Example Express -8sinx° + 15cosx° in the form ksin(x + )° *********

Slides:



Advertisements
Similar presentations
Trigonometric Identities
Advertisements

Trig Graphs. y = sin x y = cos x y = tan x y = sin x + 2.
Sumber : PowerPointmaths.com x y = f(x)
Evaluating Sine & Cosine and and Tangent (Section 7.4)
Review
2 step problems 5) Solve 0.5Cos(x) + 3 = 2.6 1) Solve 4Sin(x) = 2.6 2) Solve Cos(x) + 3 = ) Solve 2Tan(x) + 2 = ) Solve 2 + Sin(x) =
6.2 Trigonometric Integrals. How to integrate powers of sinx and cosx (i) If the power of cos x is odd, save one cosine factor and use cos 2 x = 1 - sin.
5.5 Solving Trigonometric Equations Example 1 A) Is a solution to ? B) Is a solution to cos x = sin 2x ?
Find the period of the function y = 4 sin x
Solving Trig Equations
Maths revision course by Miriam Hanks
Unit 1 revision Q 1 What is the perpendicular bisector of a line ?
6.5.3 – Other Properties of Inverse Functions. Just like other functions, we need to consider the domain and range of inverse trig functions To help us.
11. Basic Trigonometric Identities. An identity is an equation that is true for all defined values of a variable. We are going to use the identities to.
6.5 – Inverse Trig Functions. Review/Warm Up 1) Can you think of an angle ϴ, in radians, such that sin(ϴ) = 1? 2) Can you think of an angle ϴ, in radians,
Multiple Angle Formulas ES: Demonstrating understanding of concepts Warm-Up: Use a sum formula to rewrite sin(2x) in terms of just sin(x) & cos(x). Do.
The Wave Function Heart beat Electrical Many wave shapes, whether occurring as sound, light, water or electrical waves, can be described mathematically.
Trigonometric Equations Edited by Mr. Francis Hung Last Updated: 2013–03–12 1http:///
Solving Trigonometric Equations Involving Multiple Angles 6.3 JMerrill, 2009.
If is measured in radian Then: If is measured in radian Then: and: -
Review For The Midterm Exam.
Trigonometric Identities
Warm Up Sign Up. AccPreCalc Lesson 27 Essential Question: How are trigonometric equations solved? Standards: Prove and apply trigonometric identities.
Chapter 6 Trig 1060.
Trigonometric Equations Edited by Mr. Francis Hung Last Updated:
Using our work from the last few weeks,
Class Work Find the exact value of cot 330
Trigonometry Review Find sin(  /4) = cos(  /4) = tan(  /4) = Find sin(  /4) = cos(  /4) = tan(  /4) = csc(  /4) = sec(  /4) = cot(  /4) = csc(
Evaluating Inverse Trigonometric Functions
7.1.1 Trig Identities and Uses
6.3 Graphing Sine and Cosine Functions. Periodic Functions A periodic function is a function with a repeating pattern this includes sin and cos graphs.
Solving Trig Equations Starter CStarter C Starter C SolutionsStarter C Solutions Starter DStarter D Starter D SolutionsStarter D Solutions.
Notes Over 6.3 Evaluating Trigonometric Functions Given a Point Use the given point on the terminal side of an angle θ in standard position. Then evaluate.
Check Your Homework Answers with a Partner & Around the Room… Unit Circle Quiz Day!
Warm Up May 8 th Evaluate each of the following. 1.tan(570°)2. csc(11π/6) 3.cot(5π/2)4. sec(-210°) Solve for θ if 0°
Practice Evaluate each of the following.
Trig Identities in Equations Brought to you by Seamus and Lucas.
Trigonometry Exact Value Memory Quiz A Trigonometry Exact Value Memory Quiz A.
Higher Maths Revision Notes The Auxiliary Angle Get Started.
Pg. 407/423 Homework Pg. 407#33 Pg. 423 #16 – 18 all #19 Ѳ = kπ#21t = kπ, kπ #23 x = π/2 + 2kπ#25x = π/6 + 2kπ, 5π/6 + 2kπ #27 x = ±1.05.
DIAGNOSTIC TEST CALCULUS 2 MATH 208.
Describe the vertical shift in the graph of y = -2sin3x + 4. A.) Up 2 B.) Down 2 C.) Up 4 D.) Down 4.
7.4.1 – Intro to Trig Equations!. Recall from precalculus… – Expression = no equal sign – Equation = equal sign exists between two sides We can combine.
Trigonometry Review Find sin(  /4) = cos(  /4) = tan(  /4) = Find sin(  /4) = cos(  /4) = tan(  /4) = csc(  /4) = sec(  /4) = cot(  /4) = csc(
Simplify the given expression: sec²t csct csc²t sect.
(1) Sin, Cos or Tan? x 7 35 o S H O C H A T A O Answer: Tan You know the adjacent and want the opposite.
Clicker Question 1 What is  x sin(3x) dx ? – A. (1/3)cos(3x) + C – B. (-1/3)x cos(3x) + (1/9)sin(3x) + C – C. -x cos(3x) + sin(3x) + C – D. -3x cos(3x)
UNIT 6: GRAPHING TRIG AND LAWS Final Exam Review.
Sin x = Solve for 0° ≤ x ≤ 720°
sinx + circle 90 o 180 o  0o0o 270 o 1 The Trigonometric Ratios for any angle
Jeopardy Simplify Trig expressions Verify Trig Identities Find all Solutions Solutions with multiple angles Solutions with factoring Q $100 Q $200 Q $300.
1 Lecture 7 of 12 Inverse Trigonometric Functions.
Chapter 10 – Trigonometric (Functions) Q1
Review of radian measure.
MATH 1330 Section 6.3.
MATH 1330 Section 6.3.
Graphs of Trigonometric Functions
Trigonometric Function: The Unit circle
Review 5.1 to 5.3.
Finding a Limit as x c Plug in---Factor/Conjugate.
1 step solns A Home End 1) Solve Sin(x) = 0.24
1 step solns A Home End 1) Solve Sin x = 0.24
One way to use identities is to simplify expressions involving trigonometric functions. Often a good strategy for doing this is to write all trig functions.
Last time… Homework questions?.
© T Madas.
MATH 1330 Section 6.3.
Trig. equations with graphs
3 step problems Home End 1) Solve 2Sin(x + 25) = 1.5
Half-Angle Identities
Product-to-Sum and Sum-to-Product Formulas
Presentation transcript:

