Solving linear equations: Variable on both sides and brackets

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Presentation transcript:

Solving linear equations: Variable on both sides and brackets Silent Teacher Intelligent Practice Narration Your Turn 2(𝑥+3)=𝑥+5 3(𝑥+3)=2(𝑥+5) Practice

Worked Example Your Turn 2(𝑥+1)=𝑥+5 3(𝑥+1)=𝑥+5 @mathsmiles_k

𝑥+5=3 𝑥+1 3 𝑥−5 =3(2𝑥+1) 3 𝑥+5 =𝑥+1 3 𝑥−5 =−3(2𝑥+1) 3 𝑥+5 =3(2𝑥+1) 1. 7. 3 𝑥−5 =3(2𝑥+1) 3 𝑥+5 =𝑥+1 2. 8. 3 𝑥−5 =−3(2𝑥+1) 3. 3 𝑥+5 =3(2𝑥+1) 9. −3 𝑥+5 =−3(2𝑥+1) 4. 3 𝑥+5 =3(2𝑥−1) 10. −3 𝑥−5 =−3(2𝑥+1) 5. 3 𝑥−5 =3(2𝑥−1) 11. −3 𝑥−5 =−3(2𝑥−1) 6. 3 2𝑥−5 =3(𝑥−1) 12. −3 2𝑥−1 =−3(𝑥−5) @mathsmiles_k

𝑥+5=3 𝑥+1 3 𝑥−5 =−3(2𝑥+1) 𝑥=1 𝑥=−6 3 𝑥+5 =𝑥+1 −3 𝑥+5 =−3(2𝑥+1) 𝑥=-7 𝑥= 12 9 3 𝑥+5 =3(2𝑥+1) 𝑥=4 −3 𝑥−5 =−3(2𝑥+1) 𝑥=4 3 𝑥+5 =3(2𝑥−1) 𝑥=6 −3 𝑥−5 =−3(2𝑥−1) 3 𝑥−5 =3(2𝑥−1) 𝑥=−4 𝑥=−4 −3 2𝑥−1 =−3(𝑥−5) 𝑥=−4 3 2𝑥−5 =3(𝑥−1) 𝑥=4 @mathsmiles_k