadro’s number (N A ) n 1 mol = 6.02  10.
Chapter 3 Percent Compositions and Empirical Formulas
Atomic Structure. Subatomic Particles (Particles that make up an atom) ● Proton (p+) - Positively charged - Found in the nucleus - Large mass ●Neutron.
  I can determine the percent composition for each element in a compound or sample.
Chapter 6 Chemical Composition 6.1 Counting by Weighing Bean Lab
Chapter 7 Chemical Quantities or How do you measure how much? You can measure mass, volume, or you can count pieces of a substance. We measure mass in.
1 Chapter 12 Chemical Quantities. 2 How do you measure things? How do you measure things? n We measure mass in grams. n We measure volume in liters. n.
Chapter 10: Chemical Quantities
The Mole: A measurement of Matter
Ch. 10: The Mole *Part of Sec. 13.2: Avogadro’s Principle (pages ) Sec. 10.3: Moles of Compounds (pages 333 – 334 & )
Chapter 10 “Chemical Quantities”
Chapter 10 II. Formula Calculations
Chapter 11. Mole SI base unit for measuring the amount of substance The number of representative particles in exactly 12 grams of pure carbon-12 1 mole.
Percent Composition  The percent by mass of an element in a compound is the number of grams of the element divided by the mass in grams of the compound.
Measurement of Matter: The Mole
Unit 6 Moles Conversions Formulas. Mole SI base unit for measuring the amount of substance The number of representative particles in exactly 12 grams.
MOLAR MASS What is molar mass? How do you calculate molar mass?
Unit 12 Mass and Moles.
Empirical and Molecular formulas. Empirical – lowest whole number ratio of elements in a compound Molecular – some multiple of the empirical formula Examples:
CHEMICAL COMPOUNDS AND THE MOLE Chapter 7. Formula Mass  Mass of H 2 O? H 2(1.01) + O 16.00_ amu  Formula Mass: mass of molecule, formula unit,
IIIIIIIV The Mole I. Molar Conversions What is the Mole? A counting number (like a dozen or a pair) Avogadro’s number 6.02  mole = 6.02  10.
IIIIII Suggested Reading: Pages Chapter 7 sec 3 & 4.
Percent Composition Like all percents: Part x 100 % whole Find the mass of each component, divide by the total mass.
Chapter 11 : Matter Notes. Mole (mol) is equal to 6.02x10 23 The mole was named in honor of Amedeo Avogadro. He determined the volume of one mole of gas.
THE MOLE. Atomic and molecular mass Masses of atoms, molecules, and formula units are given in amu (atomic mass units). Example: Sodium chloride: (22.99.
The mole (abbreviation: mol) is the amount of substance equal to 6.02 x particles These particles can be atoms, ions, formula units,molecules, electrons,
MEASURING MASS  A moleis a quantity of things, just as… 1 dozen= 12 things 1 gross = 144 things 1 mole= 6.02 x things  “Things” usually measured.
Math in Chemistry.
THE MOLE Chapter 10: Chemical Quantities Measuring Matter What is a mole? It is the SI unit that measures the amount of substance.
IIIIII III. Formula Calculations (p ) Ch. 3 & 7 – The Mole.
1 Chapter 8 Chemical Composition 2 How you measure how much? How you measure how much? n You can measure mass, n or volume, n or you can count pieces.
CHEMICAL COMPOUNDS AND THE MOLE Chapter 7. Formula Mass  Mass of H 2 O?  Formula Mass: mass of molecule, formula unit, or ion is sum of masses of all.
IIIIII Formula Calculations The Mole. A. Percentage Composition n the percentage by mass of each element in a compound.
1 The Mole 6.02 X What is “The Mole??” A counting unit (similar to a dozen) 6.02 X (in scientific notation) = 602 billion trillion = 602,000,000,000,000,000,000,000.
The Mole & Chemical Quantities. The Mole Mole-the number of particles equal to the number of atoms in exactly 12.0 grams of carbon mol = 6.02 x.
CHEMICAL QUANTITIES Composition Stoichiometry Calculating Molar Mass Avogadro’s Number and the Mole Percentage Composition and Empirical Formulas Molecular.
Math in Chemistry. Percent Composition Purpose: Can be used to figure out chemical formulas.
Formula Math & The Mole. I. Percent Composition –Gives the percent, by mass, of the elements in a compound –Grams of element x 100 grams of compound grams.
9-3 Compounds and Moles *C 2 H 6 O 2 means there are 2 moles of carbon, 6 moles of hydrogen, and 2 moles of oxygen…(In one mole of the compound.)… *…or.
Chapter 10 The Mole Measuring Matter Dozen eggs Pair of gloves.
Chapter 10 – Chemical Quantities Jennie L. Borders.
Unit 9: Covalent Bonding Chapters 8 & 9 Chemistry 1K Cypress Creek High School.
The Mole.  Matter can be measured in 3 ways:  Counting particles  Mass  Volume.
Chapter 7 Chemical Quantities or How you measure how much? You can measure mass, volume, or you can count pieces of a substance. We measure mass in grams.
Unit 6: The Mole What is the MOLE? The Mole is a unit of measurement. ► Just as 1 dozen =12 ► x atoms = 1 mole ► Also called Avogadro’s Number.
1 Chapter 10 “Chemical Quantities” Yes, you will need a calculator for this chapter!
“Chemical Quantities” Yes, you will need a calculator for this chapter!
Empirical Formulae The empirical formula of a compound is the simplest ratio of the different atoms in it. For example, for ethane (C2H6)it is CH3. You.
THE MOLE. STANDARDS Use the mole concept to determine the number of particles and mass in a chemical compound. (includes gram to mole to atom conversions)
IIIIII II. % Composition and Formula Calculations Ch. 3 – The Mole.
Chemical Quantities Chapter 10. The Mole: A Measurement of Matter We can measure mass (g), volume (L), count atoms or molecules in MOLES Pair: 1 pair.
Chapter 7 Moles. What is a Representative Particle The smallest unit into which a substance can be broken down without changing the composition of the.
1 Chapter 10 “Chemical Quantities” Yes, you will need a calculator for this chapter!
III. Formula Calculations (p )
The Mole Formula Calculations.
Identify the Representative Particle
Section 9.3—Analysis of a Chemical Formula
Simplest Chemical formula for a compound
III. Formula Calculations (p )
Percent Composition Empirical Formula Molecular Formula
III. Formula Calculations
II. Percent composition
Two Relationships 1 mole = molar mass in grams of any element or compound (use periodic table) 1 mole = x 1023 particles (molecules, atoms, formula.
III. Formula Calculations (p )
Chapter 10 – Chemical Quantities
Presentation transcript:

Chapter 10 Worksheet Examples

Worksheet: Molar mass

Example: Calculate the molar mass (gram molecular weight) of a mole of iodine, I2. Unit for molar mass I = 126.9(2) = 253.8 From the formula of the compound From the mass off of the periodic table.

---------------------------------------- add together = 342.17 Example: Calculate the molar mass of a mole of aluminum sulfate (Al2(SO4)3). From the masses off of the periodic table. From the formula of the compound Al = 26.98 (2) = 53.96 S = 32.07 (3) = 96.21 O = 16.00 (12) = 192.00 ---------------------------------------- add together = 342.17 Unit for molar mass

Worksheet: Mole as a unit of mass

Example: What is the mass of 5.00 moles of water? Molar Mass Calculation H = 1.01 (2) = 2.02 O = 16.00 (1) = 16.00 ------------------------------ = 18.02 g/mol 90.1 g H2O 18.02 g/mol 5.00 mol X Molar mass From the problem

Example: What is the mass of 0.50 moles of calcium carbonate? Molar Mass Calculation Ca = 40.08 (1) = 40.08 C = 12.01 (1) = 12.01 O = 16.00 (3) = 48.00 ------------------------------ = 100.09 g/mol 50.045 g CaCO3 100.09 g/mol 0.50 mol X Molar mass From the problem

Example: How many moles of calcium chloride are in 333 grams of calcium chloride From the problem Molar Mass Calculation Ca = 40.08 (1) = 40.08 Cl = 35.45 (2) = 70.9 ------------------------------ = 110.98 g/mol 333 g CaCl2 110.98 g/mol 3.00 mol ÷ Molar mass

Worksheet: Avogadro’s Number

Example: How many molecules of water are there in 3.00 moles of water? 1.806x1024 mcl H2O 6.02x1023 mcl/mol 3.00 mol X The number of atoms/molecules in one mole is always 6.02x1023 From the problem

Example: How many moles of neon are there in 2.408x1024 atoms of neon? From the problem 2.408x1024 atm Ne 6.02x1023 atm/mol 3.99 mol ÷ The number of atoms/molecules in one mole is always 6.02x1023

Worksheet: Molar Volume of a gas

Example: What is the volume, in liters, of a 2 Example: What is the volume, in liters, of a 2.00 mole sample of methane (CH4) at STP? 44.8 L CH4 22.4 L/mol 2.00 mol X The number of liters in one mole is always 22.4 From the problem

Example: How many moles of ethane (C2H6) are there in 5 Example: How many moles of ethane (C2H6) are there in 5.60 liters of ethane? From the problem 5.6 L C2H6 22.4 L/mol 0.25 mol ÷ The number of liters in one mole is always 22.4

Worksheet: Mixed Mole Problems

Molar mass is g/mol and you find grams from the periodic table. We’ve done problems of one step. Moles to a unit or unit to moles. Now we can do multi step problems using this picture to help us see where we need to go next. This picture is a summary of all of the problems we have done up to this point along with helpful hints to units and numbers. The better you understand this the easier mole conversions will be.

Example: What would be the volume in liters of 40 Example: What would be the volume in liters of 40.36 grams of neon at STP? From the problem From the periodic table 40.36 g Ne 20.18 g/mol 2.00 mol 44.8 L Ne 22.4 L/mol 2.00 mol ÷ X The number of liters in one mole is always 22.4 We’re not to liters yet…

56 L 1.505x1024 mcl CO2 CO2 22.4 L/mol 6.02x1023 mcl/mol 2.5 mol Example: How many molecules would there be in 56 liters of carbon dioxide at STP? From the problem The number of liters in one mole is always 22.4 56 L CO2 22.4 L/mol 2.5 mol 1.505x1024 mcl CO2 6.02x1023 mcl/mol 2.5 mol ÷ X The number of atoms/molecules in one mole is always 6.02x1023 We’re not to molecules yet…

Percent Composition & Formulas Worksheet: Percent Composition & Formulas

Example: Calculate the percent composition of sodium hydrogen carbonate (NaHCO3)? Step 1 – find molar mass of the compound. Step 2 – divide mass of each element by molar mass. Step 3 – multiply answers by 100%. Molar Mass Calculation Na = 22.99 (1) = 22.99 H = 1.01 (1) = 1.01 C = 12.01 (1) = 12.01 O = 16.00(3) = 48.00 ---------------------------------------------- = 84.01 g/mol

Example: Which pair of molecules has the same empirical formula? Molecular formula Empirical formula C2H4O2 c) NaCrO4 C6H12O6 d) Na2Cr2O7 CH2O CH2O These two can not be “reduced”. An empirical formula is similar to a reduced fraction.

Example: Calculate the empirical formula for a compound with 67 Example: Calculate the empirical formula for a compound with 67.6% Hg, 10.8% S, 21.6% O? Step 1 – change percents to grams (assume we have 100 gram sample then percents are the number of grams). Step 2 – change the grams to moles. Step 3 – divide all answers by the smallest number (of the answers). Step 4 – the results become the subscripts for the formula. Step 4 HgSO4 Step 1 Step 2 Step 3 ÷ ÷

Example: Find the molecular formula of ethylene glycol, which is used as antifreeze. The molecular mass is 62g/mol and the empirical formula is CH3O? Step 1 – Find the empirical formula mass (EFM) Step 2 – Divide the molar mass (from problem) by the EFM to get the multiplier. Step 3 – Use the multiplier to determine the subscripts by multiplying each subscript by the multiplier. Step 3 C2H6O2 Step 1 EFM Calculation C = 12.01 (1) = 12.01 H = 1.01 (3) = 3.03 O = 16.00(1) = 16.00 ---------------------------------------- =31.04 g/mol Step 2 MULTIPLIER