INVESTIGATION INTO THE DESIGN OF A 6600V LONGWALL MINING SYSTEM Presented by Adrian Trevor.

Slides:



Advertisements
Similar presentations
TWO STEP EQUATIONS 1. SOLVE FOR X 2. DO THE ADDITION STEP FIRST
Advertisements

You have been given a mission and a code. Use the code to complete the mission and you will save the world from obliteration…
LED Drivers Al Marble Manager, Sales & Market Development January 2010.
Advanced Piloting Cruise Plot.
Chapter 17 Direct currents
1 Copyright © 2010, Elsevier Inc. All rights Reserved Fig 2.1 Chapter 2.
1 Chapter 40 - Physiology and Pathophysiology of Diuretic Action Copyright © 2013 Elsevier Inc. All rights reserved.
By D. Fisher Geometric Transformations. Reflection, Rotation, or Translation 1.
Business Transaction Management Software for Application Coordination 1 Business Processes and Coordination.
Jeopardy Q 1 Q 6 Q 11 Q 16 Q 21 Q 2 Q 7 Q 12 Q 17 Q 22 Q 3 Q 8 Q 13
Jeopardy Q 1 Q 6 Q 11 Q 16 Q 21 Q 2 Q 7 Q 12 Q 17 Q 22 Q 3 Q 8 Q 13
Title Subtitle.
You will need some paper!
0 - 0.
ALGEBRAIC EXPRESSIONS
DIVIDING INTEGERS 1. IF THE SIGNS ARE THE SAME THE ANSWER IS POSITIVE 2. IF THE SIGNS ARE DIFFERENT THE ANSWER IS NEGATIVE.
MULTIPLYING MONOMIALS TIMES POLYNOMIALS (DISTRIBUTIVE PROPERTY)
ADDING INTEGERS 1. POS. + POS. = POS. 2. NEG. + NEG. = NEG. 3. POS. + NEG. OR NEG. + POS. SUBTRACT TAKE SIGN OF BIGGER ABSOLUTE VALUE.
SUBTRACTING INTEGERS 1. CHANGE THE SUBTRACTION SIGN TO ADDITION
MULT. INTEGERS 1. IF THE SIGNS ARE THE SAME THE ANSWER IS POSITIVE 2. IF THE SIGNS ARE DIFFERENT THE ANSWER IS NEGATIVE.
GEPA Lessons 1-5 Review. Directions: You may work with a partner to complete the following questions in order as they appear in the slideshow. Use a separate.
Addition Facts
Electricity and Magnetism
Year 6 mental test 5 second questions
Year 6 mental test 10 second questions Numbers and number system Numbers and the number system, fractions, decimals, proportion & probability.
CM-22 Magnet Issues, 6 June MICE Magnet Cool Down and Other Issues Michael A. Green Lawrence Berkeley Laboratory Berkeley CA
The Renewable Future for the UK
ZMQS ZMQS
Demand Resource Operable Capacity Analysis – Assumptions for FCA 5.
Micro Focus Research 1 As far as youre aware, how does your organization plan to drive business growth over the next three years? (Respondents' first choices)
1 New build-up technique with copper bump AGP Process.
Problem1; Admission Flow
Appliance Exam. 1. Energy Star appliances exceed minimum US Government energy standards by ______% or more? a. 15% b. 10% c. 30% d. 50%
ABC Technology Project
Standard Market Design (SMD) in New England Federal Energy Regulation Commission Conference on Standard Market Design January 22, 2002 David LaPlante Vice.
Chapter 3: Electromagnetism
Cost-Volume-Profit Relationships
Chapter 11 AC Power Analysis
Since Therefore Since.
AC POWER CALCULATION Instantaneous, average and reactive power
Filling and Wrapping Review Sheet
7. PV System Sizing Herb Wade Consultant
© S Haughton more than 3?
1 Review of AC Circuits Smith College, EGR 325 March 27, 2006.
Squares and Square Root WALK. Solve each problem REVIEW:
Created by Susan Neal $100 Fractions Addition Fractions Subtraction Fractions Multiplication Fractions Division General $200 $300 $400 $500 $100 $200.
Lets play bingo!!. Calculate: MEAN Calculate: MEDIAN
A/C Final Project: Design Builder
Past Tense Probe. Past Tense Probe Past Tense Probe – Practice 1.
The Distributive Property. The distributive property is mental math strategy that can be used when multiplying. 43 x 5 =?
Chapter 5 Test Review Sections 5-1 through 5-4.
SIMOCODE-DP Software.
GG Consulting, LLC I-SUITE. Source: TEA SHARS Frequently asked questions 2.
Hosted by Mrs. Dickard RatiosProportionsUnit Rates Indirect Measurement
Addition 1’s to 20.
25 seconds left…...
Equal or Not. Equal or Not
Slippery Slope
Test B, 100 Subtraction Facts
EnvironmentEnvironnementCanada Nusa Dua, Bali, Indonesia September 5 – 7, Part 4: LFG Utilization.
Week 1.
We will resume in: 25 Minutes.
1 Unit 1 Kinematics Chapter 1 Day
TASK: Skill Development A proportional relationship is a set of equivalent ratios. Equivalent ratios have equal values using different numbers. Creating.
Chapter 11 Using Energy.
How Cells Obtain Energy from Food
ECE 424 – Introduction to VLSI
Complete Quiz You have 10 minutes to complete the quiz The Quiz is Open-Book (use it) Get help from your neighbor.
Chapter 4 Ohm’s Law, Power, and Energy. 2 Ohm’s Law The current in a resistive circuit is directly proportional to its applied voltage and inversely proportional.
11/27/2007ILC Power and Cooling VM Workshop Mike Neubauer 1 RF Power and Cooling Requirements Overview from “Main Linac Power and Cooling Information”
Presentation transcript:

INVESTIGATION INTO THE DESIGN OF A 6600V LONGWALL MINING SYSTEM Presented by Adrian Trevor

2 Overview What is a Longwall? Why bother moving to 6600V? Predicted Future Power Requirements Cable size selection Power flow modeling of proposed system Future work

3 Used because of efficiency ( Cutting and recovery rates) Continuous process once started Overview

4 All Drives at 3300V Shearer > 2MW AFC (Armoured Face Conveyor) 2.55MW BSL (Beam Stage Loader) 300kW Crusher 300kW Hydraulic Pumps 600kW Shearer Water Pump 200kW Electrical Overview

5 Ultimate reason is to improve torque for motors Also allows increase in installed power without extremely large cable sizes Allows longer monorail hence less flits Why 6600V?

6 Motor Torque The torque of a motor is proportional to the voltage squared. At 3300V, currents are drawn which causes voltage drops in all supply cables At 6600V, currents, and any voltage drop is a % of rated voltage Ideally in new system we want torque to remain above 90% at all times.

7 An increase in voltage allows power increases to be obtained without increases in conductor sizes –E.g Type cable with 50sq mm conductor can carry 170A which at 3300V is approx 970kW compared to 1940kW at 6600V –However physical dimensions and mass of cable marginally due to extra insulation required In most cases cable sizes will be reduced Increased Power

8 Voltage allows potential length of monorail to be increased by voltage drop If monorail length is doubled this has the potential of reducing monorail flits from approx 8 per block to 4 –Each flit takes approx 8 hrs –8hrs production = tonnes x 4 flits = tonnes –56000 tonnes x $40 = $2.24 million!! per block Longer Monorail

9 Predicted future power requirements Cable sizing calculations Power flow study Work Completed

10 Future power requirements can not simply be increased linearly. i.e. increase all items by 10% Each piece of machinery requires its operation to be analysed to determine what, if any power increases are required. Shearer –Increase in cutter motors to 1000kW each –Increase in traction motors to 165kW each –Total installed shearer power of 2.4MW Future Power

11 AFC –Considering increase in face width to 400m from 265m –Increase in power to 4 x 1000kW motors BSL –Increase in power to 2 x 300kW motors Crusher –Increase in power to 1 x 300kW motor Hyd Pumps and Shearer Water Pump –Increase hydraulic pumps to a total of 1000kW (Fat Face) –Determined that current SWP is suitable Future Power

12 This will result in a total installed power of 8.6MW, which is an of approx 50% on present Future Power LONGWALL POWER RATINGS EquipmentPresent Rating (kW)Future Rating (kW) Shearer2050kW2385kW AFC2250kW4000kW BSL300kW600kW Crusher300kW400kW Hydraulic Pumps600kW1000kW Shearer Water Pump200kW Total5700kW8585kW

13 Cable selection is dependant on 2 main conditions –Current carrying capacity –Voltage drop Current carrying capacity relates to the thermal limit of the cable –Heating effect of current in a cable (I 2 R losses) –Ability of insulation to dissipate this heat Voltage drop is dependant on cable size, length and current –Must remain below 5% to keep torque above 90% Cable Selection

14 The heating effect on a cable occurs over a continuous time, and instantaneous values are not of a large concern. FLC of motors NOT used to determine this. Future average currents are used by projecting present averages to future Voltage and Power levels. Present averages determined via Scada over a fixed period of time. Current Carrying Capacity

15 Cable Selection Example of Scada Data for TG AFC Motor with calculated average.

16 Most important at motor startup Full Operational Load (FOL) currents were determined by using the future FLC of the motor and allocating each motor a load factor. PF=0.85% and n=0.9% Voltage drop calcs performed using FOL in that cable plus the starting current (6xFLC) of the largest motor. Voltage Drop

17 Main Limiting factor was the voltage drop, most cables are significantly overrated in current carrying capacity to achieve acceptable voltage drop levels. Cable Selection

18 A load flow simulation was completed at future levels using EasyPower simulation software. Results confirmed calculated values 3 scenarios were simulated –Full operational load –Full operational load with TG AFC Motor starting –Full operational load with 1 Shearer Cutter Motor starting Load Flow Simulation

19 Load Flow Simulation

20 Investigate issues that DMR has –Presently CMRA prohibits voltages >4kV Investigate availability of equipment e.g motors, plugs, cables switching gear etc –Also sizing due to creepage and clearance values Investigate issues with fault current energy, in relation to flame proof enclosures. Investigate effects of EMI on control systems –Clearances inside enclosures –Effect on pilot core communication systems Future Work

21 Questions??