Pair Production and photon-matter interactions

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Presentation transcript:

Pair Production and photon-matter interactions Contents: Photoelectric effect Compton scattering Absorption Pair production Whiteboards

Photoelectric effect Photon knocks electron from atom Photon disappears in the process

Compton Scattering Photon bounces off electron Electron absorbs some energy Photon has longer wavelength after collision

Absorption Photon hits electron in orbital Electron moves to excited state Photon disappears in the process Only for photons with the right energy

Help me! I’m going to be annihilated presently! Pair production Photon with sufficient energy passes near nucleus Energy of photon turns into matter Pair of matter/anti matter is created Nucleus must carry off some momentum Help me! I’m going to be annihilated presently! Positron m = 9.11 x 10-31 kg Charge = +e Electron m = 9.11 x 10-31 kg Charge = -e

Example 1: What energy photon (in MeV) is needed to create a electron-positron pair each with a kinetic energy of 0.34 MeV? What is the wavelength of that photon? Photon energy = energy to create matter + kinetic energy

Example 2: A 0. 00025 nm photon creates a electron positron pair Example 2: A 0.00025 nm photon creates a electron positron pair. What is the kinetic energy of each particle?

Whiteboards: Pair production 1 | 2 | 3

A photon creates a electron-positron pair each with a kinetic energy of 0.170 MeV. What is the energy of the photon? (in MeV) photon energy = energy to create mass + kinetic energy = .511 MeV + .511 MeV + .170 MeV + .170 MeV = 1.362 MeV 1.362 MeV

A 2134 MeV photon creates a proton, antiproton pair, each with how much kinetic energy? (2) Proton rest mass = 938 MeV photon energy = energy to create mass + kinetic energy 2134 MeV = 938 MeV + 938 MeV + kinetic energy kinetic energy = 258 MeV/(2 particles) = 129 MeV 129 MeV

A photon with a wavelength of 5 A photon with a wavelength of 5.27113x 10-13 m creates a electron-positron pair with how much kinetic energy each? (answer in keV) E = hf = hc/ E = hc/, = (6.626 x 10-34 Js)(3.00 x 108 m/s)/(5.27113x 10-13 m) = (3.77111x 10-13 J)/(1.602 x 10-19 J/eV) = 2354000 eV = 2354 keV photon energy = energy to create mass + kinetic energy 2354 keV= 511 keV + 511 keV + kinetic energy kinetic energy = 1332 keV/(2 particles) = 666 keV 666 keV

Solving pair production E = hf = hc/ E = mc2 E - Energy m - mass c = 3.00 x 108 m/s 1 eV = 1.602 x 10-19 J Example 1: What energy photon (in MeV) is needed to create a electron-positron pair each with a kinetic energy of 0.34 MeV? What is the wavelength of that photon? Photon energy = energy to create matter + kinetic energy

Solving pair production E = hf = hc/ E = mc2 E - Energy m - mass c = 3.00 x 108 m/s 1 eV = 1.602 x 10-19 J Example 3: A 0.00025 nm photon creates a electron positron pair. What is the kinetic energy of each particle?