Chapter 2 Trigonometry 2.4 The Cosine Law

Slides:



Advertisements
Similar presentations
The Law of Cosines February 25, 2010.
Advertisements

Aim: What is the Law of Sine? Do Now: In ∆ABC, AC = b, BC = a, and the height is (h). Find: 1. sin A 2. sin B A D B C HW: p.567 # 6,8,12,19,20,21,22,23.
5/5/ : Sine and Cosine Ratios 10.2: Sine and Cosine Expectation: G1.3.1: Define the sine, cosine, and tangent of acute angles in a right triangle.
The Law of Sines and The Law of Cosines
Chapter 6 Trigonometry- Part 3. Aim #6.1:How do we apply the Law of Sines? An oblique triangle is one that does not contain a right angle.
Section SOLVING OBLIQUE TRIANGLES
Trigonometry 2 Aims Solve oblique triangles using sin & cos laws Objectives Calculate angles and lengths of oblique triangles. Calculate angles and lengths.
Essential Question: What is the law of cosines, and when do we use it?
Aim: How do we solve problems with both law of sine and law of cosine?
Geometry Notes Lesson 5.3B Trigonometry
2-24 Honors Geometry Warm-up
13.4 L AW OF S INES 13.5 L AW OF COSINES Algebra II w/ trig.
8-5 Laws of sines and cosines
Notes Over 8.1 Solving Oblique Triangles To solve an oblique triangle, you need to be given one side, and at least two other parts (sides or angles).
Chapter 6.  Use the law of sines to solve triangles.
Material Taken From: Mathematics for the international student Mathematical Studies SL Mal Coad, Glen Whiffen, John Owen, Robert Haese, Sandra Haese and.
In Chapter 7, we learned how to solve problems with right-angled triangles using SOH-CAH-TOA OPPOSITE ADJACENT HYPOTENUSE Now, in Chapter 8, we will learn.
TRIGONOMETRY Lesson 2: Solving Right Triangles. Todays Objectives Students will be able to develop and apply the primary trigonometric ratios (sine, cosine,
1 What you will learn  How to solve triangles by using the Law of Cosines  How to find the area of triangles if the measures of the three sides are given.
8-4 Trigonometry, day 2 You used the Pythagorean Theorem to find missing lengths in right triangles. Find trigonometric ratios using right triangles. Use.
The Law of Sines Day 1: Areas and AAS
Math 20-1 Chapter 2 Trigonometry 2.4 The Cosine Law Teacher Notes.
Special Right Triangles Definition and use. The Triangle Definition  There are many right angle triangles. Today we are most interested in right.
Law of Sines & Law of Cosine. Law of Sines The ratio of the Sine of one angle and the length of the side opposite is equivalent to the ratio of the Sine.
TRIGONOMETRY Lesson 2: Solving Right Triangles. Todays Objectives Students will be able to develop and apply the primary trigonometric ratios (sine, cosine,
9-2 Sine and Cosine Ratios. There are two more ratios in trigonometry that are very useful when determining the length of a side or the measure of an.
Sullivan Algebra and Trigonometry: Section 9.2 Objectives of this Section Solve SAA or ASA Triangles Solve SSA Triangles Solve Applied Problems.
8-5 The Law of Sines Objective: To apply the Law of Sines Essential Understanding : If you know the measures of two angles and the length of a side(AAS.
Welcome to Week 5 College Trigonometry. Secant Secant with a graphing calculator.
Topic 8 Goals and common core standards Ms. Helgeson
Grade 10 Academic (MPM2D) Unit 6: Trigonometry 2: Non-Right Triangles SSA - Triangles Investigations Mr. Choi © 2017 E. Choi – MPM2D - All Rights.
Objective Use the Law of Sines and the Law of Cosines to solve triangles.
Advanced Geometry Trigonometry Lesson 5 The Law of Cosines.
Grrrreat! To do so, you will need to calculate trig
Section T.5 – Solving Triangles
Oblique Triangles.
If none of the angles of a triangle is a right angle, the triangle is called oblique. All angles are acute Two acute angles, one obtuse angle.
The Cosine Rule.
Copyright © 2014, 2010, 2007 Pearson Education, Inc.
Trigonometry Ratios in Right Triangles
Warm-Up Exercises ABC Find the unknown parts of A = 75°, B 82°, c 16
Copyright © 2014, 2010, 2007 Pearson Education, Inc.
6-3: Law of Cosines
You will need a calculator and high lighter!
Day 7: Solving Triangles
Trigonometry Welcome to Camp SOH-CAH-TOA
Law of Cosine Chapter 8.3.
Copyright © 2014, 2010, 2007 Pearson Education, Inc.
19. Law of Sines.
8.2-Law of the Cosines Law of the Cosines & Requirements
8-5 The Law of Sines Geometry.
Let’s Get It Started ° 60° A B C
Chapter 9 Right Triangle Trigonometry
Trigonometry Ratios in Right Triangles
7.7 Law of Cosines.
15. Law of Cosines.
Law of Sines and Cosines
Law of Cosines.
Warm – up Find the sine, cosine and tangent of angle c.
Copyright © 2014, 2010, 2007 Pearson Education, Inc.
Law of Cosines.
Section 6.2 The Law of Cosines
Geometry Section 7.7.
DAY 74 AGENDA: DG minutes Turn in Rec Letter --- due Mon.
7.2 The Law of Sines.
Reviewing Trig Ratios 7.4 Chapter 7 Measurement 7.4.1
Law of Sines (Lesson 5-5) The Law of Sines is an extended proportion. Each ratio in the proportion is the ratio of an angle of a triangle to the length.
The Law of Sines.
Chapter 2 Trigonometry 2.3 The Sine Law Pre-Calculus 11.
2.2 Trig Ratios of Any Angle (x, y, r)
Presentation transcript:

Chapter 2 Trigonometry 2.4 The Cosine Law Explain why the sine law cannot be used to solve each triangle. A B 28° 37° 115° C J K L 70 40 45 There is no known side opposite a known angle. There is no known angle opposite a known side. P Q R 15 E D 85° 20 25 F There is no known angle and only one known side. There is no known angle opposite a known side Pre-Calculus 11

a2 = b2 + c2 -2bc cosA b2 = a2 + c2 -2ac cosB c2 = a2 + b2 -2ab cosC Law of Cosines a2 = b2 + c2 -2bc cosA b2 = a2 + c2 -2ac cosB c2 = a2 + b2 -2ab cosC When should we use the Law of Cosine to solve a triangle? SSS Given the measure of three sides. SAS Given the measure of two sides and one angle not opposite a side. Pre-Calculus 11

Proof for the Law of Cosines B C A a c pythagorean h x D b - x sohcahtoa b Pre-Calculus 11

b2 = a2 + c2 -2ac cosB a2 = b2 + c2 -2bc cosA a = 37.9 cm SAS Applying the Law of Cosines (to the nearest 10th) Determine the length of side b b2 = a2 + c2 -2ac cosB = (230)2 + (150)2 - 2(230)(150)cos430 b = 157.9 m Determine the length of side a a2 = b2 + c2 -2bc cosA = (61)2 + (43)2 - 2(61)(43)cos380 a = 37.9 cm Pre-Calculus 11

SSS Finding an Angle Using the Law of Cosines (to the nearest degree) Determine the measure of angle A. a2 = b2 + c2 -2bc cosA 382 = 612 + 432 -2(61)(43) cosA 382 - 612 - 432 = -2(61)(43) cosA Pre-Calculus 11

SSS Finding an Angle Using the Law of Cosines (to the nearest degree) Given triangle DEF, find Pre-Calculus 11

h Solving Two Triangles b2 = (95)2 + (200)2 - 2(95)(200)cos50 From the following information determine the height of the balloon from the ground (to the nearest tenth) b2 = (95)2 + (200)2 - 2(95)(200)cos50 b2 ~ 24599.07083 b = 156.841 (we need length side b before we can calculate h) ← Sine Law h h = 263. 7 The balloon is 263.7 m from the ground b Pre-Calculus 11

Begin by using the method Solving Triangles When solving triangles, it is important to choose the most appropriate method. The choice depends on the given information. Place the letter of the appropriate method beside the given information. Given Information Begin by using the method Three sides Three angles Two angles and any side Right triangle Two sides and the angle between them Two sides and the angle opposite one of the sides A. Primary trig ratio SSS C AAA D B. sine law AAS B C. cosine law A D. none of the above SAS C SSA B Pre-Calculus 11

Assignment Suggested Questions Page 119: (1-6)ac, 8, 10, 12, 14, 17, 19, 20, 23 Pre-Calculus 11