Consider the reversible reaction: 2 NaHSO 3 (s)  Na 2 SO 3 (s) + H 2 O(g) + SO 2 (g) ΔH > 0  What will be the mass action expression for this reaction?

Slides:



Advertisements
Similar presentations
Chemical Equilibrium Equilibrium.
Advertisements

Le Châteliers principle. The significance of Kc values Read 14.6 ( ) do PE5 If Kc is small (0.001 or lower), [products] must be small, thus forward.
Le Chatelier’s Principle Chem 12 Chapter 13, Pg
Le Chatelier’s Principle Chem 12 - Unit 3. Le Chatelier’s Principle The French chemist Henri Le Chatelier ( ) studied how the equilibrium position.
Chapter 18: Chemical Equilibrium
Concentration and Temperature.  If a stress is applied to a system at equilibrium, the system shifts in the direction that relieves the stress.  Stresses.
Le Chatelier’s Principle
Equilibrium Unit 10 1.
Chemical Equilibrium AP Chem Unit 13.
Disturbing Equilibrium and Non-equilibrium conditions
Chemical equilibrium is a state in which the forward and reverse reactions balance each other because they take place at equal rates. Rateforward reaction.
CHAPTER 14 CHEMICAL EQUILIBRIUM
Section 8.4—Le Chatelier’s Principle How can we push a reaction to make more products?
Chemical Equilibrium Chapter 6 pages Reversible Reactions- most chemical reactions are reversible under the correct conditions.
Chemical Equilibrium - General Concepts (Ch. 14)
Chemical Equilibrium Chapter 13. Chemical Equilibrium The state where the concentrations of all reactants and products remain constant with time. On the.
1 CHEMICAL EQUILIBRIUM. Chemical Equilibrium Chemical Reactions Types; What is equilibrium? Expressions for equilibrium constants, K c ; Calculating K.
Equilibrium A state in which opposing processes of a system are occurring at the same rate. 1.Physical (a) Saturated Solution – dissolution and crystallization.
(7.3) Le Chatelier’s Principle - Regaining Equilibrium.
Dynamic Equilibrium Notes p NO 2 (g)  N 2 O 4 (g) Initial concentration N 2 O 4 : 0.40 M Final concentration N 2 O 4 : M Initial concentration.
EQUILIBRIUM TIER 4 Apply LeChatelier’s principle to predict the qualitative effects of changes of temperature, pressure and concentration on the position.
Le Chatelier’s Principle. When a system at equilibrium is placed under stress, the system will undergo a change in such a way as to relieve that stress.
How do you handle the calculations and data for the gas law lab (molar mass of butane)? February 27.
Chemical Equilibrium The reversibility of reactions.
Lecture 41/24/07 Quiz Friday. Manipulating K Multiply the equation by a constant Reverse equation Add equations.
Lecture 41/28/05. Quiz 2 1. Given the following reaction: 2 H 2 S (g) ↔ 2 H 2 (g) + S 2 (g) Calculate K c and K p at 1400 K if at equilibrium a flask.
Aim : How can equilibrium be shifted? Do Now: 1.Take out a calculator and reference tables. 2.What can change the equilibrium of a phase change?
Daniel L. Reger Scott R. Goode David W. Ball Chapter 14 Chemical Equilibrium.
If a stress is applied to a system at equilibrium, the position of the equilibrium will shift to reduce the stress This shift occurs because the stress.
1 Partial Pressure Pressure of individual gases in a mixture.
Molar Volume. Avagadro’s Principle Equal volumes of gases contain equal numbers of molecules Volume of a gas varies directly with the number of molecules.
Chemical Equilibrium 4/24/2017.
Chapter 13 Chemical Equilibrium. REVERSE REACTION  reciprocal K.
Section 17.3 Application of Equilibria 1.To learn to predict the changes that occur when a system at equilibrium is disturbed 2.To learn to calculate equilibrium.
Le Chatelier’s Principle
Chapter 18 – Rates of Reactions and Equilibrium Every biological and non-biological chemical reaction in nature eventually reaches a state called equilibrium.
Kp When the reactants and products are gases, we can determine the equilibrium constant in terms of partial pressures. Dalton’s Law of Partial Pressures.
DALTON’S LAW OF PARTIAL PRESSURE
Chemical Equilibrium Chapter 13. Chemical Equilibrium The state where the concentrations of all reactants and products remain constant with time. On the.
Chapter 13 Chemical Equilibrium The state where the concentrations of all reactants and products remain constant with time. On the molecular level, there.
Gases Online Lecture Part 2. Gas Density and Molar Mass Using the ideal gas law and the density of a gas you can solve for the molar mass of the gas.
Le Chatelier’s Principle  A reaction at equilibrium, when “stressed,” will react to relieve the stress.  (If you mess with it, it will work to return.
The Reading is for the next class. Problems are for that day’s class. Problems for each week (MWF) are due the following Monday.
Equilibrium. This is usually Question #1 on FR write equilibrium expressions convert between K P and K c eq. constants calculate eq. constants calculate.
Chapter 15 Chemical Equilibrium
Review 2 Chapter 16 Chemical Equilibrium. Equilibrium Condition: Study equilibrium tells us more about whether a reaction will occur or not. Closed system.
Chemical Equilibrium Chapter Write the expressions for the equilibrium constants K P of these thermal decompositions:
Chapter 16 Chemical Equilibrium. Different States a System Can Be In A state of change A state of change No change (there are several no change states.
17-1 Copyright ©The McGraw-Hill Companies, Inc. Permission required for reproduction or display. Equilibrium: The Extent of Chemical Reactions.
Rates of Reactions and Equilibrium Rates of Chemical Reactions The rate, or speed, of a chemical reaction is measured in units of a mass / time. Reaction.
AP Chemistry Chapter 15 Jeopardy Jennie L. Borders.
Chapter 13 Chemical Equilibrium Reversible Reactions REACTANTS react to form products. PRODUCTS then react to form reactants. BOTH reactions occur: forward.
Factors which Affect Chemical Equilibrium Le Chateliers Principle –Projects Direction of Change N 2 (g) + 3H 2 (g) ↔ 2NH 3 (g)
Chemical Equilibrium Reactants Products Reactants Products As the time increases… [Reactants] decrease, so the rate of forward reaction decreases; [Products]
Chapter 15 Chemical Equilibrium. Equilibrium - Condition where opposing processes occur at the same time. - Processes may be physical changes or chemical.
CHEMICAL EQUILIBRIUM Dynamic Equilibrium Equilibrium constant expression – K c – K p – Q c Le Chatelier’s principle.
Ch. 15 Chemical Equilibrium
Le Chatelier’s Principle
LeChatelier’s Principle
Unit 5: Solutions Honors Unit.
Le Chatelier’s Principle
Equilibrium.
2 NH3 (g) + H2SO4 à (NH4)2SO4 (aq)
Le Chatelier's Principle and Equilibrium
The summation of all things!
Lesson 3.
Le Chatelier’s Principle Notes
Chapter 14 Chemical Equilibrium
Effects of Volume and Pressure Changes
Presentation transcript:

