Differentiation.

Slides:



Advertisements
Similar presentations
Remember: Derivative=Slope of the Tangent Line.
Advertisements

Question 1 How do you find the equation of a perpendicular bisector of a straight line ? 1.1.
Chapter : Differentiation. Questions 1. Find the value of Answers (1) 2. If f(x) = 2[2x + 5]⁴, find f ‘ (-2) Answers(2) 3. If y = 2s⁶ and x = 2s – 1,
Let Maths take you Further…
Quadratic Functions.
§ 8.3 Quadratic Functions and Their Graphs.
§ 8.3 Quadratic Functions and Their Graphs. Graphing Quadratic Functions Blitzer, Intermediate Algebra, 5e – Slide #2 Section 8.3 The graph of any quadratic.
“Teach A Level Maths” Vol. 1: AS Core Modules
Higher Maths Revision Notes Basic Differentiation Get Started goodbye.
4.6 Optimization The goal is to maximize or minimize a given quantity subject to a constraint. Must identify the quantity to be optimized – along with.
Chapter 21 Application of Differential Calculus
Chapter 17 Applications of differential calculus A Kinematics
Inequalities.
3-7 investigating graphs of polynomial functions
Solving Equations Containing To solve an equation with a radical expression, you need to isolate the variable on one side of the equation. Factored out.
Differentiation Calculus was developed in the 17th century by Sir Issac Newton and Gottfried Leibniz who disagreed fiercely over who originated it. Calculus.
Session 1 Paper 2 Questions and Answers Calculator Harris Academy Supported Study.
Maximum volume/space or minimum materials Design your own assignment.
Quadratic Functions. The graph of any quadratic function is called a parabola. Parabolas are shaped like cups, as shown in the graph below. If the coefficient.
Min-Max Problems Unit 3 Lesson 2b – Optimization Problems.
Introduction This chapter reminds us of how to calculate midpoints and distances between co-ordinates We will see lots of Algebraic versions as well We.
Introduction This chapter gives you several methods which can be used to solve complicated equations to given levels of accuracy These are similar to.
§ 8.3 Quadratic Functions and Their Graphs. Blitzer, Intermediate Algebra, 4e – Slide #48 Graphing Quadratic Functions Graphs of Quadratic Functions The.
Differential Equations There are many situations in science and business in which variables increase or decrease at a certain rate. A differential equation.
Sketching quadratic functions To sketch a quadratic function we need to identify where possible: The y intercept (0, c) The roots by solving ax 2 + bx.
Introduction This chapter focuses on Parametric equations Parametric equations split a ‘Cartesian’ equation into an x and y ‘component’ They are used.
Higher Mathematics Unit 1.3 Using Differentiation.
Introduction This Chapter focuses on sketching Graphs We will also be looking at using them to solve Equations There will also be some work on Graph transformations.
Introduction We have seen how to Integrate in C1 In C2 we start to use Integration, to work out areas below curves It is increasingly important in this.
Example 1 Find the derivative of Function is written in terms of f(x), answer should be written in terms of f ′ (x) Continue 
Introduction This Chapter focuses on solving Equations and Inequalities It will also make use of the work we have done so far on Quadratic Functions and.
Introduction Integration is the reverse process of Differentiation Differentiating gives us a formula for the gradient Integrating can get us the formula.
Quadratic Functions.
Differentiation.
7.5 Formulas. Formulas: a formula is an equation that relates one or more quantities to another quantity. Each of these quantities is represented by a.
Difference between Expression and Equation?. L.O. To be able to solve Quadratic Equations There are several ways to solve a quadratic equation Factorising.
Chapter 11 Maximum and minimum points and optimisation problems Learning objectives:  Understand what is meant by stationary point  Find maximum and.
Functions 2 Copyright © Cengage Learning. All rights reserved.
Using Differentiation Stationary Points © Christine Crisp.
Calculus Continued Tangents and Normals Example Find the equations of the tangent and normal to the graph of at the point where.
Stationary/Turning Points How do we find them?. What are they?  Turning points are points where a graph is changing direction  Stationary points are.
Quadratic Functions PreCalculus 3-3. The graph of any quadratic function is called a parabola. Parabolas are shaped like cups, as shown in the graph below.
Level 2 Certificate Further Mathematics 8360 Route Map
Graphing Quadratic Functions Solving by: Factoring
Coordinate Geometry in the (x,y) plane.
Sketching Curves.
Optimizing Area/SA/Volume
Co-ordinate Geometry in the (x, y) Plane.
Properties of Functions
Quadratic Functions.
Tangents and Rates of Change – Outcomes
Solving Equations Containing
Copyright © Cengage Learning. All rights reserved.
Coordinate Geometry in the (x,y) plane.
Solving Equations Containing
Differentiation.
Solving Equations Containing
Differentiation Summary
Application of Differentiation
AS-Level Maths: Core 2 for Edexcel
“Teach A Level Maths” Vol. 1: AS Core Modules
Implicit differentiation
“Teach A Level Maths” Vol. 1: AS Core Modules
Identifying Stationary Points
Tutorial 3 Applications of the Derivative
POLAR CURVES Tangents.
Substitution 3..
Solving Equations Containing
Presentation transcript:

Differentiation

Introduction We have seen Differentiation in C1 In C2 we will be looking at solving more types of problem We are also going to be applying the process to worded practical problems

Teachings for Exercise 9A

Differentiation y You need to know the difference between Increasing and Decreasing Functions An increasing function is one with a positive gradient. A decreasing function is one with a negative gradient. This function is increasing for all values of x x y This function is decreasing for all values of x x 9A

Differentiation y You need to know the difference between Increasing and Decreasing Functions An increasing function is one with a positive gradient. A decreasing function is one with a negative gradient. Some functions are increasing in one interval and decreasing in another. x This function is decreasing for x > 0, and increasing for x < 0 At x = 0, the gradient is 0. This is known as a stationary point. 9A

Differentiation You need to know the difference between Increasing and Decreasing Functions An increasing function is one with a positive gradient. A decreasing function is one with a negative gradient. Some functions are increasing in one interval and decreasing in another. You need to be able to work out ranges of values where a function is increasing or decreasing.. Example Question Show that the function ; is an increasing function. Differentiate to get the gradient function  Since x2 has to be positive, 3x2 + 24 will be as well  So the gradient will always be positive, hence an increasing function 9A

Differentiation You need to know the difference between Increasing and Decreasing Functions An increasing function is one with a positive gradient. A decreasing function is one with a negative gradient. Some functions are increasing in one interval and decreasing in another. You need to be able to work out ranges of values where a function is increasing or decreasing.. Example Question Find the range of values where: is an decreasing function. Differentiate for the gradient function We want the gradient to be below 0 Factorise Factorise again Normally x = -3 and 1 BUT, we want values that will make the function negative… 9A

Differentiation You need to know the difference between Increasing and Decreasing Functions Example Question Find the range of values where: y f(x) is an decreasing function. Differentiate for the gradient function We want the gradient to be below 0 x Factorise Factorise again Normally x = -3 and 1 BUT, we want values that will make the function negative… -3 1 Decreasing Function range 9A

Teachings for Exercise 9B

Differentiation You need to be able to calculate the co-ordinates of Stationary points, and determine their nature A point where f(x) stops increasing and starts decreasing is called a maximum point A point where f(x) stops decreasing and starts increasing is called a minimum point A point of inflexion is where the gradient is locally a maximum or minimum (the gradient does not have to change from positive to negative, for example) These are all known as turning points, and occur where f’(x) = 0 (for now at least!) y Local maximum x Point of inflexion Local minimum 9B

Differentiation You need to be able to calculate the co-ordinates of Stationary points, and determine their nature To find the coordinates of these points, you need to: 1) Differentiate f(x) to get the Gradient Function 2) Solve f’(x) by setting it equal to 0 (as this represents the gradient being 0) 3) Substitute the value(s) of x into the original equation to find the corresponding y-coordinate y Local maximum x Point of inflexion Local minimum 9B

Differentiation You need to be able to calculate the co-ordinates of Stationary points, and determine their nature To find the coordinates of these points, you need to: 1) Differentiate f(x) to get the Gradient Function 2) Solve f’(x) by setting it equal to 0 (as this represents the gradient being 0) 3) Substitute the value(s) of x into the original equation to find the corresponding y-coordinate Example Question Find the coordinates of the turning point on the curve y = x4 – 32x, and state whether it is a minimum or maximum. Differentiate Set equal to 0 Add 32 Divide by 4, then cube root Sub 2 into the original equation The stationary point is at (2, -48) Work out the y-coordinate 9B

Differentiation You need to be able to calculate the co-ordinates of Stationary points, and determine their nature To find the coordinates of these points, you need to: 1) Differentiate f(x) to get the Gradient Function 2) Solve f’(x) by setting it equal to 0 (as this represents the gradient being 0) 3) Substitute the value(s) of x into the original equation to find the corresponding y-coordinate 4) To determine whether the point is a minimum or a maximum, you need to work out f’’(x) (differentiate again!) Example Question Find the coordinates of the turning point on the curve y = x4 – 32x, and state whether it is a minimum or maximum. The stationary point is at (2, -48) Differentiate again So the stationary point is a MINIMUM in this case! Sub in the x coordinate Positive = Minimum Negative = Maximum 9B

