Warm-up Divide the following using Long Division: (6x3 - 16x2 + 17x - 6) (3x –2 ) Divide the following with Synthetic Division (5x3 – 6x2 + 8) (x – 4) Given the following polynomial and one of its factors, Find the remaining factors (3x3 + 2x2 –19x + 6) : (x + 3) is a factor
Warm-up Divide the following using Long Division: (6x3 - 16x2 + 17x - 6) (3x –2 ) 2x2 – 4x + 3
Warm-up Divide the following with Synthetic Division (5x3 – 6x2 + 8) (x – 4)
Warm-up Given the following polynomial and one of its factors, Find the remaining factors (3x3 + 2x2 –19x + 6) : (x + 3) is a factor (x – 2)(3x – 1)
Complex Numbers Section 2-4 Digital Lesson Complex Numbers Section 2-4
Objectives I can use “i” to write complex numbers I can add, subtract, and multiply complex numbers I can simplify Negative Square Roots
Applications Impedance readings for electronics and electrical circuits are all measured in complex units
Complex Numbers Real Numbers Imaginary Numbers Rational Irrational
Complex Numbers The set of all numbers that can be written in the format: a + bi ; “a” is the real number part “bi’ is the imaginary part
The Imaginary Unit
Negative Radicals
Negative Radicals
Add or Subtract Complex Numbers To add or subtract complex numbers: 1. Write each complex number in the form a + bi. 2. Add or subtract the real parts of the complex numbers. 3. Add or subtract the imaginary parts of the complex numbers. (a + bi ) + (c + di ) = (a + c) + (b + d )i (a + bi ) – (c + di ) = (a – c) + (b – d )i Add or Subtract Complex Numbers
Adding Complex Numbers Example: Add (11 + 5i) + (8 – 2i ) = (11 + 8) + (5i – 2i ) Group real and imaginary terms. = 19 + 3i a + bi form Adding Complex Numbers
Subtracting Complex Numbers Examples: Subtract: (– 21 + 3i ) – (7 – 9i) = (– 21 – 7) + [(3 – (– 9)]i Group real and imaginary terms. = (– 21 – 7) + (3i + 9i) = –28 + 12i a + bi form Subtracting Complex Numbers
Product of Complex Numbers The product of two complex numbers is defined as: (a + bi)(c + di ) = (ac – bd ) + (ad + bc)i 1. Use the FOIL method to find the product. 2. Replace i2 by – 1. 3. Write the answer in the form a + bi. Product of Complex Numbers
1. 7i (11– 5i) = 77i – 35i2 = 77i – 35 (– 1) = 35 + 77i 2. (2 + 3i)(6 – 7i ) = 12 – 14i + 18i – 21i2 = 12 + 4i – 21i2 = 12 + 4i – 21(–1) = 12 + 4i + 21 = 33 + 4i Examples
Homework WS 3-7