Consider the reversible reaction: 2 NaHSO 3 (s)  Na 2 SO 3 (s) + H 2 O(g) + SO 2 (g) ΔH > 0  What will be the mass action expression for this reaction?

Consider the reversible reaction: 2 NaHSO 3 (s)  Na 2 SO 3 (s) + H 2 O(g) + SO 2 (g) ΔH > 0  What will be the mass action expression for this reaction?  How will the position of equilibrium be affected by the following changes?  Adding sulfur dioxide gas to the reaction vessel? Provide a “rate changes” explanation.

Consider the reversible reaction: 2 NaHSO 3 (s)  Na 2 SO 3 (s) + H 2 O(g) + SO 2 (g) ΔH > 0  What will be the mass action expression for this reaction?  How will the position of equilibrium be affected by the following changes?  Adding sulfur dioxide gas to the reaction vessel? Provide a “rate changes” explanation.  Removing some solid sodium sulfite from the reaction vessel? Provide a “le Chatelier” explanation.

Consider the reversible reaction: 2 NaHSO 3 (s)  Na 2 SO 3 (s) + H 2 O(g) + SO 2 (g) ΔH > 0  What will be the mass action expression for this reaction?  How will the position of equilibrium be affected by the following changes?  Adding sulfur dioxide gas to the reaction vessel? Provide a “rate changes” explanation.  Removing some solid sodium sulfite from the reaction vessel? Provide a “le Chatelier” explanation.  Removing water vapor by adding an inert hygroscopic solid? Provide a “mathematical” explanation.

Consider the reversible reaction: 2 NaHSO 3 (s)  Na 2 SO 3 (s) + H 2 O(g) + SO 2 (g) ΔH > 0  What will be the mass action expression for this reaction?  How will the position of equilibrium be affected by the following changes?  Adding sulfur dioxide gas to the reaction vessel? Provide a “rate changes” explanation.  Removing some solid sodium sulfite from the reaction vessel? Provide a “le Chatelier” explanation.  Removing water vapor by adding an inert hygroscopic solid? Provide a “mathematical” explanation.  Increasing the volume. Provide a “le Chatelier” explanation… then confirm with a “mathematical” explanation.

Consider the reversible reaction: 2 NaHSO 3 (s)  Na 2 SO 3 (s) + H 2 O(g) + SO 2 (g) ΔH > 0  What will be the mass action expression for this reaction?  How will the position of equilibrium be affected by the following changes?  Adding sulfur dioxide gas to the reaction vessel? Provide a “rate changes” explanation.  Removing some solid sodium sulfite from the reaction vessel? Provide a “le Chatelier” explanation.  Removing water vapor by adding an inert hygroscopic solid? Provide a “mathematical” explanation.  Increasing the volume. Provide a “le Chatelier” explanation… then confirm with a “mathematical” explanation.  Heating the reaction vessel? (any explanation)

A student was studying the following reaction: SO 2 Cl 2 (g)  SO 2 (g) + Cl 2 (g). The value of K p for the sys­tem is 12.5 when the temperature is 565 K. A reactor vessel was filled with enough SO 2 Cl 2 (g) to give it a pressure of atm at 565 K. The system was left undisturbed so it could come to equilibrium. Calculate the total pressure, in atmospheres, at equilibrium.

Maybe change this one… the cube root is yucky… but works. At 200.0˚C, K c = 1.4 x for the following reaction: N 2 O(g) + NO 2 (g)  3 NO(g) A sample of 300 mL of NO(g) measured at 800 torr and 25˚C is placed in a 4.00 L container. The temperature is raised to 200.0˚C and the system is allowed to reach equilibrium. What will be the molar concentration of NO at equilibrium? What will be its partial pressure?