Example Express -8sinx° + 15cosx° in the form ksin(x + )° ********* a = -8 & b = 15 kcos°<0 Q2 or Q3 kcos° = -8 and ksin° = 15 ksin°>0 Q1 or Q2 (kcos°)2 + (ksin°)2 = (-8)2 + 152 k2 = 64 + 225    k2 = 289  k = 17 tan° = b/a = 15/-8  in Q2 tan-1(15/8) = 61.9° Q2:  = 180 – 61.9 = 118.1° So -8sinx° + 15cosx° = 17sin(x + 118.1)°

Example (radians) Express 3/2sin - 1/2cos in the form ksin( + ) ********* a = 3/2 & b = -1/2 kcos>0 Q1 or Q4 kcos = 3/2 and ksin = -1/2 ksin<0 Q3 or Q4 (kcos)2 + (ksin)2 = (3/2 )2 + (-1/2)2 k2 = 3/4 + 1/4  k2 = 1    k = 1  in Q4 tan = b/a = (-1/2)(3/2) = -1/2 X ( 2 /3) = -1/3 tan-1 (1/3)= 30° = /6 Q4:  = 2 - /6 = 11/6 So 3/2sin - 1/2cos = sin( + 11/6)

VARIATIONS The usual formats are acosx° + bsinx° = kcos(x - )° asinx° + bcosx° = ksin(x + )° The variations kcos(x + )° and ksin(x - )° are easily obtained by considering reverse rotations from the X-axis. NB: -200° = +160° while +120° = -240° So sin(x + 225)° = sin(x – 135)° and cos( - 7/5) = cos( + 3/5)

Example Express 12sinx° - 5cosx° in the form ksin(x - )° ********* a = 12 & b = -5 kcos° = 12 and ksin° = -5 kcos°>0 Q1 or Q4 (kcos°)2 + (ksin°)2 = 122 + (-5)2 ksin°<0 Q3 or Q4 k2 = 144 + 25 k2 = 169  k = 13    tan° = b/a = -5/12  in Q4 tan-1(5/12) = 22.6° Q4:  = 360 – 22.6 = 337.4° So 12sinx° - 5cosx° = 13sin(x + 337.4)° = 13sin(x – 22.6)°