Differentiation You need to be able to calculate the co-ordinates of Stationary points, and determine their nature To find the coordinates of these points, you need to: 1) Differentiate f(x) to get the Gradient Function 2) Solve f’(x) by setting it equal to 0 (as this represents the gradient being 0) 3) Substitute the value(s) of x into the original equation to find the corresponding y-coordinate 4) To determine whether the point is a minimum or a maximum, you need to work out f’’(x) (differentiate again!) Example Question Find the stationary points on the curve: y = 2x3 – 15x2 + 24x + 6, and state whether they are minima, maxima or points of inflexion Differentiate Set equal to 0 Factorise Factorise again Write the solutions Substituting into the original formula will give the following coordinates as stationary points: (1, 17) and (4, -10) 9B

Differentiation You need to be able to calculate the co-ordinates of Stationary points, and determine their nature To find the coordinates of these points, you need to: 1) Differentiate f(x) to get the Gradient Function 2) Solve f’(x) by setting it equal to 0 (as this represents the gradient being 0) 3) Substitute the value(s) of x into the original equation to find the corresponding y-coordinate 4) To determine whether the point is a minimum or a maximum, you need to work out f’’(x) (differentiate again!) Example Question Find the stationary points on the curve: y = 2x3 – 15x2 + 24x + 6, and state whether they are minima, maxima or points of inflexion Stationary points at: (1, 17) and (4, -10) Differentiate again Sub in x = 1 Sub in x = 4 So (1,17) is a Maximum So (4,-10) is a Minimum 9B

Differentiation You need to be able to calculate the co-ordinates of Stationary points, and determine their nature To find the coordinates of these points, you need to: 1) Differentiate f(x) to get the Gradient Function 2) Solve f’(x) by setting it equal to 0 (as this represents the gradient being 0) 3) Substitute the value(s) of x into the original equation to find the corresponding y-coordinate 4) To determine whether the point is a minimum or a maximum, you need to work out f’’(x) (differentiate again!) Example Question Find the maximum possible value for y in the formula y = 6x – x2. State the range of the function. Differentiate Set equal to 0 Solve Sub x into the original equation Solve 9 is the maximum, so the range is less than but including 9 9B

Teachings for Exercise 9C

Differentiation You need to be able to recognise practical problems that can be solved by using the idea of maxima and minima Whenever you see a question asking about the maximum value or minimum value of a quantity, you will most likely need to use differentiation at some point. Most questions will involve creating a formula, for example for Volume or Area, and then calculating the maximum value of it. A practical application would be ‘If I have a certain amount of material to make a box, how can I make the one with the largest volume? (maximum)’ 9C

Differentiation You need to be able to recognise practical problems that can be solved by using the idea of maxima and minima Example Question A large tank (shown) is to be made from 54m2 of sheet metal. It has no top. Show that the Volume of the tank will be given by: 1) Try to make formulae using the information you have Formula for the Volume x Formula for the Surface Area (no top) x y 3) Substitute the SA formula into the Volume formula, to replace y. 2) Find a way to remove a constant, in this case ‘y’. We can rewrite the Surface Area formula in terms of y. 9C

Show that the Volume of the tank will be given by: Differentiation You need to be able to recognise practical problems that can be solved by using the idea of maxima and minima Example Question A large tank (shown) is to be made from 54m2 of sheet metal. It has no top. Show that the Volume of the tank will be given by: Differentiate x x y Set equal to 0 b) Calculate the values of x that will give the largest volume possible, and what this Volume is. Rearrange Solve Sub the x value in 9C

Differentiation You need to be able to recognise practical problems that can be solved by using the idea of maxima and minima Example Question A wire of length 2m is bent into the shape shown, made up of a Rectangle and a Semi-circle. 1) Find the length of the semi-circle, as this makes up part of the length. y a) Find an expression for y in terms of x. πx 2 x Rearrange to get y alone y Divide by 2 9C

Differentiation You need to be able to recognise practical problems that can be solved by using the idea of maxima and minima Example Question A wire of length 2m is bent into the shape shown, made up of a Rectangle and a Semi-circle. 1) Work out the areas of the Rectangle and Semi-circle separately. y a) Find an expression for y in terms of x. Rectangle Semi Circle x b) Show that the Area is: y 9C

Differentiation You need to be able to recognise practical problems that can be solved by using the idea of maxima and minima Example Question A wire of length 2m is bent into the shape shown, made up of a Rectangle and a Semi-circle. 1) Work out the areas of the Rectangle and Semi-circle separately. y a) Find an expression for y in terms of x. Rectangle Semi Circle x b) Show that the Area is: y Replace y Factorise Expand 9C

Differentiation You need to be able to recognise practical problems that can be solved by using the idea of maxima and minima Example Question A wire of length 2m is bent into the shape shown, made up of a Rectangle and a Semi-circle. 1) Use the formula we have for the Area y a) Find an expression for y in terms of x. x b) Show that the Area is: Expand y c) Find the maximum possible Area Differentiate Set equal to 0 Factorise Multiply by 8 Divide by (4 + π) Divide by 2 9C

Summary We have expanded our knowledge of Differentiation to include stationary points We have looked at using maxima and minima to solve more practical problems