Section 4.8: Newton’s Method

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Presentation transcript:

Section 4.8: Newton’s Method Practice HW from Stewart Textbook (not to hand in) p. 325 # 1, 5-15 odd, 23

Newton’s Method Recall: A root (zero) of a function is a value x = c where .

Example 1: Find the zeros of the function . Verify your answer is correct. Solution:

Fact: Graphically, the roots (zeros) give the x- intercepts of a function.

In this section, we need a method to approximate zeros, which are not easily found by algebraic methods.

Suppose we want to find a root x = c of the following function .

We make a guess which is “sufficiently” close to the solution. We use the point slope equation to find equation of the tangent line at the point .

Consider the point where the graph of the tangent line intercepts the x axis, which we label as . The idea is the value of is “closer” to the zero x = c than . At , y = 0 and we have the point . This gives the equation

We solve this equation for .

We next find the equation of the tangent line to the graph of at the point . This gives Suppose this tangent line intercepts the x axis at the point . Using a similar process described above, we find that is given by

The value is even closer to the zero of x = c than . Generalizing this idea gives us the following algorithm.

Newton’s Method (Newton Raphson Method) Given an initial value that is sufficiently “close” to a zero x = c of a function . Then the following iterative calculation can be used to successively better approximate the zero x = c.

Notes: 1. We usually generate iterations until two successive iterates agree to a specified number of decimal places. Newton’s method generally converges to a zero in a small number (< 10) iterations. 3. Newton’s method may fail in certain instances.

Examples of Failure for Newton’s Method 1. Iterate produces a tangent line slope of zero.

2. Initial guess not close enough

Example 2: Use Newton’s Method to approximate the root of to six decimal places. Solution:

Example 3: Use Newton’s Method to approximate the root of to eight decimal places. Solution: